search for: einthal

Displaying 6 results from an estimated 6 matches for "einthal".

2006 Dec 11
2
Switch and integer
I searched the help list and the manual, but I do not find my mistake. Switch is working with character , with integer, but not in the third example Regards Knut count1 <- 0 test
2005 Aug 15
1
png and resolution (PR#8066)
Full_Name: Knut krueger Version: 2.1.1 OS: xp Home Submission from: (NULL) (149.225.134.34) In the png function the value res seems to be inactive: bmp(filename = "c:/r/Rplot%03d.bmp", width = 1920, height = 1920, pointsize = 48, bg = "white", res = 2400) result: witdh/heigth = 1920 <> 20.32 mm ppi=2400 Results as expected png(filename =
2006 Dec 27
4
axis and times() problem
Dear R-Group, the first example is working as expected, but I need the plot without the box, normally no problem, but I am not able to get the x-axis formatted as times with the axis, command. I tried a lot of things, nothing was working so I used the most easy axis command in the second example here .... # working library(chron) # for times() library(graphics)# for axis
2006 Dec 27
4
axis and times() problem
Dear R-Group, the first example is working as expected, but I need the plot without the box, normally no problem, but I am not able to get the x-axis formatted as times with the axis, command. I tried a lot of things, nothing was working so I used the most easy axis command in the second example here .... # working library(chron) # for times() library(graphics)# for axis
2006 Dec 08
3
how to create data.frame with dynamic count of values
Hello R-Group I found how to fill the data.frame -> http://finzi.psych.upenn.edu/R/Rhelp02a/archive/70843.html N1 <- rnorm(4) N2 <- rnorm(4) N3 <- rnorm(4) N4 <- rnorm(4) X1 <- LETTERS[1:4] ################### nams <- c(paste("N", 1:4, sep = ""), "X1") dat <- data.frame(lapply(nams, get)) names(dat) <- nams dat But I need also to create
2006 May 08
3
(g)lm ordinal or scaled values?
There is a difference in the p- value from 0.000 and 0.012 when I am using SPSS. 0.000 when I am using the independent variable as scaled 0.012 if I am using the variable as ordinal. The independent variable is ordinal but it seems that R is using the variable as an scaled, because the P- Value is computed with 4.66e-06 so I am not sure which description I am misunderstanding: SPSS;: