search for: divides

Hi guys, I found the troblue and fix it! I attached the patch. The trouble was in the command reply buffer use. You compute the value that value = reply[6]*256+reply[5] <- it's wrong The right solution: value = reply[5] * 256 + reply[6]; And other bug, battery.runtime compute, you divide this value 60 <- it's wrong right value: divide 1.0 I continue the work on this

Under 4.6, we recompiled the kernel with HZ=100 for improved time-keeping in VMware guests. I've read about the backporting of the divider patch into RHEL/CentOS 4.7, but it sounds like it also comes with some bugs. I have been unable to determine the current status of the divider option in the latest 4.7 kernel update. I have experimented with "divider=10" and it works with no major

Here's another example of my plotmath whipping boy, the Normal distribution. A colleague asks for a Normal plotted above a series of axes that represent various other distributions (T, etc). I want to use vectors of equations in plotmath to do this, but have run into trouble. Now I've isolated the problem down to a relatively small piece of working example code (below). If you would

Hi, I have a problem that I'm finding a bit tricky. I'm trying to use mapply and assign to generate curried functions. For example, if I have the function divide divide <- function(x, y) { x / y } And I want the end result to be functionally equivalent to: half <- function(x) divide(x, 2) third <- function(x) divide(x, 3) quarter <- function(x) divide(x, 4) But I want

Dear r-help, Now I am drawing graphs with xyplot function. In order to place a legend under the plots I use the key argument in the xyplot function. One of the 'key' components is 'divide', which defines a number of points on the each line of the legend. The default is 3 points. I would like a single point, so I set divide = 1. Call to xyplot didn't produce

libswfdec/swfdec_as_interpret.c | 1 + test/trace/Makefile.am | 3 +++ test/trace/crash-0.5.3-divide-by-zero.as | 5 +++++ test/trace/crash-0.5.3-divide-by-zero.swf |binary test/trace/crash-0.5.3-divide-by-zero.swf.trace | 1 + 5 files changed, 10 insertions(+) New commits: commit c6d96d7d47704ca3d62c08d35874c64f7878bdf2 Author:

Hey all, In my code, it seems that when I divide two integers, the result is an integer. Is there any way to make it such that when I divide two integers, the result is a double? Any help appreciated, Jin _______________________________________________ Rails mailing list Rails-1W37MKcQCpIf0INCOvqR/iCwEArCW2h5@public.gmane.org http://lists.rubyonrails.org/mailman/listinfo/rails

Hi, I have a matrix, say m=matrix(c( 983,679,134, 383,416,84, 2892,2625,570 ),nrow=3 ) i can find its row/col sum by rowSums(m) colSums(m) How do I divide each row/column by its rowSum/colSums and still return in the matrix form? (i.e. the new rowSums/colSums =1) Thanks. Casper -- View this message in context:

Hi, I am getting the same problem of divided by zero while decoding in the function multicomb(). I am using fixed point speex code. Can anybody please tell me the solution for it. -----Original Message----- From: speex-dev-bounces@xiph.org [mailto:speex-dev-bounces@xiph.org] On Behalf Of speex-dev-request@xiph.org Sent: Tuesday, March 13, 2007 12:30 AM To: speex-dev@xiph.org Subject: Speex-dev

Hi, Use ?split() #dat1 is the dataset: lst1<- split(dat1,dat1$BaseProd) lst1 #$`2231` ?# BaseProd? CF OSA #1???? 2231 0.5 0.7 #2???? 2231 0.8 0.6 #3???? 2231 0.4 0.8 # #$`2232` ?# BaseProd CF OSA #4???? 2232? 1?? 2 #5???? 2232? 3?? 1 # #$`2233` ?# BaseProd? CF OSA #6???? 2233 0.9 0.5 #7???? 2233 0.7 0.5 #8???? 2233 4.0 5.0 #9???? 2233 5.0 7.0 lst1[[1]] #? BaseProd? CF OSA #1???? 2231 0.5 0.7

Hi, I noticed that when dividing with signed 8-bit values the IR uses a 32-bit signed divide, however, when unsigned 8-bit values are used the IR uses an 8-bit unsigned divide. Why not use a 8-bit signed divide when using 8-bit signed values? Here is the C code and IR: char idiv8(char a, char b) { char c = a / b; return c; } define signext i8 @idiv8(i8 signext %a, i8 signext %b) nounwind

Hi, I have two dataframes one with 144 rows and 160 columns (SDF1) and one with 12 rows and 160 columns (SDF2). Now I'm trying to divide rows 1:12 with SDF2, rows 13:24 with SDF2, rows 25:36 with SDF 2, . In S-Plus the following code works fine: DFS = SDF1[1:144,1:60] / as.vector(SDF2[1:12,1:160]) but in R when I try to implement the formula I get the following error: "/

I am confused about why the following occurs: > version _ platform i386-pc-mingw32 arch i386 os mingw32 system i386, mingw32 status major 2 minor 4.0

R 2.1.1 Win 2k Would someone suggest a method (or methods) that can be used to determine ntile cutpoints of a vector, i.e. to determine values that can be used to divide a vector into thirds such as 0-33 centile, 34-66 centile, 67-100 centile. If for example I had a vector: 1,2,3,4,5,6,7,8,9 and wanted to divide the vector into thirds I would have cut-points of 3, and 6. Thanks, John John

Hi All, I have some data where I am doing fairly simple calculations, nothing more than adding, subtracting, multiplying and dividing. I’m running into a problem when I divide one variable by another and when they’re both 0 I get NaN. I realize that if you divide a non-zero by 0 then you get Inf, which is, of course, correct. But in my case I never get Inf, just NaN because of the structure

Hi, This is just to report about the "alignment check: 0000 [#1] SMP" kernel messages in one of my build system (domU) running Scientific Linux 6.1. I am compiling/rpm package for sbcl (http://sbcl.sourceforge.net/) in my build system (domU) and hit the following kernel messages although the domU in question still running and compilation still in progress. I have done some searching

What are the correct target description side effect flags for instructions which may trap (e.g. divide / remainder)? The divide instruction in my backend currently has no flags set. I've enabled the MachineLICM pass and it's causing a miscompilation by hoisting a divide by zero instruction out of the loop. Clearly this pass needs to be made aware that this is not safe. The current

Hi, if given the value of, say, 15000, I would like to be able to divide that value recursively by, say, 5, and to get a vector of a determined length, say 9, the last value being (set to) zero- i.e. like this: 15000 3000 600 120 24 4.8 0.96 0.192 0 These are in fact concentration values from an experiment. For my script, I get only the starting value (here 15000), and the factor by which

Currently it states in the language manual that the results of division by zero are undefined. However, I'm curious as to how you would normally handle either divide by zero or other "hardware" exceptions (null pointer dereference and so on) and turn them into LLVM exceptions. It seems to me that you would need some way to set up the unwind labels beforehand, just like you do

Hey Guys I want to divide(numerically) all the columns of a data frame by different numbers. Here is what I am doing but getting a weird error. The values in each column are not getting divided by the corresponding value in the denominator vector instead by the alternative values. I am sure I am messing up something. Appreciate your help -Abhi head(counts) WT_CON WT_RB MU_CON