Displaying 2 results from an estimated 2 matches for "dl_n".
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2009 Jun 02
2
What do you think about my function?
...ddf <- data.frame(dd1=d1,dd2=d2,dd3=d3,dd4=d4)
for (i in 1:length(n1)){
wekt_n = ndf[i,]
wekt_d = ddf[i,]
wekt_n_ok = wekt_n[!is.na(wekt_n)]
wekt_n_ok = as.numeric(wekt_n_ok)
wekt_d_ok = wekt_d[!is.na(wekt_d)]
wekt_d_ok = as.numeric(wekt_d_ok)
dl_n = length(wekt_n_ok)
dl_d = length(wekt_d_ok)
if (skl[i] %in% NA){ wynik[i]=NA}
else {wynik[i] =
sum(((1*wekt_n_ok)+(3*wekt_n_ok))/((1*dl_n)+(3*dl_d)))}
}
return (wynik)
}
### Call function ###
dzieci$zywnosc <- zywnoscCalosc(dzieci$zywnosc, dzieci$sklepik,
dzieci$skl...
2009 May 31
1
Error:non-numeric argument in my function
Hello!
I have a function:
zywnoscCalosc<- function( jedzenie, n1, n2, n3, n4, d1, d2, d3, d4 ) {
ndf <- data.frame(nn1=n1,nn2=n2,nn3=n3,nn4=n4)
ddf <- data.frame(dd1=d1,dd2=d2,dd3=d3,dd4=d4)
for (i in 1:length(n1)){
wekt_n = ndf[i,]
wekt_n_ok = wekt_n[!is.na(wekt_n)]
dl_n = length(wekt_n_ok)
wynik = (1*wekt_n_ok)/(1*dl_n)
}
}
and I get an error like this:
Error in 1 * wekt_n_ok : non-numeric argument to binary operator
Anybody can help me?
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