Displaying 14 results from an estimated 14 matches for "e_ij".
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e_i
2005 Nov 16
6
nlme question
I am using the package nlme to fit a simple random effects (variance
components model)
with 3 parameters: overall mean (fixed effect), between subject
variance (random) and
within subject variance (random).
I have 16 subjects with 1-4 obs per subject.
I need a 3x3 variance-covariance matrix that includes all 3 parameters
in order to
compute the variance of a specific linear
2005 Mar 28
1
mixed model question
I am trying to fit a linear mixed model of the form
y_ij = X_ij \beta + delta_i + e_ij
where e_ij ~N(0,s^2_ij) with s_ij known
and delta_i~N(0,tau^2)
I looked at the ecme routine in package:pan, but this routine
does not allow for different Vi (variance covariance matrix of
the e_i vector) matrices for each cluster.
Is there an easy way to fit this model in R or should I bite the...
2011 Jul 19
1
notation question
Dear list, I am currently writing up some of my R models in a more
formal sense for a paper, and I am having trouble with the notation.
Although this isn't really an 'R' question, it should help me to
understand a bit better what I am actually doing when fitting my
models!
Using the analysis of co-variance example from MASS (fourth edition, p
142), what is the correct notation for the
2003 Mar 30
1
simple test of lme, questions on DF corrections
...Details:
I''ve read relevant parts of Pinheiro and Bates''s book and various
articles. To test my understanding of various definitions, I
considered the simplest limit of fitting a 1-parameter model
(i.e., just the mean or intercept) with 1 level of grouping:
y_ij = beta + b_i + e_ij
where beta is the population mean, b_i is the random effect for
the i''th group, and e_ij is the random error of the j''th
observation from the i''th group. I''m using the simple "Rail"
dataset of N=18 observations, consisting of 3 measurements of
ultraso...
2008 Dec 02
1
question on lmer function
suppose something like probability(passing test) is driven by
1. fixed effects -- sex
2. district effects - district funding
3. school effects - neighborhood income, racial composition, % two parent
families, ...
4. class effects - teacher quality measurement,
5. individual random effects - IQ.
how would such a model be setup in lmer? I can't find much discussion on
the
2009 May 07
2
lasso based selection for mixed model
Dear useRs (called Frank Harrell, most likely),
after having preached for years to my medical colleagues to be cautious
with stepwise selection procedures, they chanted back asking for an
alternative when using mixed models.
There is a half dozen laXXX packages around for all types of linear models,
but as far I see there is none for mixed models such as lme. Even
boot.stepAIC (which I
2008 May 07
0
Help with Mixed effect modeling in R
Hi everyone,
I want to fit the following mixed effect model
Y_ij = b_0i + b_1i * (t_ij*grp_ij == 1) + b_2i * (t_ij*grp_ij == 2) +
v_0i + v_1i*t_ij + e_ij
with a different covariance matrix of random effects for each group.
(Y is the response
t is time
grp is the group indicator
b 's are fixed effects
v 's are random effects)
I know that this is possible in SAS (I am no expert in SAS, I just
looked up some notes) as
* Fit...
2003 Oct 05
2
Jonckheere-Terpstra test
Hello,
can anybody here explain what a Jonckheere-Terpstra test is and whether it is
implemented in R? I just know it's a non-parametric test, otherwise I've no
clue about it ;-( . Are there alternatives to this test?
thanks for help,
Arne
2018 Feb 16
2
[FORGED] Re: SE for all levels (including reference) of a factor atfer a GLM
...etrisation of the model which by default in R is formed using the
so-called "treatment" contrasts.
To wander from R into statistics (sorry Bert) the problem arises because
the "usual" parametrisation of the model is the "over-parametrised" form:
Y_ij = mu + beta_i + E_ij (i = 1, ..., I, j = 1, ..., J_i)
where Y_ij is the j-th observation corresponding to the i-th "treatment"
or group. (Things get a bit more complicated in "multi-way" models;
let's not go there.)
The parameter "mu" is the "grand mean" and the "be...
2003 Apr 18
1
Help with nlme--freq weights, logit model, and more
Below you will find the output from a failed multi-level model run. I am
trying to estimate the following model:
Pr(PLFP=1)= logistic regression ->
B1_j * bm + B2_j * wm + B3_j bf + B4_j wf + B5 yrsed+ B6 age+ B7 age^2+e_ij
B1_j = G01 + G11 bmxd + d1
B2_j = G02 + G12 wmxd + d2
B3_j = G03 + G13 bfxd + d3
B4_j = G04 + G14 wfxd + d4
d1-d4 freely correlated
Note that there is no intercept, so the B1-B4 are race/sex specific
intercepts (bm=black male, wm=white male, bf=black female, wf=white
female).
This model all...
2018 Feb 16
0
SE for all levels (including reference) of a factor atfer a GLM
This is really a statistical issue. What do you think the Intercept term
represents? See ?contrasts.
Cheers,
Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along and
sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Thu, Feb 15, 2018 at 5:27 PM, Marc Girondot via R-help <
r-help at
2018 Feb 16
2
SE for all levels (including reference) of a factor atfer a GLM
Dear R-er,
I try to get the standard error of fitted parameters for factors with a
glm, even the reference one:
a <- runif(100)
b <- sample(x=c("0", "1", "2"), size=100, replace = TRUE)
df <- data.frame(A=a, B=b, stringsAsFactors = FALSE)
g <- glm(a ~ b, data=df)
summary(g)$coefficients
# I don't get SE for the reference factor, here 0:
2011 Mar 07
3
linear mixed model with nested factors
Hi R-help.
I am trying to run a linear mixed model with nested factors with either
lme or lmer and I am having no luck obtaining the same results as Minitab.
Here is Minitab's code:
MTB > GLM 'count' = site year replicate(site year) site*year;
SUBC> Random 'year' 'replicate';
Can you tell me how to code this in R?
The settings are typeII, Tukey,
2007 Nov 22
5
testing independence of categorical variables
hi,
is there a way of calculating of measuring dependence between two
categorical variables. i tried using the chi square test to test for
independence but i got error saying that the lengths of the two
vectors don't match. Suppose X and Y are two factors. X has 5 levels
and Y has 7 levels. This is what i tried doing
>temp<-chisq.test(x,y)
but got error "the lengths of the two