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I've read that LLVM can convert from C++ to C code. So I've used it in such a way: I'm Windows-user so I used MinGW. I employed this file as the test: llvm-hello.cpp: #include <iostream> int main(int argc, char* argv[]) { system("pause"); return 0; } result of "llvm-g++ C:\llvm_hello.cpp -o C:\llvm_hellopp.exe" worked just fine. as a result of

On Sep 29, 2009, at 9:37 AM, dilas dilas wrote: > I've read that LLVM can convert from C++ to C code. It does, but it does not supply a C++ library. You'll need to do that. > So I've used it in such a way: > I'm Windows-user so I used MinGW. > I employed this file as the test: > > llvm-hell...

...lues by using this formula: weight$v6 <-(weight1*AS)+(weight2*BL)+(weight3*Serdang)+(weight4*Jhr)+(weight5*Phg); Targetstation but I still could not replace the NA's. My problem is, how do I replace those NA's with another value? Thank you so much for your help and attention. Regards, Dila [[alternative HTML version deleted]]

hello, I try to run simulation of levene's test to find the p-value but the error of replacement has length zero occur, could anyone help me to fix this problem? asim <- 1000 pv<-rep(NA,asim) for(i in 1:asim) {print(i) set.seed(i) g1 <- rnorm(20,0,2) g2 <- rnorm(20,0,2) g3 <- rnorm(20,0,2) x <- c(g1,g2,g3) group<-as.factor(c(rep(1,20),rep(2,20),rep(3,20))) library(Rcmdr)

Hi All, I bought a DID number from VOxbone...this number could be dialed from any PSTN line and could be forwarded to any SIP server like asterisk server...Now I need to forward this number to my asterisk server so when a customer dial this number from his GSM or Land line PSTN number the call will be forwarde to my asterisk server and I need to play a wav file for example.. Can you please give me

How to compile the libstdc++ library to LLVM bitcode?

Hi, I run this code to get the power of the test for modified bartlett's test..but I'm not really sure that my coding is right.. #normal distribution unequal variance asim<-5000 pv<-rep(NA,asim) for(i in 1:asim) {print(i) set.seed(i) n1<-20 n2<-20 n3<-20 mu<-0 sd1<-sqrt(25) sd2<-sqrt(50) sd3<-sqrt(100) g1<-rnorm(n1,mu,sd1) g2<-rnorm(n2,mu,sd2)