Displaying 17 results from an estimated 17 matches for "diviya".
2012 Jul 26
3
Solving quadratic equation in R
Hi there,
I would like to solve a simple equation in R
a^2 - a = 8.313
There is no real solution to this problem but I would like to get an
approximate numerical solution. Can someone suggest how I can set this up?
Thanks in advance,
Diviya
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2011 Sep 14
2
Optimization package
...It is -
y <- (p*exp(-a*d)*(1-exp((d-p)*(a-x[1]))))/((p-d)*(1-exp(-p*(a-x[1]))))
For this equation, I have all the values except for x[1]. So I need to solve
this problem numerically. Can anyone suggest an optimization package that I
can use to estimate the value for x[1]?
Thanks in advance,
Diviya
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2011 Nov 11
1
barplot names.arg
...using names.arg to print the label for the bars. However, I would like
to group all the entries for the Mon and print the label only once. Is
there a way to do this? The documentation for barplots suggests that this
can be done but I was not able to figure it out. Please help.
Thanks in advance,
Diviya
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2011 Dec 05
1
Binning the data based on a value
...[1] <- c(10, 60)
bin[2] <- c(110, 200, 250)
bin[3] <- c(400, 450)
NOTE that the number of data points in each bin is not the same and the
empty bins are removed (since there are no points between [199..299],
bin[3] starts at 400.
Any help would be most appreciated. Thank you in advance.
Diviya
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2012 Mar 19
1
Linear regression
...pha1
beta2 <- 1-apha2
I now want this equation to estimate the values of A and B. Both A and B
are constrained to be between (0,1). I would like to use lm with these
constraints and I am having a little trouble in defining the equations
correctly. Any help would be most appreciated.
Thank you,
Diviya
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2012 Dec 21
1
Legend symbols
Hi there,
I was wondering if there is any R package that one can use for plotting
that has more legend symbols - the standard pch has 18 symbols but I need
~30 for my application- and just using different colors is not an option.
Thank you in advance,
Diviya
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2013 Jan 31
1
LogLik of nls
...ulating the logLik of nls function?
I am using the nls to fit the following model to data -
Model 1: y ~ Ae^(-mx) + Be^(-nx) +c
and want to understand what is the likelihood function used by nls.
Presumably it is using -
N(Ae^(-mx) + Be^(-nx) +c, var = residuals from nls)
Thank you in advance,
Diviya
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2011 Dec 08
1
R function implementation
...ing if it is possible to see the code between
some of the functions.
I am looking for the raw code for simple data handling functions such as
split, cut, etc so that I can directly use those in C. I am fairly new to
programming in C and so this will be a big help.
Thanks for you help in advance.
Diviya
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2011 Jun 12
2
NLS fit for exponential distribution
...gradient matrix at initial parameter estimates
Any suggestions how I can fix this? Also next I want to try to fit a sum of
2 exponentials to this data. So the new model would be y = a*exp[(-m1+
m2)*x]+c . Any suggestion how I can do this... Any help would be most
appreciated. Thanks in advance.
Diviya
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2012 Jul 23
2
Solving equations in R
Hi there,
I would like to solve the following equation in R to estimate 'a'. I have
the amp, d, x and y.
amp*y^2 = 2*a*(1-a)*(-a*d+(1-a)*x)^2
test data:
amp = 0.2370 y=
0.0233 d=
0.002 x=
0.091
Can anyone suggest how I can set this up?
Thanks,
Diviya
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2011 Sep 20
1
NLS error
...t cases, but every now and again, I get the following error -
Error in numericDeriv(form[[3L]], names(ind), env) :
Missing value or an infinity produced when evaluating the model
Any suggestions on how I can resolve this? Can you suggest a better way for
picking the starting parameters?
Thanks,
Diviya
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2011 Jun 12
1
Error in NLS example in the documentation
...st + A * exp(B * x), trace = TRUE) :
step factor 0.000488281 reduced below 'minFactor' of 0.000976562
In addition: Warning message:
In nls(y ~ Const + A * exp(B * x), trace = TRUE) :
No starting values specified for some parameters
Can someone propose how I can fix this error? Thanks.
Diviya
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2012 Feb 14
1
Strange plotting error
...im doesnt work
data <- rnorm(2000,0,1)
acf(data,xlim=c(1,10)) # works - the plot starts at 1
acf(data,lag=100,xlim=c(1,100)) # this does not work and the plot still
starts at 0
Is there another way to specify the xlim or the starting value for x? Any
help would be most appreciated.
Thanks,
Diviya
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2012 Sep 10
1
Rscript installing packages
...nstalling package(s) into ‘/home/xx/R/x86_64-pc-linux-gnu-library/2.13’
(as ‘lib’ is unspecified)
Error in contrib.url(repos, type) :
trying to use CRAN without setting a mirror
Any idea how I can fix this or specify "lib"? Any help would be most
appreciated.
Thank you in advance,
Diviya
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2012 Dec 16
1
nls for sum of exponentials
Hi there,
I am trying to fit the following model with a sum of exponentials -
y ~ Ae^(-md) + B e^(-nd) + c
the model has 5 parameters A, b, m, n, c
I am using nls to fit the data and I am using DEoptim package to pick the
most optimal start values -
fm4 <- function(x) x[1] + x[2]*exp(x[3] * -dist) + x[4]*exp(x[5] * -dist)
fm5 <- function(x) sum((wcorr-fm4(x))^2)
fm6 <- DEoptim(fm5,
2011 May 26
2
likelihood ratio test
Dear R-help,
Can anybody tell me which R package has Lo-Mendell Rubin LR test and Bootstrap
LR test to compare the model fit between k class and k+1 class model for Latent
class analysis?
Thanks in advance,
warn regards,Ms.Karunambigai M
PhD Scholar
Dept. of Biostatistics
NIMHANS
Bangalore
India
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2011 Jun 15
1
Print the summary of a model to file
...9,
-0.631051094181987, 109.678196497457, 68.5588878978997, 0.528151752824769,
0, 0)
c(-0.00018212632256334, 0.166967461792613, 10.8045839935834,
0.000288607886496774, 0.00152233960007251, 0.157595671762849,
-0.631051094181987, 109.678196497457, 68.5588878978997, 0.528151752824769,
0, 0)
Thanks,
Diviya
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