Displaying 6 results from an estimated 6 matches for "einthal".
2006 Dec 11
2
Switch and integer
I searched the help list and the manual, but I do not find my mistake.
Switch is working with character , with integer, but not in the third
example
Regards Knut
count1 <- 0
test
2005 Aug 15
1
png and resolution (PR#8066)
Full_Name: Knut krueger
Version: 2.1.1
OS: xp Home
Submission from: (NULL) (149.225.134.34)
In the png function the value res seems to be inactive:
bmp(filename = "c:/r/Rplot%03d.bmp", width = 1920, height = 1920, pointsize =
48, bg = "white", res = 2400)
result:
witdh/heigth = 1920 <> 20.32 mm
ppi=2400
Results as expected
png(filename =
2006 Dec 27
4
axis and times() problem
Dear R-Group,
the first example is working as expected, but I need the plot without
the box,
normally no problem, but I am not able to get the x-axis formatted as
times with the axis, command.
I tried a lot of things, nothing was working so I used the most easy
axis command in the second example here ....
# working
library(chron) # for times()
library(graphics)# for axis
2006 Dec 27
4
axis and times() problem
Dear R-Group,
the first example is working as expected, but I need the plot without
the box,
normally no problem, but I am not able to get the x-axis formatted as
times with the axis, command.
I tried a lot of things, nothing was working so I used the most easy
axis command in the second example here ....
# working
library(chron) # for times()
library(graphics)# for axis
2006 Dec 08
3
how to create data.frame with dynamic count of values
Hello R-Group
I found how to fill the data.frame ->
http://finzi.psych.upenn.edu/R/Rhelp02a/archive/70843.html
N1 <- rnorm(4)
N2 <- rnorm(4)
N3 <- rnorm(4)
N4 <- rnorm(4)
X1 <- LETTERS[1:4]
###################
nams <- c(paste("N", 1:4, sep = ""), "X1")
dat <- data.frame(lapply(nams, get))
names(dat) <- nams
dat
But I need also to create
2006 May 08
3
(g)lm ordinal or scaled values?
There is a difference in the p- value from 0.000 and 0.012 when I am
using SPSS.
0.000 when I am using the independent variable as scaled 0.012 if I am
using the variable as ordinal.
The independent variable is ordinal but it seems that R is using the
variable as an scaled, because the P- Value is computed with 4.66e-06
so I am not sure which description I am misunderstanding:
SPSS;: