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...id.arrange() library(gridGraphics) library(gridExtra) grab <- function{ grid.echo() grid.grab() } x <- rnorm(100, 1, 2) y <- rnorm(100, 0, 0.5) plot(x,y) p <- grab() a <- rnorm(20, 0, 1) b <- rnorm(20, 1, 2) plot(a, b) q <- grab() grid.arrange(p, q) Best, Eivind K. Dovik Bergen, NO > ______________________________________________ > R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented,...

I have dose response data I have analyzed with the 'drc' package. Using plot() works great. I want to arrange my plots and source data on a single page. I think 'gridExtra' is the usual package for this. I could use plot() and par(mfrow=...), but then I can't put the source data table on the page. gridExtra provides grid.table() which makes nice graphical tables. It

...thelist # Creating the type-vector type <- c() for(i in 1:length(thelist)){ type <- c(type, rep(names(thelist)[i], sapply(thelist, nrow)[i])) } # Creating the data frame df <- data.frame(type, do.call(rbind.data.frame, c(thelist, make.row.names = FALSE))) df Kind regards, Eivind K. Dovik Bergen, NO > > -- > Kevin E. Thorpe > Head of Biostatistics, Applied Health Research Centre (AHRC) > Li Ka Shing Knowledge Institute of St. Michael's Hospital > Assistant Professor, Dalla Lana School of Public Health > University of Toronto > email: kevin.thorpe at...

You may also want to check this out: plot(ttt, type = "p") points(ttt, col = ifelse(ttt < 8, "black", "red")) Eivind K. Dovik Bergen, NO On Tue, 1 May 2018, Christopher W Ryan wrote: > Excellent! Worked like a charm. Thanks. > > --Chris Ryan > > On Tue, May 1, 2018 at 4:33 PM, William Dunlap <wdunlap at tibco.com> wrote: > >> The ts method for plot() is quirky. You can use the default met...

Excellent! Worked like a charm. Thanks. --Chris Ryan On Tue, May 1, 2018 at 4:33 PM, William Dunlap <wdunlap at tibco.com> wrote: > The ts method for plot() is quirky. You can use the default method: > > plot(as.vector(time(ttt)), as.vector(ttt), type = "p", col=ifelse(ttt<8, > "black", "red")) > > > Bill Dunlap > TIBCO Software

..., B = data.frame( x=5:6, y=7:8 ) ) D <- data.frame( Type = names( L ) , stringsAsFactors = FALSE ) D$data <- L unnest(D, data) #> Type x y #> 1 A 1 3 #> 2 A 2 4 #> 3 B 5 7 #> 4 B 6 8 ######## On Wed, 2 May 2018, Eivind K. Dovik wrote: > On Wed, 2 May 2018, Kevin E. Thorpe wrote: > >> I suspect this is pretty easy, but I'm having trouble figuring it out. >> Basically, I have a list of data frames such as the following example: >> >> list(A=data.frame(x=1:2, y=3:4),B=data.frame(x=5:6,y=7...

I suspect this is pretty easy, but I'm having trouble figuring it out. Basically, I have a list of data frames such as the following example: list(A=data.frame(x=1:2, y=3:4),B=data.frame(x=5:6,y=7:8)) I would like to turn this into data frame where the list elements are essentially rbind'ed together and the element name becomes a new variable. For example, I would like to turn the

hello sir im working on text classification using java and r programming i start with exporting a document term matrix (tdm) from my java programme using corpus and now i try to apply knn algorithem using the matrix and r but i cant do that any help sir here my data here my script https://mega.nz/#!Q6J2ibAA!4PadiOKbP7rLodyiRrVsdKl-D2ZP7LYm0gaz94uBmF8 itry to post put icant whay!!

Hi, May I please ask how I do the following in R. Sorry - this may be trivial, but I am struggling here for this. For two dataframes (A and B), I wish to identify (based on a primary key-column present in both A & B) - 1. Which records (rows) of A did not match with B, and 2. Which records of B did not match with A ? I came across a setdt function while browsing, but when I tried