search for: end2

Can you explain why you need them as 'integer', A floating point representation can hold a value upto ~4.5e15 as an "integer" keeping the precision that you might need. Jim Holtman Data Munger Guru What is the problem that you are trying to solve? Tell me what you want to do, not how you want to do it. On Tue, Apr 26, 2016 at 1:11 PM, Andr? Luis Neves <andrluis at

...11 13317 2.444859889 3.425644379 6ZBLK 4 1 Grain 4 End1 1.31E+11 1395 2.630183444 3.685312672 82ZBLK 4 1 Grain 4 End1 1.10E+12 5368 2.102445712 2.945866701 92ZBLK 4 1 Grain 4 End1 4.32E+11 14981 2.137551055 2.995054968 94BLK 4 1 Grain 4 End1 1.54E+11 1680 2.533433557 3.549750423 126BLK 1 2 Forage 1 End2 2.22E+11 13000 4.760093885 1.775579657 13ZBLK 1 2 Forage 1 End2 6.75E+11 18291 4.585536093 1.71046723 157BLK 1 2 Forage 1 End2 2.88E+11 8904 5.286298418 1.971861094 162ZRED 1 2 Forage 1 End2 1.85E+11 3124 4.501846838 1.679250002 17ZBLKY 1 2 Forage 1 End2 1.02E+11 4288 4.722218572 1.761451651 184ZBL...

Dear all: I converted the columns (Baci, Meti, Fungii, Protozoai) into integers (using excel) and then imported the data (.txt) into R. Interestingly, the other three variables were loaded as INT, but the 'Baci' one continued as Num. I imported the data using the following command line: X <- read.delim(file.choose(), header = TRUE, dec =

Dear all, I am a biologist. I have two sets of distance P(start1, end1) and Q(start2, end2). The distance will be like this. P ------------------------ Q ---------------------------------------- I want to know whether P falls closely to the right end or left end of Q. P and Q are of different lengths for each data point. There are more than 10000 pairs of P and Q. Is there an...

> Suppose you have four lifetime operations on the same address in memory, > with loads and stores all around them: > > start1--end1 .. start2--end2 > > If you remove start1 then you have a bare pointer, the memory came from > somewhere and you lose the optimization that loads before start1 become > undef, but you don't miscompile. This is assuming no looping after end1 or end2, right? > If you remove end1 then the code bet...

...y only invented them for a specific case, so I haven't thought through all the cases where it may or may not be legal to add or delete them. Here goes! Suppose you have four lifetime operations on the same address in memory, with loads and stores all around them: start1--end1 .. start2--end2 If you remove start1 then you have a bare pointer, the memory came from somewhere and you lose the optimization that loads before start1 become undef, but you don't miscompile. If you remove end1 then the code between start1 and start2 is in trouble. We would miscompile start1+store+load+s...

...------------------------------ When data imported from Excel 2007 into R (2.13) all time variables, depending on date (summer or winter) get (un-asked for it!) a time zone addition CEST (for summer dates) or CET (for winter dates). > Dataset Start End1 End2 days2End1.from.Excel days2End2.from.Excel days2End1.in.R days2End2.in.R 1 2010-01-01 2011-01-01 2012-01-01 365 730 365 days 730.0000 days 2 2010-02-01 2011-02-01 2012-01-01 365...

On 12/28/2012 04:20 AM, Rafael Espíndola wrote: >> Suppose you have four lifetime operations on the same address in memory, >> with loads and stores all around them: >> >> start1--end1 .. start2--end2 >> >> If you remove start1 then you have a bare pointer, the memory came from >> somewhere and you lose the optimization that loads before start1 become >> undef, but you don't miscompile. > > This is assuming no looping after end1 or end2, right? Right. There'...

