Displaying 1 result from an estimated 1 matches for "dupareasum".
2009 Oct 29
5
Summing identical IDs
...5
6 0.50 5
7 293.00 6
8 300.00 7
9 0.09 7
Becomes
Acres Bldgid
1 100.00 1
2 101.00 2
3 100.00 3
4 130.00 4
5 156.50 5
7 293.00 6
8 300.09 7
dup<-unique(DF$Bldgid[duplicated(Bldgid)])
dupbuild<-DF[DF$Bldgid %in% dup,]
dupbuild..dupareasum<-sum(dupbuild$Acres[duplicated(dupbuild$Bldgid)])
This sums the unique Ids of the duplicated records, not whati want. Thanks
ahead of time
JR
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