Displaying 5 results from an estimated 5 matches for "dsstoffer".
2009 Oct 03
1
Multiple time series and their names
Suppose I have multiple time series with names for each one, for example,
x <- ts(matrix(rnorm(30,0,1),10,3), names=c("Juan", "Tuey", "Trey"),
frequency=4)
So now, as I start to explore these series, if I do everything at once, the
names
stay attached to the series. For example,
plot(x) # gives a plot of the series with their names
acf(x) # gives the ACFs &
2008 Feb 11
0
Testing for differecnes between groups, need help to find the right test in R. (Kes Knave)
.../mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
>
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Message: 44
Date: Sun, 10 Feb 2008 18:12:01 -0800 (PST)
From: dss <dsstoffer at gmail.com>
Subject: Re: [R] Re gression with time-dependent coefficients
To: r-help at r-project.org
Message-ID: <15404399.post at talk.nabble.com>
Content-Type: text/plain; charset=UTF-8
There's an example in our text: http://www.stat.pitt.edu/stoffer/tsa2
Time
Series Analysis a...
2010 Nov 24
0
4. Rexcel (Luis Felipe Parra)-how to run a code from excel
...roducible code.
>
--
Spencer Graves, PE, PhD
President and Chief Operating Officer
Structure Inspection and Monitoring, Inc.
751 Emerson Ct.
San Jos?, CA 95126
ph: 408-655-4567
------------------------------
Message: 139
Date: Mon, 22 Nov 2010 20:29:11 -0800 (PST)
From: David Stoffer <dsstoffer at gmail.com>
To: r-help at r-project.org
Subject: Re: [R] Is it possible to make a matrix to start at row 0?
Message-ID: <1290486551690-3054829.post at n4.nabble.com>
Content-Type: text/plain; charset=us-ascii
bogdanno-2 wrote:
>
> I want to make the matrix to be indexed from ro...
2008 Nov 03
1
array in version 2.8.0
What happened? TIA.
In version 2.7.x:
> (x <- array(1:4, c(2,2)))
[,1] [,2]
[1,] 1 3
[2,] 2 4
> as.array(x)
[,1] [,2]
[1,] 1 3
[2,] 2 4
In version 2.8.0:
> (x <- array(1:4, c(2,2)))
[,1] [,2]
[1,] 1 3
[2,] 2 4
> as.array(x)
Error: evaluation nested too deeply: infinite recursion /
options(expressions=)?
-----
The power
2008 Jul 11
1
Comparing complex numbers
Is there an easy way to compare complex numbers?
Here is a small example:
> (z1=polyroot(c(1,-.4,-.45)))
[1] 1.111111-0i -2.000000+0i
> (z2=polyroot(c(1,1,.25)))
[1] -2+0i -2+0i
> x=0
> if(any(identical(z1,z2))) x=99
> x
[1] 0
# real and imaginary parts:
> Re(z1); Im(z1)
[1] 1.111111 -2.000000
[1] -8.4968e-21 8.4968e-21
> Re(z2); Im(z2)
[1] -2