search for: eliza

People, I sent this note to JF at Recoll and he suggested asking here (his response below) - any suggestions? Thanks, Phil. -------- Original Message -------- Subject: Re: Another ue for Recoll? - AI/Eliza Date: 2012-12-23 19:22 From: jf at dockes.org To: <phil at pricom.com.au> Philip Rhoades writes: > Jean, > > I have been using Recoll happily for some time now but I also have a > need for an AI/Eliza-like facility and I thought Recoll's fast text > searching ma...

dear useRs, i created a distance matrix, of certain voltage values. unfortunately, i lost the original values. i am only left with the distance matrix that i created from those values. i wanted to ask that is there a way in R to reverse distance matrix for the original values? thanks in advance eliza [[alternative HTML version deleted]]

..., from column number 1, i will first subtract itself(column 1) and then the remaining 37 columns. Afterwards i will take column number 2 and do the same. In this way i want to proceed till 38th column. 2. i want to print the resulting matrix on A4 paper. Bundle of thanks in advance. best regards eliza [[alternative HTML version deleted]]

...ll 37th column. i have tried following loop command which is not working.can anyone plz see whats wrong in that? >for (i in 1:37) >{ >a<-e[,e[i]:444] >} > lapply(seq_len(1), function(i) { >a[,c(TRUE, rep(FALSE,1))] >}) extremly sorry for bothering you once again.. eliza [[alternative HTML version deleted]]

...nction(x) {if(is.data.frame(x[,-1])) rowMeans(x[,-1]) else mean(x[,-1])}) >lapply(seq_along(res), fun) >fun <- function(i){ >matplot(res[[i]][,-1], type="l",col="grey") >lines(b[[i]], lwd = 2, col = "black") >}} >dev.off() >} thanks in advance eliza [[alternative HTML version deleted]]

...6.7063592 18.745256 13.278218 afterwards when i applied the "colMeans" command i was not able to calculate the mean as i got the following error >'x' must be an array of at least two dimensions i cant spot the mistake in the last 5 hours. you help is neededthanks in advance eliza -------------- next part -------------- An embedded and charset-unspecified text was scrubbed... Name: eliza.txt URL: <https://stat.ethz.ch/pipermail/r-help/attachments/20121224/322d49da/attachment-0002.txt>

...r useRs, 1. how to calculate single median value for two columns of a matrix? 2. i have a matrix of 16 columns and 365 rows, how to calculate median between columns 1 and 16, 2 and 16, 3 and 16, 4 and 16, 5 and 16 till 15th column. is there a loop command to do the said operation? regards eliza [[alternative HTML version deleted]]

...s -------80<x<100 and 2<y<4 -------40<x<60 and 8<y<10 -------100<x<120 and 6<y<8 Then, i also want to draw square around those dots falling in these ranges and finally naming the areas with alphabets A, B and C. Is there a way of doing it? Thanks in advance Eliza [[alternative HTML version deleted]]

...on...for that i created the followng loop. >e<-lapply(seq(1),function(i) rbind(r[[i]][1:31,],(r[[i]][32:nrow(r[[i]]),][-seq(i,nrow(r[[i]]),32),]))) but this loop executes the desired operation on the list at the top and doesnt do anything to the remaining 16 lists. any help?thanks in advance eliza [[alternative HTML version deleted]]

...udes column 1 too and then subtracting these values from the column i left out i.e. col=2.and then continuing this process the last column. i know a kind of "manual way" of doing things but its extremely long and laborious.Is there any loop command or shorter way?? thanks in advanceregardseliza [[alternative HTML version deleted]]

...s in such a way that i should have euclidean distance of matrix B against all the columns of matrix A. More precisely, first i want euclidean dist. of column 1 of A against B, then column 2 against B, 3rd column of A against B and so on.is there a way in r to do it?your help is deeply appreciated.. eliza [[alternative HTML version deleted]]

...30<x<=355??? 0 #8? 35<x<=405??? 0 #9? 40<x<=455??? 0 #10 45<x<=505??? 0 hist(vec1,breaks=c(0,55,100,145,190,235,280,325,370,415,460)) ?hist(vec1,breaks=c(0,55,100,145,190,235,280,325,370,415,460),prob=TRUE) ?lines(density(vec1)) A.K. ________________________________ From: eliza botto <eliza_botto at hotmail.com> To: "smartpink111 at yahoo.com" <smartpink111 at yahoo.com> Sent: Sunday, February 17, 2013 2:35 PM Subject: histogram Dear Arun, [text file is attached in case format of email is changed] For the following data set 33 18 13 47 30 10 ?6 2...

...by "e". Although the output was shown inside the loop but when i tried to call the variable outside the loop it only gave the first row, where as it should have 35 rows as it showed inside loop.The command which i used in the loop is e<-print(sum(abs(b-m[,i]))) Kindly help me on it.. Eliza [[alternative HTML version deleted]]

Dear useRs, Is there a way to draw helix spring in R of desired diameter and number of turns? regards, Eliza [[alternative HTML version deleted]]

Dear Eliza, Try this: Lines1<-readLines(textConnection("1911.01.01?????? 7.87 1911.01.02?????? 9.26 1911.01.03?????? 8.06 1911.01.04?????? 8.13 1911.01.05????? 12.90 1911.02.06?????? 5.45 1911.02.07?????? 3.26 1911.03.08?????? 5.70 1911.03.09?????? 9.24 1911.04.10?????? 7.60 1911.05.11?????...

Thank you very much peter. It worked out nicely. I have additional question. How can I get Y-axis on log-scale? Thank you very much in Advance, Eliza UoS PP ________________________________ From: PIKAL Petr <petr.pikal at precheza.cz> Sent: 23 November 2017 16:22:39 To: Eliza Botto; r-help at r-project.org Subject: RE: adding percentage secondary y-axis Hi It is usually not recommended but if you insist maybe library(plotrix) ?twoord...

...rting from 1. more precisely i want to select columns 1, 38,75, 112 and so on. then doing the same by starting from column number 2(2,39,76,113.......). i know that there is a manual way of doing it but i wanted to make it more quickly as i have fairly large data to dealth with. thanks in advance eliza [[alternative HTML version deleted]]

...r [1:29585] "-9999.000" "-9999.000" "-9999.000" "-9999.000" ... Regarding the space between date1 and discharge, I haven't checked it as you didn't mention whether it is needed in data.frame or not. A.K. ________________________________ From: eliza botto <eliza_botto at hotmail.com> To: "smartpink111 at yahoo.com" <smartpink111 at yahoo.com> Sent: Tuesday, February 19, 2013 10:01 AM Subject: RE: THANKS ARUN.. ITS A CHARACTER.... SORRY FOR NOT TELLING YOU IN ADVANCE ELISA > Date: Tue, 19 Feb 2013 07:00:03 -0800...

HI Eliza, You could do this: set.seed(15) mat1<-matrix(sample(1:800,124*12,replace=TRUE),nrow=12) # smaller dataset #Your codes ?list1<-list() ?for(i in 1:ncol(mat1)){ ? list1[[i]]<-t(apply(mat1,1,function(x) x[i]-x)) ? list1} ?x<-list1?? x<-matrix(unlist(x),nrow=12) x<-abs(x) ?y<-col...

...curves) should appear on the same axis at the same time. i used >par(new=TRUE) But it has 2 limitations 1- it completly distorted y-axis values 2- it was not very efficient as average curve in no overlapped the original curves. can any1 advise me what to do? thanks in advance for you time. eliza botto [[alternative HTML version deleted]]