search for: emagent

Displaying 20 results from an estimated 194 matches for "emagent".

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2008 Nov 18
0
Emagic Logic Platinum - Wine?
Dear everybody, Has anyone looked into Emagic Logic 5 running on WINE? I have searched a little, and I have not found anything to date. The software was made by a German company called Emagic until 2003 when Apple (3vil) bought them, ditched Windows, and made it available for the Mac. I have the Windows XP version. Any links available for people who have managed this feat? Regards, Ian.
2009 Mar 25
2
"[.data.frame" and lapply
Dear all, Trying to extract a few rows for each element of a list of data.frames, I'm puzzled by the following behaviour, > d <- lapply(1:4, function(i) data.frame(x=rnorm(5), y=rnorm(5))) > str(d) > > lapply(d, "[", i= c(1)) # fine, this extracts the first columns > lapply(d, "[", j= c(1, 3)) # doesn't do nothing ?! > > library(plyr)
2009 Mar 25
2
"[.data.frame" and lapply
Dear all, Trying to extract a few rows for each element of a list of data.frames, I'm puzzled by the following behaviour, > d <- lapply(1:4, function(i) data.frame(x=rnorm(5), y=rnorm(5))) > str(d) > > lapply(d, "[", i= c(1)) # fine, this extracts the first columns > lapply(d, "[", j= c(1, 3)) # doesn't do nothing ?! > > library(plyr)
2008 Nov 09
1
[Rd] Re Bessel functions of complex argument
Dear all, I'm writing a code that requires Bessel functions with complex argument. Searching the list, I found the continuation of a thread I initiated a few months ago: http://tolstoy.newcastle.edu.au/R/e4/devel/08/03/0746.html As I understand, the most promising option would be to use the fortran or C implementation of Amos,
2008 Apr 03
1
data.frame or list
Dear R list, I'm having difficulties in choosing between a list or a data.frame, or an array for the storage and manipulation of my data (example follows). I've been using the three for different purposes but I would rather like to know which is more adapted to what task. Here is the data I'm currently working on: 200 observations, each observation being a vector of length
2008 Feb 03
1
distances between points in R^3
Dear R helpers, I'm trying to write a numerical scheme for a boundary integral method to solve an electromagnetic problem. This requires the computation of the distance between points at the surface of an object (a sphere, in my example). Here is my code, > require(rgl) > r<-1 > size<-10 > theta<-seq(0,2*pi,length=size*2) > phi<-seq(0,pi,length=size) > pc
2008 Jun 18
2
highest eigenvalues of a matrix
DeaR list, I happily use eigen() to compute the eigenvalues and eigenvectors of a fairly large matrix (200x200, say), but it seems over-killed as its rank is limited to typically 2 or 3. I sort of remember being taught that numerical techniques can find iteratively decreasing eigenvalues and corresponding orthogonal eigenvectors, which would provide a nice alternative (once I have the
2011 Jul 12
1
Can zpool permanent errors fixed by scrub?
...agent10g/perl/lib/5.8.3/sun4-solaris-thread-multi/auto/Socket/Socket.so /zones/cctsprod/root/ccts/grid_agent/app/agent10g/lib32/libnmefsql.so /zones/cctsprod/root/ccts/grid_agent/app/agent10g/network/log/sqlnet.log /zones/cctsprod/root/ccts/grid_agent/app/agent10g/sysman/log/emagent.trc /zones/cctsprod/root/ccts/grid_agent/app/agent10g/sysman/log/emdctl.trc /zones/cctsprod/root/ccts/grid_agent/app/agent10g/sysman/log/emagent.nohup /zones/cctsprod/root/ccts/oracle/app/product/10.2.0/lib/libons.so /zones/cctsprod/root/ccts/oracle/app/product/10.2....
2009 Jun 25
3
grid.polygon() + color gradient
Hi, I wonder whether there is a way to generate a polygon (a triangle in my case) with color gradient using grid.polygon() in package grid? I tried something like library(grid) grid.polygon(x=c(0, 0.5, 1), y=c(0.5, 1, 0.5), gp=gpar(col=NA, fill=colorRampPalette(c("green", "lightgray"), space="Lab")(200))) But am only
2009 Apr 14
2
subset dataframe by rows using character vector?
