Displaying 7 results from an estimated 7 matches for "divison".
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divisor
2012 Sep 18
2
Data frame divison by another data frame with common groups and different length
Dear all,
I have two different data frames, that have two common variables: date and
sample. Here is a small extract of both of them
> head(traffic)
datet sessiont samplet buddleiat
1 07-08-2012 1 1 1
2 07-08-2012 1 1 1
3 07-08-2012 1 1 1
4 07-08-2012 1 2 3
5 07-08-2012 1 2
2011 Feb 16
3
image() with a vector
...(z),zlim=c(1,7),col=heat.colors(7),xlab="Year",ylab="Action",yaxt="n",xaxs="r",yaxs="r")
The problem is that when I include the figure that is produced in my pdf, there ends up being a white line that runs through the middle horizontally (where the divison of the cells is) which ruins the presentation of the graphic as x
is a time series, and z is an action that is performed at that time. There is only one action that is performed at each time step in x, and having the line running through the middle might cause confusion as to how many actions are...
2006 Mar 01
1
Eager loading problem. Help greately appreciated
Each Timesheet has an employee. An employee has a division and a
location.
I want to find all the timesheets with a status of 2. I then iterate
over the timesheet collection and print the timesheet name, employee
name, employee divison name, and employee location name. Like so:
for t in
Timesheet.find(:all,:conditions=>"status=2",:include=>:employee)
puts timesheet.date
puts timesheet.employee.name
puts timesheet.employee.division.name
puts timesheet.employee.location.name
end
Adding the ":include...
2009 Nov 06
2
another question: how to delete one of columes in two ones with high correlation(0.95)
my programe is below:
a=c(1,2,1,1,1); b=c(1,2,3,4,1); c=c(3,4,3,3,3); d=c(1,2,3,5,1);
e=c(1,5,3,5,1)
data.f=data.frame(a,b,c,d,e)
origin.data<-data.f
cor.matrix<-cor(origin.data)
origin.cor<-cor.matrix
m<-0
for(i in 1:(cor.matrix[1]-1))
{
for(j in (i+1):(cor.matrix[2]))
{
if (cor.matrix[i,j]>=0.95)
{
data.f<-data.f[,-i];
i<-i+1
}
2003 Jul 02
2
user mannual
Dear Sir
I have successfuly downloaded R package.
Kindly let me know where i will get _/*user mannual*/_ for the same.
awaiting a prompt reply
with regards
Pankaj
@#@#@#@#@#@#@#@#@#@#@#@#@#@#@#@#@#@#@#@#@#@#@
Pankaj Kumar
Research Scholar
Climatology & Hydrometeorology Divison
Indian Institute Of Tropical Meteorology
Homi Bhabha Road, Pune-411008
India
Phone No. +91-20-5893600 Ext. 361 (Work)
+91-20-5897381 (Home)
Fax: +91-20-5893825
E-mail: pankaj at tropmet.res.in
pinku_1975 at yahoo.com
2006 Feb 28
3
[AR] #{id} namespace visibility used in finder_sql
...:finder_sql => ''select
u.userid, u.username, p.personname, <etc>
<snip>
where
<snip>
s.divid = #{id}''
Here #{id} is correctly used as the current Divison record''s id for
querying, works as explained in all api examples.
m=Division.find(18).members returns a list of users.
Now, inside another model, a try to use #{id} inside finder_sql, for
using current record and grab external datas using active model
record''s id.
In console, i...
2005 Nov 29
2
qcc
violating.runs
I read from the news
cran.r-project.org/doc/Rnews/Rnews_2004-1.pdf
that the criteria for the violating is 5 but
1)I cannot find "5" in the code of the function. Where is the "5" ?
2)What is the easiest way to change it ?
3)Is there any more criterias made somewhere ?
Yours sincerelly, Tommi Viitanen