Displaying 5 results from an estimated 5 matches for "equiprob".
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equipo
2008 Feb 12
2
re cognizing patterns
DeaRs,
i'm looking for some references on a statement as follows:
"Humans are good at spotting trends and patterns in data, but they are also
good at spotting those patterns where none really exist". This is not
verbatim but there must be some scholarly work on this. I can't remember
where I came across it - perhaps I dreamed it up? Help, anyone?
Best wishes
Paul
--
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2011 Nov 07
2
Dunif and Punif
Hi,
I am trying to use dunif and runif
however, I have two problems:
if I do
dunif(1:10, min=1, max=10)
I get 10 values, which summed give me 1.1111
I understand that the probability is computed as f(x) = 1 / (max-min)
but in this case it looks wrong: I have 10 values, each one
equiprobable, and the probability for each one should be 0.1 and not
0.11111 (which is, consistently with the definition, 1/9)
It looks like one of the extremes is not considered in the computation
of the probability, but then it's assigned a probability anyway.
Similar problem with punif.
if I do
pu...
2000 Dec 11
1
fixing shuffle in ogg123
Hi,
There is a bug in the shuffle of ogg123 which was here at least until the
CVS version of 3 days ago. Here's our fix: (it seems to be not perfectly
equiprobable but at least fixes the old one which sometimes gives two
times the same song and never the other song)
-=-=--
--- vorbis-tools-1.0beta3/ogg123/ogg123.c.pix Sat Nov 4 01:23:21 2000
+++ vorbis-tools-1.0beta3/ogg123/ogg123.c Thu Dec 7 13:13:36 2000
@@ -324,12 +324,20 @@
if (param.shuffle)...
2008 Apr 29
7
How do you test for "consecutivity"?
I need to use R to model a large number of experiments (say, 1000). Each
experiment involves the random selection of 5 numbers (without replacement)
from a pool of numbers ranging between 1 and 30.
What I need to know is what *proportion* of those experiments contains two
or more numbers that are consecutive. So, for instance, an experiment that
yielded the numbers 2, 28, 31, 4, 27 would be
2007 Oct 02
1
permutations of a binary matrix with fixed margins
J?r?me,
As a first attempt, how about the function below. It works (or not) by
randomly sorting the rows and columns, then searching the table for
"squares" with the corners = matrix(c(1,0,0,1),ncol=2) and subtracting them
from 1 to give matrix(c(0,1,1,0),ncol=2) (and vice versa). Randomized
matrices can be produced as a chain where each permutation is seeded with
the previous one.