Displaying 3 results from an estimated 3 matches for "df6".
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2010 Nov 11
4
How to get a specific named element in a nested list
Hello,
I have a nested named list structure, like the following:
x <- list(
list(
list(df1,df2)
list(df3,
list(df4,df5))
list(df6,df7)))
with df1...d7 as data frames. Every data frame is named.
Is there a way to get a specific named element in x?
so, for example,
x[[c("df5")]] gives me the data frame 5?
Thank you in advance!
Best,
Friedericksen
2007 Sep 27
2
create data frame(s) from a list with different numbers of rows
...one" in very
clunky fashion.
# here is an example of my code
sample.df1 <-data.frame(list.sample[[1]])
sample.df2 <-data.frame(list.sample[[2]])
sample.df3 <-data.frame(list.sample[[3]])
sample.df4 <-data.frame(list.sample[[4]])
sample.df5 <-data.frame(list.sample[[5]])
sample.df6 <-data.frame(list.sample[[6]])
sample.df1
sample.df2
sample.df3
sample.df4
sample.df5
sample.df6
# In the future i will have up to 1,200 of these small dataframes to create.
# is there a way to loop through the list and create many small data
frames??
# or perhaps make each of the list eleme...
2010 Jan 20
1
Reshaping data with xtabs giving me 'extra' data
...es[2], Show = shows, Score = 1:3)
> df3 <- data.frame(Date = dates[1], Time = times[4], Show = shows, Score = 1:3)
> df4 <- data.frame(Date = dates[2], Time = times[1], Show = shows, Score = 1:3)
> df5 <- data.frame(Date = dates[2], Time = times[2], Show = shows, Score = 1:3)
> df6 <- data.frame(Date = dates[2], Time = times[3], Show = shows, Score = 1:3)
> df7 <- data.frame(Date = dates[2], Time = times[4], Show = shows, Score = 1:3)
> df7
Date Time Show Score
1 2010-01-20 15:30:00 Red Dwarf 1
2 2010-01-20 15:30:00 Being Human 2
3 201...