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...g dplyr and the group_by approach on a dataframe, I want to be able to apply a specific action according to the group name. The code bellow works, but I am not able to write it in a more esthetic way using dplyr. Can somebody help me to find a better solution ? Thank you Best regards Laurent df_test <- data.frame( x1=1:9, x2=1:9, gr=rep(paste0("gr",1:3),each=3)) df_test? <-? df_test %>% dplyr::group_by(gr) %>% ? group_modify(.f=function(.x,.y){ ??? print(paste0("Nom du groupe : ",.y[["gr"]])) ??? switch(as.character(.y[["gr"]]) ??????????...

...functions get sufficiently complicated or numerous, it may be useful to store them in a named list and use the names to call them in some sort of loop. Here I have just used your anonymous functions in the list, but of course you could have used already existing functions instead. ## your example df_test <- data.frame( x1=1:9, x2=1:9, gr=rep(paste0("gr",1:3),each=3)) ## function list with the relevant names funcs <- list(gr1 = \(x)x+1, gr2 = \(x)0, gr3 = \(x)x+2) ## Alternatively you could do this if you had many different functions: ## funcs <- list(\(x)x+1, \(x)0, \(x)x+2) ##...

...functions get sufficiently complicated or numerous, it may be useful to store them in a named list and use the names to call them in some sort of loop. Here I have just used your anonymous functions in the list, but of course you could have used already existing functions instead. ## your example df_test <- data.frame( x1=1:9, x2=1:9, gr=rep(paste0("gr",1:3),each=3)) ## function list with the relevant names funcs <- list(gr1 = \(x)x+1, gr2 = \(x)0, gr3 = \(x)x+2) ## Alternatively you could do this if you had many different functions: ## funcs <- list(\(x)x+1, \(x)0, \(x)x+2) ##...