search for: elemnts

Hi, well, how do i replace an element with rubyful_soup ?? I tried soup = BeautifulSoup.new(input) elemnt = soup.find(''quote'') elemnt = tag(''<div></div>'') elemnt = ''<div></div>'' elemnt.replaceWith(''<div></div>'') elemnt = BeautifulSoup.new(''<div></div>'') elemnt

Dear all, I have a data frame that is created like that data.frame(x=CRX[-1],y=CRY[-1],z=CRagent[[1]]$sr) the output looks like 45 116 162 -30.89105988567164 46 128  79 -42.66296679571184 47 180 195 -30.45626175641315 48 114  83 -45.26843476475688 49 118  73 -46.85389245327003 How can I select only the rows that their third column is higher that -45? This will return the following 116 162

Dear R forum I have a vector say as given below df = c("F", "C", "F", "B", "D", "A", "D", "D", "A", "F", "D", "F", "B",    "C") I need to find (1) how many times each element occurs? e.g. in above vector F occurs 4 times, C occurs 2 times etc. (2)

Dear all, Is there a way to compute and list all combinations with replication of two elements in sets of 8 elemnts? For example, I've two elements, 0 and 1, and I would to get all possible combinations with replication such as, for example, 00000000, 00000001, 00000010, and so on. They are 2^8 and it's very hard to list handly!! Thank you Marina -- View this message in context: http://www.nabble.com/co...

Add oVirt specific elemnt to OVF. It represents the combination of machine type (i440fx/q35) and firmware (BIOS/UEFI). Signed-off-by: Tomáš Golembiovský <tgolembi@redhat.com> --- v2v/create_ovf.ml | 20 +++++++++++++++++++- v2v/create_ovf.mli | 2 +- v2v/output_rhv.ml | 6 ++---- v2v/output_rhv_upload.ml

Hi, I understand the idea behind compare_numeric() is to compare strings containing digits in a special way: Do a normal string-compare up to the point where both string elemnts are numerical. Find then an outcome based on the number of consecutive digits in the strings while disregarding the value of the digits, eg a12b < a123. I guess then this order should hold: a12 == a22 < a1b, for these strings. Looking at StringRef::compare_numeric(StringRef RHS), the proble...

...weight = c(12.3, 6.8, 10.5, NA, "5.5")) myDF$type # ... is a vector of factors for(type in myDF$type) { print(type) } # or (less explicit in the code and will break if the order of columns # ever changes): for(type in myDF[ , 1]) { print(type) } # In a matrix, all elemnts have to be of the same type. Let's make a # matrix of characters: myMat <- matrix(cbind(as.character(myDF$type), c("red", "green", "red", "red", "green")), ncol = 2) for(type in myMat[ , 1]) { print(...

...> > myDF$type # ... is a vector of factors > > for(type in myDF$type) { > print(type) > } > > # or (less explicit in the code and will break if the order of columns > # ever changes): > for(type in myDF[ , 1]) { > print(type) > } > > # In a matrix, all elemnts have to be of the same type. Let's make a > # matrix of characters: > > myMat <- matrix(cbind(as.character(myDF$type), > c("red", "green", "red", "red", "green")), > ncol = 2) > > for...

On Thursday, 19 July 2018 15:51:04 CEST Tomáš Golembiovský wrote: > Add oVirt specific elemnt to OVF. It represents the combination of > machine type (i440fx/q35) and firmware (BIOS/UEFI). Other than adding a new element in the OVF, this also enables the conversion of UEFI guests to oVirt. It is tested? Does it require other changes? I'd split the addition of <BiosType> to the

Hello!! I would like create a window that has diferent element as: http://bioinf.wehi.edu.au/~wettenhall/RTclTkExamples/checkboxes.html http://bioinf.wehi.edu.au/~wettenhall/RTclTkExamples/radiobuttons.html I know as make it, but I don?t know as I could (align the diferent elemnts to left, right, top, bottom) or (put in a coordinates into windows). If anybody know as I could make it, I would like you say me. Thank you very much, Luismi A greetings -- View this message in context: http://www.nabble.com/Aling-elmentos-into-Windows-with-TK-tp17103275p17103275.html Sent from...

