Displaying 20 results from an estimated 48 matches for "dlpli".
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dlply
2009 Jul 21
1
strange dlply behavior
I'm running R 2.9.1 on winXP, using the library plyr.
Can anyone explain to me what is going wrong in this code? (in particular
see lines marked with ******************) Trying to modify objects in a list
created using dlply seems to corrupt the objects in the list.
> library(plyr)
> d=as.data.frame(cbind(c(1,1,1,2,2,2),c(1,2,3,4,5,6)))
> d
V1 V2
1 1 1
2 1 2
3 1 3
4 2 4
5
2012 Mar 18
1
Help with dlply, loop and column names
Hi,
I have a dataframe basically like this:
> head(asturias.gen2011[,c(1,4,9:14)])
municipio total upyd psoe pp iu fac tipo
440 Allande 2031 1.44 31.10 39.75 4.01 21.62 1000-10000
443 Aller 12582 1.37 33.30 37.09 15.53 10.35 10000-50000
567 Amieva 805 1.48 32.69 37.36 6.15 20.16 <1000
849
2011 Mar 11
1
Generation of random numbers in a function - (Return command)
Dear R helpers
I have following data.frame and for each product_name, I have associated mean and standard deviation. I need to generate 1000 random no.s for each of these products and find the respective mean and standard deviation.
My R code is as follows.
library(plyr)
library(reshape2)
filtered_new <- data.frame(product_name = c("P1", "P2", "P3",
2013 Jan 08
2
plot residuals per factor
Dear R-users,
I want to plot residuals vs fitted for multiple groups with ggplot2.
I try this code, but unsuccessful.
library("plyr")
models<-dlply(dat1,"d",function(df)
mod<-lm(y~x,data=df)
ggplot(models,aes(.fitted,.resid), color=factor(d))+
geom_hline(yintercept=0,col="white",size=2)+
geom_point()+
geom_smooth(se=F)
--
---
Catalin-Constantin ROIBU
2011 Oct 25
1
regression using GMM for mulltiple groups
Inthe code below I was trying to to obtain the GMM estimates for CAPM
(REGRESSION) for 36 stocks each have 180 observations,however it only gives
me one output rather than 36.
In SAS i would just put in a *By statement*. I have a variable TICKER that
categorize them into 36 groups.
*How can I obtain all 36 output instead of just one.*
**
2010 Nov 25
1
Help on running regression by grouping firms
Hi there,
I have a huge data set with multiple firms years and other firm characteristics. I want to run a regression on the dependent variable and other explanatory variables and calculate the residual terms by grouping the firms in same year and same industry.
What I want to do is to divide my obseravtion into sub sample that contains the observation with same fiscal year(FYEAR=1990) and same
2012 Sep 12
6
How to append the random no.s for different variables in the same data.frame
Dear R helpers,
(At the outset I sincerely apologize if I have not put forward my following query properly, though I have tried to do so.)
Following is a curtailed part of my R - code where I am trying to generate say 100 random no.s for each of the products under consideration.
library(plyr)
n = 100
my_code = function(product, output_avg, output_stdev)
{
BUR_mc = rnorm(n, output_avg,
2013 Aug 27
1
[plyr] Moving average filter with plyr
Dear all,
I'm stuck with a problem using plyr to process a rather large junk of data. What I'm trying to do is applying a moving average to all the subparts of the dataframe (the example data can be found here https://dl.dropboxusercontent.com/u/2414056/testData.Rdata).
require(plyr)
load("testData.Rdata")
applyfilter<-function(x){
return(filter(x,rep(1/5, times=5)))
}
2010 Aug 09
2
coef(summary) and plyr
Dear all,
I?m having trouble getting a list of regression variables back into a dataframe.
mydf <- data.frame(x1=rnorm(100), x2=rnorm(100), x3=rnorm(100))
mydf$fac<-factor(sample((0:2),replace=T,100))
mydf$y<- mydf$x1+0.01+mydf$x2*3-mydf$x3*19+rnorm(100)
dlply(mydf,.(fac),function(df) lm(y~x1+x2+x3,data=df))->dl
here I?d like to use
ldply(dl,coef(summary)) or something
2011 Jun 03
0
ragged data.frame? using plyr
I have a dataset that looks like:
set.seed(144)
sam<-sample(1000,100)
dat<-data.frame(id=letters[1:10],value=rnorm(1000),day=c(rep(1,100),rep(2,100),rep(3,100),rep(4,100),rep(5,100)))
I want to "normalise" it using the following function (unless you have
a better idea...):
adj.values<-function(dframe){
value_mean<-mean(dframe$value)
value_sd<-sd(dframe$value)
2012 Apr 03
1
help in ddply
Hi
I've records like this
df=
x panel
4 1
93 2
21 3
83 4
75 1
87 2
87 3
78 4
50 1
76 2
86 3
65 4
84 1
40 2
39 3
26 4
i want to create histogram out of it . i want all the mid and count values
for panel wise
my code is
histoutput = ddply(df,.(df[2]),hist)
i'm not able to get the required result.
