search for: equiprob

Displaying 5 results from an estimated 5 matches for "equiprob".

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2008 Feb 12
2
re cognizing patterns
DeaRs, i'm looking for some references on a statement as follows: "Humans are good at spotting trends and patterns in data, but they are also good at spotting those patterns where none really exist". This is not verbatim but there must be some scholarly work on this. I can't remember where I came across it - perhaps I dreamed it up? Help, anyone? Best wishes Paul -- View this
2011 Nov 07
2
Dunif and Punif
Hi, I am trying to use dunif and runif however, I have two problems: if I do dunif(1:10, min=1, max=10) I get 10 values, which summed give me 1.1111 I understand that the probability is computed as f(x) = 1 / (max-min) but in this case it looks wrong: I have 10 values, each one equiprobable, and the probability for each one should be 0.1 and not 0.11111 (which is, consistently with the definition, 1/9) It looks like one of the extremes is not considered in the computation of the probability, but then it's assigned a probability anyway. Similar problem with punif. if I do pu...
2000 Dec 11
1
fixing shuffle in ogg123
Hi, There is a bug in the shuffle of ogg123 which was here at least until the CVS version of 3 days ago. Here's our fix: (it seems to be not perfectly equiprobable but at least fixes the old one which sometimes gives two times the same song and never the other song) -=-=-- --- vorbis-tools-1.0beta3/ogg123/ogg123.c.pix Sat Nov 4 01:23:21 2000 +++ vorbis-tools-1.0beta3/ogg123/ogg123.c Thu Dec 7 13:13:36 2000 @@ -324,12 +324,20 @@ if (param.shuffle)...
2008 Apr 29
7
How do you test for "consecutivity"?
I need to use R to model a large number of experiments (say, 1000). Each experiment involves the random selection of 5 numbers (without replacement) from a pool of numbers ranging between 1 and 30. What I need to know is what *proportion* of those experiments contains two or more numbers that are consecutive. So, for instance, an experiment that yielded the numbers 2, 28, 31, 4, 27 would be
2007 Oct 02
1
permutations of a binary matrix with fixed margins
J?r?me, As a first attempt, how about the function below. It works (or not) by randomly sorting the rows and columns, then searching the table for "squares" with the corners = matrix(c(1,0,0,1),ncol=2) and subtracting them from 1 to give matrix(c(0,1,1,0),ncol=2) (and vice versa). Randomized matrices can be produced as a chain where each permutation is seeded with the previous one.