search for: eks

Hi. System is snv_56 sun4u sparc SUNW,Sun-Fire-V440, zil_disable=1 We see many operation on nfs clients to that server really slow (like 90 seconds for unlink()). It''s not a problem with network, there''s also plenty oc CPU available. Storage isn''t saturated either. First strange thing - normally on that server nfsd has about 1500-2500 number of threads. I did

Hi, I have tried compiling the latest cvs version of dovecot on my FreeBSD 5.2.1-release box with the ports version of vpopmail: 5.4.3_1. In the configuration file I have two auth paragraphs, one for passwd authentication and one for vpopmail-auth: auth vpopmail { mechanisms = plain userdb = vpopmail passdb = vpopmail user = vpopmail } But the vpopmail dosn'nt work. I got the

The paragraph below is from ZFS admin guide Traditional Volume Management As described in ?ZFS Pooled Storage? on page 18, ZFS eliminates the need for a separate volume manager. ZFS operates on raw devices, so it is possible to create a storage pool comprised of logical volumes, either software or hardware. This configuration is not recommended, as ZFS works best when it uses raw physical

Thank you Jeff. Your code works, as usual , perfectly. I am just wondering why if i put the whole code in one line, i get an error message. sdf2 <- lapply( sdf, function(z){z$Value <-ifelse(is.na(z$Value),z$Value[!is.na(z$Value)][1],z$Value)z}) error. unexpected symbol in sdf2 Thanks again EK On Mon, Jan 8, 2018 at 3:12 AM, Jeff Newmiller <jdnewmil at dcn.davis.ca.us> wrote: >

Hi all-- I stumbled on this problem online. I did not like the solution given there which was a long UDF. I thought why cannot split and l/s apply work here. My aim is to split the data frame, use l/sapply, make changes on the split lists and combine the split lists to new data frame with the desired changes/output. The data frame shown below has a column named ID which has 2 variables a and b;

I don't know. You seem to be posting in HTML so your code is mangled. Can you post plain text and use the reprex package to make sure it produces the errorin a clean R session? -- Sent from my phone. Please excuse my brevity. On January 8, 2018 8:03:45 AM PST, Ek Esawi <esawiek at gmail.com> wrote: >Thank you Jeff. Your code works, as usual , perfectly. I am just >wondering why

OPS! Sorry i did indeed posted the code in HTML; should have known better. ifelse(is.na(z$Value),z$Value[!is.na(z$Value)][1],z$Value)z}) error. unexpected symbol in sdf2 On Mon, Jan 8, 2018 at 11:44 AM, Jeff Newmiller <jdnewmil at dcn.davis.ca.us> wrote: > I don't know. You seem to be posting in HTML so your code is mangled. Can you post plain text and use the reprex package to

I just came up with a solution right after i posted the question, but i figured there must be a better and shorter one.than my solution sdf1[[1]][1,4]<-lapplyresults[[1]] sdf1[[2]][1,4]<-lapplyresults[[2]] EK On Sun, Jan 7, 2018 at 10:13 PM, Ek Esawi <esawiek at gmail.com> wrote: > Hi all-- > > I stumbled on this problem online. I did not like the solution given > there

Why do you want to modify df1? Why not just reassemble the parts as a new data frame and use that going forward in your calculations? That is generally the preferred approach in R so you can re-do your calculations easily if you find a mistake later. -- Sent from my phone. Please excuse my brevity. On January 7, 2018 7:35:59 PM PST, Ek Esawi <esawiek at gmail.com> wrote: >I just came

OPS, Sorry i did not read the post carfully. Mine will not work if you have zeros on columns A and B.. But you could modify it to work for specific columns i believe. EK On Wed, Nov 22, 2017 at 8:37 AM, Ek Esawi <esawiek at gmail.com> wrote: > Hi *Massimo,* > > *Try this.* > > *a <- mydf==0mydf[a] <- NAHTHEK* > > On Wed, Nov 22, 2017 at 5:34 AM, Massimo Bressan

Upon closer examination I see that you are not using the split version of df1 as I usually would, so here is a reproducible example: #---- df1 <- read.table( text= "ID ID_2 Firist Value 1 a aa TRUE 2 2 a ab FALSE NA 3 a ac FALSE NA 4 b aa TRUE 5 5 b ab FALSE NA ", header=TRUE, as.is=TRUE ) sdf <- split( df1, df1$ID ) # note the extra [ 1 ]

Hi, After upgrade to dovecot 2.3.1, many IMAP clients cause errors in dovecot log: May 01 20:15:51 tiger dovecot[21985]: imap: Warning: Event 0x555fd3c01630 leaked (parent=(nil)): http-client.c:137 May 01 20:15:51 tiger dovecot[21985]: imap: Warning: Event 0x555fd3c00140 leaked (parent=(nil)): http-client.c:439 Namely: * roundcube 1.3.3 * offlineimap * nextcloud mail app Despite the errors,

Hi All? I was looking at a posting from June-17. I managed to solve it. However, when I changed the example in the posting, my solution will work only once at a time which was mentioned by Jim Lemon on his response to the original posting. This means that my solution will have to be repeated as many times as the maximum number of spaces on each gap; something that may not work well for large

In y <- substr(x, i, 1) your third integer needs to be the location not the number of digits, so change it to y <- substr(x, i, i) and you should get what you want. Cheers, Tim > Date: Sun, 21 Jan 2018 10:50:31 -0500 > From: Ek Esawi <esawiek at gmail.com> > To: Luigi Marongiu <marongiu.luigi at gmail.com>, r-help at r-project.org > Subject: Re: [R] substr

Because you need to separate the instructions with a ; (semi-colon). Hope this helps Rui Barradas Enviado a partir do meu smartphone Samsung Galaxy.-------- Mensagem original --------De: Ek Esawi <esawiek at gmail.com> Data: 08/01/2018 16:03 (GMT+00:00) Para: Jeff Newmiller <jdnewmil at dcn.davis.ca.us>, r-help at r-project.org Assunto: Re: [R] Replace NAs in split lists Thank you

Hello I want to draw a plot using the code below. Further, I want to add labels (White, Yellow, Red) to x-axis. Please kindly advise how to add the categorical labels, by modifying the code. Thank you. Elaine Code dataN <-read.csv("H:/skin_color.csv",header=T, row.names=1) dim(dataN) dataN[1,] str(dataN) obs.group<-dataN$skin_color

Hi With the example, na.locf seems to be the easiest way. > library(zoo) > na.locf(df1) ID ID_2 Firist Value 1 a aa TRUE 2 2 a ab FALSE 2 3 a ac FALSE 2 4 b aa TRUE 5 5 b ab FALSE 5 Cheers Petr > -----Original Message----- > From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of Jeff > Newmiller > Sent: Monday, January

Dear R Staff This is my file (www.fiscalforecasting.com/data.csv) if you don't download this file, my dataset same as following Year Month A B C D E 2005 July 0 *4* NA NA *1* 2005 July 0 NA NA 0 *9* 2005 July NA *4* 0 *1* 0 2005 July *4* 0 *2* *9* NA I try to count non-zero values which are not NA values for every *column* *Sincerely* *Engin YILMAZ*

...n-text-td874239.html and subsequently http://www.fileformat.info/info/unicode/char/00b1/index.htm, is: junk<- "\u00B1" print(junk) # This works very nicely. For instance: junk<-data.frame(gug=c( rep( "\u00B1 1.2", 10) , rep( "\u00B1 2.3", 10) ) ) junk$eks<-1:nrow(junk) junk$why<-with(junk, as.numeric(gug) + eks) print(summary(junk)) library(ggplot2) print( ggplot(data=junk, mapping=aes(x=eks, y=why)) + geom_point() + facet_grid(. ~ gug) ) This works very nicely on my system, but I just wanted to enquire: Is this machine-independent and...

I have a data.table which is shown below. I want to count combinations of columns on i and count on j with by. A few examples are given below the table. I want to: all months to show on the output including those that they have zero value I want the three statements combined in on if possible so the output will be one data table; that is the outputs are next to each other as manually