please help me
using for loop takes a lot of time if there are more records
-----
Thanks
2012 Aug 28
1
don't print object attributes
Dear all
Suppose the object below:
> require(Hmisc)
> require(plyr)
> x <- dlply(iris, .(Species), describe)
How can I print the object without displaying the attributes? I
inspected ?print and ?print.default with no luck.
> x
$setosa
x[, "Sepal.Length"]
n missing unique Mean .05 .10 .25 .50 .75
50 0 15 5.006 4.40 4.59
2011 Feb 08
1
Grouping by factors in R
I'm having a hard time figuring out how to group results by certain
factors in R. I have data with the following headings:
[1] "Time" "Plot" "LatCat" "Elevation" "ElevCat"
"Aspect" "AspCat" "Slope"
[9] "SlopeCat" "Species" "SizeClass" "Stems"
and
2009 Mar 04
3
Bug in by() with dates as levels?
Trying to use dates in their R-native form (e.g., POSIXct) rather than
turning them into character strings, I've encountered the following problem.
I create a data frame where one column is dates. Then I use "by()" to do a
calculation on grouped subsets of the data. When I try to extract values
from the result, I get "subscript out of bounds". The example below shows
the
2011 Sep 29
3
For loop for subset - repeating same over and over?
Hello, I am using the following script to run an anova for numerous species
in a table that I have:
SiteSpp <-
2011 Nov 03
2
Take variables in data.frame and create list of matrices
Hi,
I have this sample data below and would like to create a list of matricies.
setseed(1254)
id <- c(1,1,1,1 ,2,2,2)
o <- as.factor(c(1:4, 1, 3, 4))
r <- rep(.5, 7)
v <- rnorm(7)
s <- rnorm(7)
dat <-data.frame(id, o, r, v, s)
dat
#> dat
# id o r v s
# 1 1 0.5 0.7024631 2.0813672
# 1 2 0.5 -0.5541955 0.1095156
# 1 3 0.5 -1.0418167 0.4164930
# 1
2012 Mar 30
3
Adding text for written comments to bottom of graphs
Hello All,
Recently developed the code below for graphing patterns of chemotherapy administration. As someone just starting to use R in their work, I managed to figure out some parts of the code but needed help with others.
setwd("N:/Regimen Coding/0906/Plots Test")
getwd()
TestData <- structure(list(profile_key = c(1, 1, 1, 1, 1, 2, 2, 2, 2, 2,
2, 3, 3, 3, 3, 3), line = c(1, 1,
2012 Sep 26
1
Change in order of names after applying "plyr" package
Dear R helpers
I have following two data.frames viz. equity_data and param.
equity_data = data.frame(security_id = c("Air", "Air", "Air", "Air", "Air", "Air", "Air", "Air", "Air", "Air", "Air", "Air", "AB", "AB", "AB", "AB",
2011 Aug 29
2
splitting into multiple dataframes and then create a loop to work
Dear All
Sorry for this simple question, I could not solve it by spending days.
My data looks like this:
# data
set.seed(1234)
clvar <- c( rep(1, 10), rep(2, 10), rep(3, 10), rep(4, 10)) # I have 100
level for this factor var;
yvar <- rnorm(40, 10,6);
var1 <- rnorm(40, 10,4); var2 <- rnorm(40, 10,4); var3 <- rnorm(40, 5, 2);
var4 <- rnorm(40, 10, 3); var5 <- rnorm(40, 15,
2009 Sep 28
4
Running an ANOVA with a BY
I have a simple 1 way anova coded like
summary(ANOVA1way <- aov(Value ~ WellID, data = welldata))
How can I use the BY function to do this ANOVA for each group using another
variable in the dataset?? I tried coding it like this, but it doesn't seem
to work.
summary(ANOVA1way <- by(welldata, Analyte, function(x) aov(Value ~ WellID,
data = welldata)))
In SAS I would code it like this: