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Can someone, please, help explain to me why the following two calls return the same set: > seq(from=as.POSIXlt('2005-12-4'), to=as.POSIXlt('2006-4-2'), by='weeks') [1] "2005-12-04 EST" "2005-12-11 EST" "2005-12-18 EST" "2005-12-25 EST" [5] "2006-01-01 EST" "2006-01-08 EST" "2006-01-15 EST"

I have two collections of dates and I want to figure out what dates they have in common. This is not giving me what I want (I don't know what it is giving me). What is the best way to do this? Tom > data1 [1] "1948-02-24 EST" "1949-04-12 EST" "1950-05-29 EDT" "1951-05-21 EDT" [5] "1951-12-20 EST" "1953-01-22 EST"

Hello, I have data in the following form age sex Int.Prev.Est.1 Int.Prev.Est.2 Int.Prev.Est.3 Int.Prev.Est.4 Int.Prev.Est.5 93110 93 0 23.75482 57.86592 9.755003 4.343534 4.280714 93610 93 1 53.36475 39.47247 4.381618 1.622119 1.159044 94110 94 0 23.47514 58.23936 10.789339 3.690415 3.805741 94610 94 1

Sorry to bother you about a S-Plus related problem, but I hope someone can help. I have tried to "translate" some code from R to S-Plus (I have colleague that insists on using S-Plus. And yes, I have tried to make him change to R...) The following code works out fine in R, but in S-Plus (S-PLUS 6.2 for Windows Professional Ed.) I get the error message "Problem in est.theta(x):

Dear R-expert, How to swap and rearrange the row so that I will have Jan-Dec in order? > est31 ??????????? p0 est.alpha est.beta? est.rate Jan? 0.8802867 0.7321440 7.241757 0.1380880 Mar? 0.8598566 0.7096567 7.376367 0.1355681 May? 0.6204301 0.8657272 6.036106 0.1656697 July 0.5032258 0.9928488 4.027408 0.2482986 Aug? 0.5322581 0.9625738 4.103121 0.2437169 Oct? 0.6792115 0.8526226 5.105218

I'm installing R on an Irix 6.5 machine and R fails to understand dates prior to 1 Jan 1970. This first cropped up early in the test scripts (Examples/base-Ex.R): > > seq(as.Date("1910/1/1"), as.Date("1999/1/1"), "years") > Error in fromchar(x) : character string is not in a standard unambiguous format The root there is the

Good Afternoon, ?? I have a small problem with the following code. # The x.sub$Time[[1]] 2006-10-31 19:03:01 EST # when put in variable star give-me star<-x.sub$Time[[1]] print(star) print(x.sub$Time[[1]]) [1] 1 36 32 -........ do not understand why -- View this message in context: http://r.789695.n4.nabble.com/problem-with-data-tp4453510p4453510.html Sent from the R help mailing

Hi all, I post it on both r-help and r-finance since I don't know where is most appropriate for this topic. Sorry if it bothers you. I did garch fitting on S&P500 monthly returns with garchFit from fSeries. I got same coefficients from all cond.dist except normal. I thought that is probabaly usual for the data. But when I play with it, I got another question. I plot skew normal with

Hi all, I have a function rho.f which gives a list of estimators. I have the following problems. rho.f(0.3) gives me the right answer. However, if I use rho.f(corr[4]) give me a different answer, even though corr[4]==0.3. This prevents me from using a for loop. Can someone give me some help? Thank you very much in advance. Hannah >

Hi everyone, I am trying to build a table putting standard errors horizontally. I haven't been able to do it. library(memisc) berkeley <- aggregate(Table(Admit,Freq)~.,data=UCBAdmissions) berk0 <- glm(cbind(Admitted,Rejected)~1,data=berkeley,family="binomial") berk1 <- glm(cbind(Admitted,Rejected)~Gender,data=berkeley,family="binomial") berk2 <-

Hi, R guys: I'm using L-BFGS-B method of optim for minimization problem. My function called besselI function which need non-negative parameter and the besselI will overflow if the parameter is too large. So I set the constraint box which is reasonable for my problem. But the point outside the box was test, and I got error. My program and the error follows. This program depends on CircStats

Hi, I don't understand the following. When I create a small artificial set of date information in class POSIXct, I can calculate the mean and the median: a = as.POSIXct(Sys.time()) a = a + 60*0:10; a [1] "2009-03-10 11:30:16 EDT" "2009-03-10 11:31:16 EDT" "2009-03-10 11:32:16 EDT" [4] "2009-03-10 11:33:16 EDT" "2009-03-10 11:34:16

Can someone, please, explain the difference in as.POSIXct results before 1970 and on and after 1970 as illustrated below. After 1970, the use of 'EST' or "EST+5EDT' as the timezone does not affect the result of asPOSIXct, but before 1970 on 10/28 the results are different. > as.POSIXct('1970-10-29', tz='EST')+1 [1] "1970-10-29 00:00:01 EST" >

I have a list of numbers corresponding to timestamps, a sample of which follows: c(1327211358, 1327221999, 1327527296, 1327555433, 1327701042, 1327761389, 1327780993, 1327815670, 1327822964, 1327897497, 1327897527, 1327937072, 1327938300, 1327957589, 1328044466, 1328127921, 1328157588, 1328213951, 1328236836, 1328300276, 1328335936, 1328429102) I would like to group these into hours. In other

Hi R people: I'm trying to set the dimnames of a data frame called "ests" and am having trouble! First, I check to see if "ests" is a data.frame... > is.data.frame( ests ) [1] TRUE ... and it is a data frame! Next, I try to assign dimnames to that data frame.... > dimnames( ests )[[ 1 ]] <- as.character( ests$stfips ) Error in

I don't know R, so maybe I've done something wrong, but I'm working off an example I saw on the web and wondering why as.POXIXct isn't returning the same result on f$V1 as it is on z. Did I do something wrong? Or is it a problem with my build? > f$V1 [1] 09/11/2011 13:46:39 09/11/2011 13:45:18 09/11/2011 13:44:58 [4] 09/11/2011 13:40:02 09/11/2011 13:37:58 09/11/2011

I have a date/time imported from Excel in my dataframe oooi (with several hundred thousand rows), for example the input data near row 3100 is ActualOnLocal 11/12/2008 21:35 11/12/2008 22:03 11/12/2008 22:12 11/12/2008 22:38 11/12/2008 23:16 11/12/2008 23:23 11/13/2008 7:00 11/13/2008 7:03 11/13/2008 7:05 11/13/2008 7:11 I want to convert the column to POSIXct oooi$dpt <-

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What is 1. par.ests <- optimfit$par 2. fisher <- hessb(negloglik, par.ests, maxvalue=maxima); 3. varcov <- solve(fisher); 4. par.ses <- sqrt(diag(varcov)); Thanks a lot, fit.GEV <- function(maxima) { sigma0 <- sqrt((6. * var(maxima))/pi) mu0 <- mean(maxima) - 0.57722 * sigma0 xi0 <- 0.1 theta <- c(xi0, mu0, sigma0) #10/5/2007: removed assign() for maxima.nl

Full_Name: Mario Luoni Version: 2.10.0 OS: Windows XP HE SP3 Submission from: (NULL) (217.194.59.134) This piece of code: zzz1 <- as.POSIXct("1999-03-18", tz="CET") zzz2 <- as.POSIXlt("1999-03-18", tz="CET") zzz1 == zzz2 as.Date(zzz1) as.Date(zzz2) yields TRUE for "zzz1==zzz2", but the two dates returned by as.Date are different: >