Displaying 4 results from an estimated 4 matches for "effectif".
2004 Dec 27
2
list(0) to integer
Hello
I've another question :-)
I would like to transform a list to a integer.
I must be sure that the number entered by the user is
an integer! Thus, I've made :
repeat{
cat("Effectif des populations (integer):")
n<-scan("",n=1,what=list(0),quiet=TRUE)
if (is.integer(n[[1]])==TRUE) break
print("L'effectif des population doit etre un
entier")
}
That doesn't work of course but I've no idea to do
this. How verify that n[[1]] is an i...
2012 Aug 03
2
how to identify values from a column of a dataframe, and insert them in other data.frame with the corresponding id?
...lot):
poids
calee_id
maree_id
10
1.27E+12
0.3013157
20
1.27E+12
0.05726046
20
1.27E+12
0.73631699
25
1.27E+12
0.74492002
3
1.27E+12
0.74492002
27
1.27E+12
0.31776439
43
1.27E+12
0.31776439
Datuak2:
calee_id maree_id kg_totales effectif
1 1.33959e+12 0.782835873 129.7 30
2 1.33959e+12 0.782835873 129.7 40
3 1.33959e+12 0.782835873 129.7 10
4 1.33959e+12 0.782835873 129.7 5
5 1.33959e+12 0.782835873 129.7 1.7
6 1.339...
2007 Jun 06
2
names not inherited in functions
...me ( names(table(vari)),chiffr)
rownames(chiffr) <- NULL
chiffr <- data.frame (nom.chiffr, chiffr)
return(chiffr)
}
res <- rep(NA, 4)
for (i in 1 : ncol(tablo))
res <- rbind(res,descriptifvar(tablo[,i]))
colnames(res) <- c("variable", "niveau", "effectif", "pourcentage")
return(res[-1,])
}
# NB I used this function on a data.frame with only factors in
2006 Jun 18
0
Spare RailsConf ticket (another one!)
Unfortunately, I can''t go to RailsConf either. I''m therefore offering my
ticket for the usual $400 (list price).
Please email me off list if you''re interested.
Thanks.
--
Graham