search for: eqally

...uot;yellow", "green", "red" with equal probability. Of course these attributes can be transformed into integers (1,2,3) with a uniform distribution. So far I've tried to use the round function: y[,3] <- round(qunif(x[,3], 5, 10)) which does not sample the 1 and 10 eqally to 2:8 (this is discussed already somewhere else here on the list in another context, and the function sample() is suggested). How can this be applied here and how can a column of the lhs-output be transformed in e.g integers 1:10 or the three colors as mentioned above? thanks, Johannes [[alter...

Hi, I have a test_table where the dim is 62220 by 73 (row by col) I would like to partition the rows into 170 equal parts (170 tables where each is of dim 366 by 73), and rearrange them horizontally. The source codes I have: for (i in 1:170) { c = cbind(c,test_table[(367*i+1):(367*(i+1)),2:73]); } Unfortunately, using for loop and cbind for a table of this size

Hi @ all, I wamnt to combine two dataframes including a condition. I have two dataframes like the following: animal<-c("bear","bear","lion","monkey","fish","monkey","bear","zebra","zebra") val<-c(2,42,67,5,12,9,87,1,12)

> On Oct 13, 2017, at 2:51 AM, PIKAL Petr <petr.pikal at precheza.cz> wrote: > > Hi > > You expect us to solve your problem but you ignore advice already recieved. > > Your data are unreadable, use dput(yourdata) instead. see ?dput > >> test<-read.table("clipboard", heade=T) > Error in scan(file = file, what = what, sep = sep, quote = quote,

Please use a descriptive subject and not tag onto a prior thread for new topics. Assuming the first row is time 1 and the second row is time 2 and so on try: diff(log(P)) On 6/15/06, Wong, Kim <kwong at nymex.com> wrote: > > Hi, thank you all for the help. > > The split function works very well. > > I have an additional question. If I have a matrix of prices (row = 30,

Hemant's problem is that the indicators are not distributed uniformly. With a uniform distribution, categorization gives a reasonably optimal separation of cases. One approach would be to drop categorization and calculate the overall score as the mean of the standardized indicator scores. Whether this is an option I do not know. I did offer an "eyeball" set of breaks in a previous

hello, I'm confused what you guys are talking about. i just want to set ideal threshold values for my RFM scores which can be done using Quantiles but i don't want to use quantiles because my data is not normally distributed so it will lead to wrong ranges of breaks. to fix this problem I'm looking for an approach which can define the ideal range to breaks to categorize RFM scores into

I see the instructions about setting up a secondary domain controller at https://wiki.samba.org/index.php/Join_a_domain_as_a_DC but I am unclear on several points. I'm familiar with Kerberos/LDAP/DNS but not Windows administration. (1) This document talks about adding Samba as a slave to "an existing Active Directory domain" (presumably running Windows). Is it the same to

Hi You expect us to solve your problem but you ignore advice already recieved. Your data are unreadable, use dput(yourdata) instead. see ?dput > test<-read.table("clipboard", heade=T) Error in scan(file = file, what = what, sep = sep, quote = quote, dec = dec, : line 115 did not have 6 elements What is ?ideal interval? can you define it? Should it be such to provide eqal

Hey, i want to define 3 ideal breaks (bin) for each variable one of those variables is attached in the previous email, i don't want to consider quartile method because quartile is not working ideally for that data set because data distribution is non normal. so i want you to suggest another method so that i can define 3 breaks with the ideal interval for Recency, frequency and monetary to