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Hi I am trying to create a function that is able to calculate this sum: a<-c(2,3,5) b<-(8,7) with "a" meaning 235 and "b" 87. So the result of this sum would be 235 + 87 = 322. I've searched a function like strsplit but that worked for integers and in reverse - not spliting but combining. Can you give me a hand on this please? thanks AD -- View this message in

Hi Suppose we have an object with strings: A<-c("a","b","c","d") Now I do: B<-matrix(A,4,4, byrow=F) and I get a a a a b b b b c c c c d d d d But what I really want is: a b c d b c d a c d a b d a b c How can I do this? thank you A. Dias -- View this message in context:

Hi, I am having a problem in doing something similar to this example: Suppose I have this vector a, and from it I wish to create 5 other vector each one with less one value than what object a has So I have "a" a<-c(1,2,3,4,5) and I want a1 that shoud have (2,3,4,5) a2 that should have (1,3,4,5) a3 that should have (1,2,4,5) a4 that should have (1,2,3,5) a5 that should have

Hi, I am with a problem on how to do a comparison of values. My script is as follows: repeat{ cat("How many teams to use? (to end write 0) ") nro<-scan(n=1) if(nro==0)break cat("write the", nro, "teams names \n") teams<-readLines(n=nro) if (teams[1]==teams[2)next else print(teams) } On this example I only compare teams 1 name with teams 2 name, and if they

Hi, as an example I have made this script to give the user the answer if a number is odd or even: { cat("Please, enter a number (Zero ends)") n<-scan(n=1) if(n==0)break i<-("The number is odd") p<-("The number is even") if (n%%2==0) p else i } If you run this script it will only work once, I mean, after it gives you the answer is won't ask for

Hi, I have this character vector: A<-c("Tell me how many different letter this vector has?") Is there a way with R that it can let me know how many different letters I have on this vector? If I use nchar(A) que gives me the number 50. With this function he is counting all the letters present and also spaces between the words. Can we also not count the spaces between words? Then

Hi, I am using code below to get a plot that will show me on the X axis the number of clusters and on the Y axis the cluster average widths. However I am getting this error: Error in summary(silhouette(cutree(d, x), dist(iris[, -5])))$si.summary : $ operator is invalid for atomic vectors the code I am using is: avgs<-sapply(1:20,function(x) summary(silhouette(cutree(d,x),

Hi I have this function and this matrix: function(x,y) x+y/x m<-matrix(c(1,2,4,2,10,8),3,2) > m [,1] [,2] [1,] 1 2 [2,] 2 10 [3,] 4 8 each row represent a point (x,y) in a chart and I want via my fucntion to calculate the image in order to get this results: for point (1,2) I would get 1+2/1 = 3 for point (2,10) I would get 2+10/2 = 7 for point (4,8) I would get

Hi Suppose you have the code below. The result I get from the cat function is from the avgs object. Now, I have 30 diferent objects like this and I wish to make a summary table, something like: Avgs1 Avgs2 Avgs3 i= 2 average= 0.515983i i= 2 average= 0.746983 i= 2 average= 0.2665983 i= 3 average=