On Sep 30, 2011, at 8:29 AM, Jonas Paulsson wrote: > The conclusion is that the StringRef::compare_numeric() is not deterministic Thanks for tracking this down. I believe we have a bug in compare_numeric() causing it to be non-transitive sometimes. It is supposed to provide a total ordering of strings. Can you find the bug? /jakob -------------- next part -------------- An HTML attachment

I'm trying to troubleshoot a game crash under Wine. Here's a snippet from the log file created under Wine 1.3.20: Code: wine: Unhandled page fault on read access to 0x00000000 at address 0x44a179 (thread 0022), starting debugger... Unhandled exception: page fault on read access to 0x00000000 in 32-bit code (0x0044a179). Register dump: CS:0023 SS:002b DS:002b ES:002b FS:0063 GS:006b

Hi, I just bumped into a bug in this code. The problem was as follows: I have defined a set of registers with rather similar names including digits. The code section at RegisterInfoEmitter::run(){ ... // Process sub-register sets. runs and fills the RegisterAliases map. then, ... for (unsigned i = 0, e = Regs.size(); i != e; ++i) { RegNo[Regs[i].TheDef] = i; NumAliases +=

Hello, If you want to loop through the columns of a data.frame you can do for(i in names(df)){ [code] } Another way would be lapply(names(df), function(somecol) class(df[[somecol]])) where class(df[[somecol]]) is just an example, you would use whatever fits your needs. When you say that the column in question holds "levels" do you mean it's a factor? (factors are R's

Hi I am new on this forum. I am searching for a function in R which provides all partitions of a set, say for the set {1,2,3} you get {{1,2,3}} {1,{2,3}} {2,{1,3}} {3,{1,2}} {{1},{2},{3}} . The number of partitions of a set is given by Bellsche`s number. The number of possibilities of length (this is the number of subsets included in the partition) of the partition is given by the partition

Hi List! I''m reading the Agile book, as many online articles as I can, but there''s still some things that are just too hard to answer for yourself. In building my application, I often find myself putting code into my views of which I am not quite certain it belongs there. Where do you usually draw the line? Is it okay to, say, loop through an array of hashes that represents

changes in v2: - split patch in two - changed as per suggestions Tomáš Golembiovský (2): v2v: ovf: add firmware and machine type element v2v: enable UEFI for oVirt/RHV outputs v2v/create_ovf.ml | 12 +++++++++++- v2v/create_ovf.mli | 2 +- v2v/output_rhv.ml | 6 ++---- v2v/output_rhv_upload.ml | 4 ++--

Dear R helpers I have following data stocks <- c("ABC", "DEF", "GHI", "JKL") prices_df <- data.frame(ABC = c(17,24,15,22,16,22,17,22,15,19),                                          DEF = c(22,28,20,20,28,26,29,18,24,21),                                           GHI = c(32,27,32,36,37,37,34,23,25,32),                                          

When I just run a for loop it works. But if I am going to run a for loop every time for large vectors I might as well use C or any other language. The reason R is powerful is becasue it can handle large vectors without each element being manipulated? Please let me know where I am wrong. for(i in 1:length(news1o)){ + if(news1o[i]>s2o[i]) + s[i]<-1 + else + s[i]<--1 + } --

It?s sometimes faster to ask from someone who has already learnt the syntax. In this case one has to do e.g. names(data$somecol) To get the collection and then iteration through it is almost like in Python: for(i in names(data$somecol)) { # do something } > Bert Gunter <bgunter.4567 at gmail.com> kirjoitti 6.11.2017 kello 19.55: > > Time to go through a tutorial or two! --