search for: divid

Hi guys, I found the troblue and fix it! I attached the patch. The trouble was in the command reply buffer use. You compute the value that value = reply[6]*256+reply[5] <- it's wrong The right solution: value = reply[5] * 256 + reply[6]; And other bug, battery.runtime compute, you divide this value 60 <- it's wrong right value: divide 1.0 I continue the work on this driver,and I will write if I make a something new. I'm waiting for your reactions. -- Best Regards, Robert -------------- next part -------------- An HTML attachment was scrubbed... URL: <http://lis...

Under 4.6, we recompiled the kernel with HZ=100 for improved time-keeping in VMware guests. I've read about the backporting of the divider patch into RHEL/CentOS 4.7, but it sounds like it also comes with some bugs. I have been unable to determine the current status of the divider option in the latest 4.7 kernel update. I have experimented with "divider=10" and it works with no major problems, except that the guest clock d...

...in=myTitle1, axes=FALSE) axis(2, pos= mu - 3.6*sigma) axis(1, pos=0) lines(c(myx[1],myx[length(myx)]),c(0,0)) ### closes off axes addInteriorLine <- function(x, m, sd){ for (i in 1:(length(x))){ lines( c(x[i],x[i]), c(0, dnorm(x[i],m=m,sd=sd)), lty= 14, lwd=.2) } } dividers <- c(qnorm(0.025), -1, 0, 1, qnorm(0.975)) addInteriorLine(mu+sigma*dividers, mu,sigma) # bquote creates an expression that text plotters can use t1 <- bquote( mu== .(mu)) mtext(bquote( mu == .(mu)), 1, at=mu, line=-1) addInteriorLabel <- function(pos1, pos2, m, s){ ar...

Hi, I have a problem that I'm finding a bit tricky. I'm trying to use mapply and assign to generate curried functions. For example, if I have the function divide divide <- function(x, y) { x / y } And I want the end result to be functionally equivalent to: half <- function(x) divide(x, 2) third <- function(x) divide(x, 3) quarter <- function(x) divide(x, 4) But I want to do it using mapply and assign: mapply(assign, c("half&quo...

Dear r-help, Now I am drawing graphs with xyplot function. In order to place a legend under the plots I use the key argument in the xyplot function. One of the 'key' components is 'divide', which defines a number of points on the each line of the legend. The default is 3 points. I would like a single point, so I set divide = 1. Call to xyplot didn't produce any points at all. The body of draw.key function contains the following pointsGrob(x=(1:key$divide-1)/(ke...

libswfdec/swfdec_as_interpret.c | 1 + test/trace/Makefile.am | 3 +++ test/trace/crash-0.5.3-divide-by-zero.as | 5 +++++ test/trace/crash-0.5.3-divide-by-zero.swf |binary test/trace/crash-0.5.3-divide-by-zero.swf.trace | 1 + 5 files changed, 10 insertions(+) New commits: commit c6d96d7d47704ca3d62c08d35874c64f7878bdf2 Author: Benjamin Otte <otte at gnome.org> Date:...

Hey all, In my code, it seems that when I divide two integers, the result is an integer. Is there any way to make it such that when I divide two integers, the result is a double? Any help appreciated, Jin _______________________________________________ Rails mailing list Rails-1W37MKcQCpIf0INCOvqR/iCwEArCW2h5@public.gmane.org http://lists.ru...

Hi, I have a matrix, say m=matrix(c( 983,679,134, 383,416,84, 2892,2625,570 ),nrow=3 ) i can find its row/col sum by rowSums(m) colSums(m) How do I divide each row/column by its rowSum/colSums and still return in the matrix form? (i.e. the new rowSums/colSums =1) Thanks. Casper -- View this message in context: http://r.789695.n4.nabble.com/how-to-divide-each-column-in-a-matrix-by-its-colSums-tp3062739p3062739.html Sent from the R help mailing li...

Hi, I am getting the same problem of divided by zero while decoding in the function multicomb(). I am using fixed point speex code. Can anybody please tell me the solution for it. -----Original Message----- From: speex-dev-bounces@xiph.org [mailto:speex-dev-bounces@xiph.org] On Behalf Of speex-dev-request@xiph.org Sent: Tuesday, March 13,...

...llowing form BaseProd ?CF ?OSA 2231 ? ? ? ? ? ?0.5 ? 0.7 2231 ? ? ? ? ? ?0.8 ? 0.6 2231 ? ? ? ? ? ?0.4 ? 0.8 2232 ? ? ? ? ? ?1 ? ? ? ?2 2232 ? ? ? ? ? ?3 ? ? ? ? 1 2233 ? ? ? ? ? ?0.9 ? ? 0.5 2233 ? ? ? ? ? ?0.7 ? ?0.5 2233 ? ? ? ? ? 4 ? ? ? ? ? 5 2233 ? ? ? ? ? 5 ? ? ? ? ? 7 I want to divide the data so that the data get divided on the basis of base product. like: data1 BaseProd ?CF ?OSA 2231 ? ? ? ? ? ?0.5 ? 0.7 2231 ? ? ? ? ? ?0.8 ? 0.6 2231 ? ? ? ? ? ?0.4 ? 0.8 data2 BaseProd ?CF ?OSA 2232 ? ? ? ? ? ?1 ? ? ? ?2 2232 ? ? ? ? ? ?3 ? ? ? ? 1 data3 BaseProd ?CF ?OSA 223...

Hi, I noticed that when dividing with signed 8-bit values the IR uses a 32-bit signed divide, however, when unsigned 8-bit values are used the IR uses an 8-bit unsigned divide. Why not use a 8-bit signed divide when using 8-bit signed values? Here is the C code and IR: char idiv8(char a, char b) { char c = a / b; return c...

Hi, I have two dataframes one with 144 rows and 160 columns (SDF1) and one with 12 rows and 160 columns (SDF2). Now I'm trying to divide rows 1:12 with SDF2, rows 13:24 with SDF2, rows 25:36 with SDF 2, . In S-Plus the following code works fine: DFS = SDF1[1:144,1:60] / as.vector(SDF2[1:12,1:160]) but in R when I try to implement the formula I get the following error: "/ only defined for equally-sized data frames&qu...

...rev 39566 language R version.string R version 2.4.0 (2006-10-03) > 1 %/% 0.1 [1] 9 > 10 %/% 1 [1] 10 > This effect led me into an trap when I tried to classify a set of proportions based on the first decimal place by integer dividing by 0.1. Can someone explain why this behavior occurs and give me an insight into how to predict it? Thanks, -- Jeff

R 2.1.1 Win 2k Would someone suggest a method (or methods) that can be used to determine ntile cutpoints of a vector, i.e. to determine values that can be used to divide a vector into thirds such as 0-33 centile, 34-66 centile, 67-100 centile. If for example I had a vector: 1,2,3,4,5,6,7,8,9 and wanted to divide the vector into thirds I would have cut-points of 3, and 6. Thanks, John John Sorkin M.D., Ph.D. Chief, Biostatistics and Informatics Baltimore VA Medic...

Hi All, I have some data where I am doing fairly simple calculations, nothing more than adding, subtracting, multiplying and dividing. I’m running into a problem when I divide one variable by another and when they’re both 0 I get NaN. I realize that if you divide a non-zero by 0 then you get Inf, which is, of course, correct. But in my case I never get Inf, just NaN because of the structure of my dataset. Here’s a dumb...

...e.com/Alignment-check-on-domU-2-6-32-td2549903.html http://xen.1045712.n5.nabble.com/Kernel-panic-with-2-6-32-30-under-network-activity-td3423149.html Kernel messages: derefnull[15862]: segfault at 0 ip 000000000804c2eb sp 00000000ffb4dfac error 4 in derefnull[8048000+57000] divbyzero[15899] trap divide error ip:804d0be sp:ff849e9c error:0 in divbyzero[8048000+56000] derefnull[7328]: segfault at 0 ip 0000000000407701 sp 00007fff943b1c60 error 4 in derefnull[400000+77000] divbyzero[7345] trap divide error ip:408d05 sp:7fff35784750 error:0 in divbyzero[400000+76000] derefnull[32738]: segfault at 0...

What are the correct target description side effect flags for instructions which may trap (e.g. divide / remainder)? The divide instruction in my backend currently has no flags set. I've enabled the MachineLICM pass and it's causing a miscompilation by hoisting a divide by zero instruction out of the loop. Clearly this pass needs to be made aware that this is not safe. The current test...

Hi, if given the value of, say, 15000, I would like to be able to divide that value recursively by, say, 5, and to get a vector of a determined length, say 9, the last value being (set to) zero- i.e. like this: 15000 3000 600 120 24 4.8 0.96 0.192 0 These are in fact concentration values from an experiment. For my script, I get only the starting value (here 15000), a...

Currently it states in the language manual that the results of division by zero are undefined. However, I'm curious as to how you would normally handle either divide by zero or other "hardware" exceptions (null pointer dereference and so on) and turn them into LLVM exceptions. It seems to me that you would need some way to set up the unwind labels beforehand, just like you do for the invoke instruction. For the specific case of divide by zero, I...

Hey Guys I want to divide(numerically) all the columns of a data frame by different numbers. Here is what I am doing but getting a weird error. The values in each column are not getting divided by the corresponding value in the denominator vector instead by the alternative values. I am sure I am messing up something. App...