Dear List, I'm stuck on what seems like a simple indexing problem, I'd be very grateful to anyone willing to help me out. I queried a dataframe which returns a character vector called "plot". I have another dataframe from which I want to subset or select only those rows that match "plot". I've tried subset, and also the "which" command. plot
2008 Feb 18
2
question on function arguments
Hi, I have two small issues with my R code, no big deal but curiosity really. Here is a sample code, > > x <- rnorm(1:10) > > foo <- function(a = 1, b = list(x = c(1:10), y = c(1:10))){ > > for (ii in seq(along=b$y)){ > > print(x[ii] + b$x[ii]) > } > > > } > > foo() # default OK > > foo(b=list(x=1, y=c(1:10))) # only the first
2009 Apr 16
3
segment between points on different plots
Hi, I need to draw a line segment between two points on different plots in the same multigraph.I've tried looking at the zoominplot function in plotrix but havent understood much.any help is appreciated ~Aks [[alternative HTML version deleted]]
2009 Mar 09
3
How to write a function that accepts unlimited number of input arguments?
Dear R-helpers: I am an R newbie and have a question related to writing functions that accept unlimited number of input arguments. (I tried to peek into functions such as paste and cbind, but failed, I cannot see their codes..) Can someone kindly show me through a summation example? Say, we have input scalar, 1 2 3 4 5 then the ideal function, say sum.test, can do
2008 Apr 12
1
lm() of one matrix against another
Hello R list, I have two matrices of identical dimensions, and I want to fit a straight line for each pair of columns and plot the resulting lines. I got it to work with a for loop, but there must be a better way, > n<-5 > N<-10 > > data.x<-matrix(1:(n*N),ncol=n) > data.y<-matrix(1:(n*N) + rnorm(n*N,sd=1),ncol=n) > >
2008 Jul 03
1
ggplot2 legend for vertical lines
Dear all, The following example code produces a graph with ggplot2, to which I add several vertical lines of arbitrary colors. I am not satisfied with the legend: it automatically adds some vertical lines which I'd rather not see (they confuse the reader rather than add information in this case). > library(ggplot2) > dfr <- data.frame(values = sin(1:50/10), > fact =
2005 Mar 18
1
[happy wine] ableton live 4.1 is working
Hi all, I just want to give you feedback with my test on ableton live application. A long ago time I was trying to run audio applications with wine. Since I completely switched on linux (3 years now) I also completely stop my music creation. Of course there are goods music softwares on linux, but I was a junky with software like Emagic Logic audio and Ableton Live. And now I'm a junky on
2009 May 21
1
size of point symbols
Dear list, This might be a topic for r-devel but i may be missing something obvious. I don't understand the rationale in the absolute sizes of the point symbols, and I couldn't find it documented. The example below uses Grid to check the size of the symbols against a square of 10mm x 10mm. > checkOneSymbol <- function(pch=0){ > gTree(children=gList( >
2009 May 21
1
size of point symbols
Dear list, This might be a topic for r-devel but i may be missing something obvious. I don't understand the rationale in the absolute sizes of the point symbols, and I couldn't find it documented. The example below uses Grid to check the size of the symbols against a square of 10mm x 10mm. > checkOneSymbol <- function(pch=0){ > gTree(children=gList( >
2008 Feb 14
1
write output in a custom format
Hi, I need to create a text file in the following format, > 1 100.0 0 > 0 0 > 1 1 > 0 0 > 1 1 > # > 1 100.0 0 > 0 0 > 0 1 > 1 0 > 1 1 ... where # is part of the format and not a R comment. Each block (delimited by #) consists of a first line with three values, call it dose, and a list of (x,y) coordinates which are a matrix or data.frame, >
2008 Aug 09
2
levels values of cut()
Dear list, I have the following example, from which I am hoping to retrieve numeric values of the factor levels (that is, without the brackets): > > x <- seq(1, 15, length=100) > y <- sin(x) > > my.cuts <- cut(which(abs(y) < 1e-1), 3) > levels(my.cuts) hist() does not suit me for this, as it does not necessarily respect the number of breaks. getAnywhere