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eckerl
2005 Apr 06
1
nls.control
Hello everyone,
I'm trying to test the accurracy of R on the Eckerle4 dataset from NIST and
I don't understand how the control option of the nls function works.
I tought nls(...) was equivalent to nls(...control=nls.control()) i.e nls.control() was the default value of control, but here is the error I get :
> n2=nls(V1~(b1/b2) * exp(-0.5*((V2-b3)/b2)^2),dat...