Displaying 3 results from an estimated 3 matches for "dipa".
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dia
2007 Jan 21
2
efficient code. how to reduce running time?
...ut.3932.100"))
#print (snp);
# pi: desired proportion of variation due to QTN
pi = 0.05;
print (paste("pi:", pi));
MAF = 0.05;
print (paste("MAF:", MAF));
# S: number of segregating sites
S = length(snp[1,]);
# N: number of samples
N = length(snp[,1]);
Dips = sample(1:N,N)
DipA = Dips[1:50]
DipB = Dips[51:100]
disnp = snp[DipA,]+snp[DipB,]
snp = as.data.frame(disnp, row.names=NULL);
N = length(snp[,1]);
# get allele freq for all SNPs
allele_f <- mean(snp[,1:S])/2;
print (allele_f);
sites = rfind(allele_f);
print(sites);
# collapse sites that have perfect correlation...
2010 Jun 07
2
mgcv
Hello Sir,
I am using mgcv package for my data.
My model is y~x1+f(x2),I want to find out the function f(x2) .
Following is the code.
sm1=gam(y~x1+s(x2),family=binomial, f)
summary(sm1)
plot(sm1,residuals=TRUE, xlab="AGE",pch=20)
In this plot I am getting S(x2,1.93) on y axixs
How should I get the function for x2 from this plot.or Is there anyother procedure in R to get this
2010 Jul 12
1
ed50
I am using semiparametric Model
library(mgcv)
sm1=gam(y~x1+s(x2),family=binomial, f)
How should I find out standard error for ed50 for the above model
ED50 =( -sm1$coef[1]-f(x2)) / sm1$coef [2]
f(x2) is estimated value for non parametric term.
Thanks
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