...ble at that level. Thanks, Diego ---- .outer: ; preds = %2, %0 ... %.ph2 = phi i32 [ 62, %2 ], [ 110, %0 ] %5 = add i32 %.ph2, 1 ... vector.ph: ; preds = %.outer ... %ind.end = add i32 %5, %n.vec %ind.end2 = add i32 %.ph2, %n.vec ... middle.block: ; preds = %vector.body.latch ... scalar.ph: ; preds = %middle.block, %.outer %bc.resume.val = phi i32 [ %ind.end, %middle.block ], [ %5, %.outer ] %bc.resume.val1 = phi i32...

>> Oh, I was reading "precedes/following" as having static (dominance) >> meaning. That is, in the above example you could not delete the store >> since it is not true that >> llvm.lifetime.end dominates it. >> >> Nick, is this what you had in mind? If not, then we must delete a >> matching llvm.lifetime.end, but it is not clear how we define

...---------------------------------- When data imported from Excel 2007 into R (2.13) all time variables, depending on date (summer or winter) get (un-asked for it!) a time zone addition CEST (for summer dates) or CET (for winter dates). > Dataset Start End1 End2 days2End1.from.Excel days2End2.from.Excel days2End1.in.R days2End2.in.R 1 2010-01-01 2011-01-01 2012-01-01 365 730 365 days 730.0000 days 2 2010-02-01 2011-02-01 2012-01-01 365...

...; preds = %2, %0 > > … > > %.ph2 = phi i32 [ 62, %2 ], [ 110, %0 ] > > %5 = add i32 %.ph2, 1 > > … > > > > vector.ph: ; preds = %.outer > > … > > %ind.end = add i32 %5, %n.vec > > %ind.end2 = add i32 %.ph2, %n.vec > > … > > > > middle.block: ; preds = > %vector.body.latch > > … > > > > scalar.ph: ; preds = %middle.block, > %.outer > > %bc.resume.val = phi i3...

...DIALSTATUS-${DIALSTATUS}*****) same => n,hangup exten => h,1,NoOP(Call hangup === outgoing context) same => n,NoOP(calldate2=${CDR(calldate)},src2=${CDR(src)},dst2=${CDR(dst)}) same => n,NoOP(channel2=${CDR(channel)},dstchannel2=${CDR(dstchannel)}start2=${CDR(start)}) same => n,NoOP(end2=${CDR(end)},duration2=${CDR(duration)},billsec=${CDR(billsec)},disposition2=${CDR(disposition)}) [outgoing_ivrs] exten => s,1,Noop(----- Second LEG CALL from call file for outgoing_ivrs: Channel-${CHANNEL} -----) same => n,Playback(welcome) *same => n,Dial(DAHDI/g0/88XXXXXXXX,30,M(outgoin...

...141,6 +141,9 @@ struct aperture_range { static LIST_HEAD(apertures); static DEFINE_MUTEX(apertures_lock); +static resource_size_t firm_fb_start; +static resource_size_t firm_fb_end; + static bool overlap(resource_size_t base1, resource_size_t end1, resource_size_t base2, resource_size_t end2) { @@ -170,6 +173,9 @@ static int devm_aperture_acquire(struct device *dev, mutex_lock(&apertures_lock); + firm_fb_start = base; + firm_fb_end = end; + list_for_each(pos, &apertures) { ap = container_of(pos, struct aperture_range, lh); if (overlap(base, end, ap->base, ap-&...

...sete %dl xorl %ecx, %ecx .p2align 4, 0x90 .LBB1_1: # %do.body.us.i # =>This Inner Loop Header: Depth=1 testb $1, %dl je .LBB1_3 # BB#2: # %if.end2.us.i # in Loop: Header=BB1_1 Depth=1 movq b(%rip), %rdx movq $3, i_hasval(%rip) incq %rcx xorl %edx, %edx cmpq %rax, %rcx jl .LBB1_1 .LBB1_3: # %foo.exit...

From: Sui Jingfeng <suijingfeng at loongson.cn> Currently, the default VGA device selection is not perfect. Potential problems are: 1) This function is a no-op on non-x86 architectures. 2) It does not take the PCI Bar may get relocated into consideration. 3) It is not effective for the PCI device without a dedicated VRAM Bar. 4) It is device-agnostic, thus it has to waste the effort to