Displaying 1 result from an estimated 1 matches for "estimate0".
Did you mean:
estimate
2007 Apr 24
1
inner loop problem!?
...name2[i] <-
colnames(GROUP[k])
sig[i] <-
round(calc$p.value,4)
estimate0[i] <-
round(calc$estimate[1],2)
estimate1[i] <-
round(calc$estimate[2],2)
}...