Displaying 3 results from an estimated 3 matches for "eightout".
2011 Jul 12
1
What's wrong with my code? (Edited version-added my data)
...f
B in 98.7 de
H out 23 de
C out 43 cf
H in 567 cf
I out 12 de
E out 12 de
K out 12 cf
B in 1 cf
A out 29 de
D out 89 cf
J in 302 de
H in 12 cf
A in 153 cf
C out 233 de
My command to deal with this simple file would be:
eight <- read.csv(file="8.csv", header=TRUE, sep=",")
eightout <- subset(eight, inout=="out" & o_duration>0, select=c(inout,
enc_callee, o_duration))
f <- function(eightoutf) nrow(eightoutf)
eightnocalls <- ddply(eightout,.(enc_callee),f)
colnames(eightnocalls)[2] <- "nocalls"
eightout$nocalls <- eightnocalls$nocalls [...
2011 Jul 12
1
What's wrong with my code?
...cked my
codes so many times but still couldn't figure out what's wrong with
it...would you please help me? Thanks!
my.files <- list.files()
for (i in 1: length(my.files)) {
temp.dat <- read.csv(my.files[i])
eight <- read.csv(file="8.csv", header=TRUE, sep=",")
eightout <- subset(eight, inout=="Outgoing from panel hh" & o_duration>0,
select=c(inout, enc_callee, o_duration))
f <- function(eightoutf) nrow(eightoutf)
eightnocalls <- ddply(eightout,.(enc_callee),f)
colnames(eightnocalls)[2] <- "nocalls"
eightout$nocalls <- eig...
2011 Jul 11
1
How to generate same type of graphs using the previously written commands for a few hundred similar data sets?
...ave written out the commands for a particular subset
as the following, and then I need to do the same thing for the rest of the
data subsets, the only thing I need to change is to modify the subset names,
for example, change "seven" into "eight", "seventout" into "eightout", etc.
Is there a command in R that would do this for me? (So I don't need to
repeat myself modifying the names, copying and pasting the same things into
R.) Thank you very much!
alldata <- read.csv(file="file.csv",header=T,sep=",")
seven<- subset(alldata, asern...