search for: elegantly

Hi, I am looking for an elegant way to transform a vector into percentages of values that meet certain criteria. store<-c(1,1.4,3,1.1,0.3,0.6,4,5) # now I want to get the precentages of values # that fall into the categories <=M , >M & <=N , >N # let M <-.8 N <- 1.2 # In my real example I have many more of these cutoff-points # What I did is: out <- matrix(NA,1,3)

How to do this in an elegant way formatrix/data frame/zoo? mat= 1 2 3 4 5 6 7 8 9 vector= 1 2 3 result= 0 1 2 2 3 4 4 5 6 ie 1-1 2-1 3-1 4-2 5-2 6-2 7-3 8-3 9-3 Thanks in advance. _________________________________________________________________ 08 [[alternative HTML version deleted]]

Hi, I have a factor and I would like to find the most frequent level. I think my current approach is a bit long winded and I was wondering if there was a more elegant way to do it: x <- factor(sample(1:0, 5,replace=TRUE)) levels(x)[ which( as.logical((table(x) == max(table(x)))) == TRUE ) ] (The length of x will always be an odd number, so I wont get a tie in max()) Thanks,

Hello, I am importing some raw voltage multichannel measurements into an R data frame. I need to scale each column with the respective sensitivity for that channel. I figured how to do it, but I am curious if there isn't a more elegant way. Now I start with something like this: rawdata <- data.frame(rbind(c(1,2,3), c(4,5,6))) sens <- c(2,4,6) and I do this: data <-

What is the most elegant way to save new one-many associations? order = Order.new(:name => "My Order") order.line_items << LineItem.new(:product_id => 1, :quantity => 2) order.line_items << LineItem.new(:product_id => 2, :quantity => 5) order.save The above - which is by far the most elegant way of putting it - doesn''t work for me - the line_items

Hello everybody. I am trying to reproduce a particular matrix in an elegant way. If I have jj1 <- structure(c(1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,2, 3,1,2,3,1,2,3,1,2,3,2,3,1,2,3,1,2,3,1,2,3, 1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,3,1,2,3,1, 2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1, 2),.Dim = as.integer(c(9,9))) [ image(jj1) is good here ] then I can get this with

Hi, Can anyone help to write a more elegant version of my code? I am sure this can be put into a loop but I am having trouble creating the objects b1,b2,b3,...,etc. b1 <- rigamma(50,1,1) theta1 <- rgamma(50,0.5,(1/b1)) sim1 <- rpois(50,theta1) b2 <- rigamma(50,1,1) theta2 <- rgamma(50,0.5,(1/b2)) sim2 <- rpois(50,theta2) b3 <- rigamma(50,1,1) theta3 <-

I''m using Prototype.js with Control.modal to create a modal window on my IPB Forum which takes all the various topic posting/replying/ editing options and places them into a Modal window. The inherent nature of this action is to take the contents of whatever DIV I told Control.Modal to make a modal window out of and place the entire innerHTML of that DIV into a separate DIV outside the

Dear all: Plan 1: I want to do serval t-test means for different variables in a loop , so I want to add all results to an object then dump() them to an text. But I don't know how to append T-test result to the object? I have already plot the barplot and I want to know an elegant way to report raw result. Can anybody give me some pieces of advice? Yao He ????????????????????????? Master

-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 Hi I have to replace the last element of a vector with 0, but the length of x is not known at coding time. So I do the following: x <- 1:10 x x[length(x)] <- 0 x it is working nicely, but I am wondering: is there a more elegant solution( like tail(x, 1) <- 0 , which does not work)? Thanks, Rainer - -- Rainer M. Krug, PhD (Conservation

I have a r-script (rook.R) that starts a Rook server. To present users from having to start R and type in source("rook.R"), I want to create a bash script and bat file that starts R and sources the script. However, to keep the Rook server running R should not close after running the script and stay in interactive mode. This proves more difficult than expected. I tried various

Hello, I have a dataframe with columns like: parameter1 parameter2 metricname value and I'd like to transform it into a dataframe with columns: parameter1 parameter2 metric1 metric2 metric3 where the values for each metric would be in the appropriate column. There are often multiple values for a given (parameter1, parameter2, metricname) triple. In this case, I want to use the

Hi, x <- 0.2*5 is.integer(x) gives me FALSE because R stores it as a float number, right? Is there an elegant way to work around that problem? Right now I'm using x <- 0.2*5 round(x) == x which returns TRUE. But more strictly I should use all.equal(), right? I somehow just don't like the--pardon--ugliness of those pieces of code. Maybe there is a beautiful

Hi, I'me trying to write a function that will shuffle a vector. At the moment I'm baically making a vector of randomized indices and then making a new vector from the original one using these random indices. However, is there an alternative (more elegant) method to do this? I tried help.search('shuffle') but it does'nt return anything relevant. Thanks,

hi, I have a single stream going to my icecast server, encoded in hi-quality ogg. goal is to serve hi- and low quality ogg and mp3 streams, re-encoded from the single hi-quality ogg stream. encoding all from e.g. oddcast simultaniously is not an option. it would be easier if source-streams would be static and always named the same .. unfortunately they are not. if so, I could define simple

When a user creates a post I also want to save all the tags associated with it. I do that in the post_controller like this presently: def save @post = Post.new(@params[:post]) @tags = Tag.new(@params[:tags]) @post.user_id = session[:id] if @post.save @tags.title.split('','').each do |tag| present_tag = Tag.find_by_title(tag.strip) present_tag =

Is this book worth its dollar? If so, why?, if not, why not? Cheers. -- View this message in context: http://n4.nabble.com/Ggplot2-Elegant-Graphics-for-Data-Analysis-Use-R-2009-Paperback-tp931702p931702.html Sent from the R help mailing list archive at Nabble.com.

Hello, Using seq, I would like to specify a minumum end value, rather than a maximum end value. For example, rather than > seq(from=0, to=10, by=4) [1] 0 4 8 I would like to obtain [1] 0 4 8 12 I can do that with > by.value = 4 > seq(from=0,by=by.value,to=ceiling(10 / by.value)*by.value) [1] 0 4 8 12 That seems like a somewhat clunky solution, though, and requires an additional

Hi All, I am illustrating a simple, two-way ANOVA using the following data and I'm having difficulty in expressing the predicted values succinctly in R. X<- data.frame(read.table(textConnection(" Machine.1 Machine.2 Machine.3 53 61 51 47 55 51 46 52 49 50

On both wine 1.3.15 and 1.3.17, guitar pro 5.2 has a tendency to crash after a while. Wine gives the error message that it ran out of gdi handles and expect crashes. Trigger unknown.