search for: df5

Hello, I have a nested named list structure, like the following: x <- list( list( list(df1,df2) list(df3, list(df4,df5)) list(df6,df7))) with df1...d7 as data frames. Every data frame is named. Is there a way to get a specific named element in x? so, for example, x[[c("df5")]] gives me the data frame 5? Thank you in advance! Best, Friedericksen

...orm(40, 5, 2); var4 <- rnorm(40, 10, 3); var5 <- rnorm(40, 15, 8) # just example df <- data.frame(clvar, yvar, var1, var2, var3, var4, var5) # manual splitting df1 <- subset(df, clvar == 1) df2 <- subset(df, clvar == 2) df3<- subset(df, clvar == 3) df4<- subset(df, clvar == 4) df5<- subset(df, clvar == 5) # i tried to mechanize it * for(i in 1:5) { df[i] <- subset(df, clvar == i) } I know it should not work as df[i] is single variable, do it did. But I could not find away to output multiple dataframes from this loop. My limited R knowledge, did not help...

...mplexes <- (-1:2)+3i > df4 <- data.frame(a=fourLogicals, d=fourComplexes, b=fourInts, c=fourDoubles) > storage.mode(as.matrix(df4)) [1] "complex" If one column is of mode character, then 'as.matrix' will effectively return a character matrix: > df5 <- data.frame(toto=c("a","bb"), titi=c(9,999)) > storage.mode(as.matrix(df5)) [1] "character" Note that the doc says that "any non-numeric/complex column" will be passed thru 'format' which seems to be exactly the other way around:...

...can figure out how to do this is "one by one" in very clunky fashion. # here is an example of my code sample.df1 <-data.frame(list.sample[[1]]) sample.df2 <-data.frame(list.sample[[2]]) sample.df3 <-data.frame(list.sample[[3]]) sample.df4 <-data.frame(list.sample[[4]]) sample.df5 <-data.frame(list.sample[[5]]) sample.df6 <-data.frame(list.sample[[6]]) sample.df1 sample.df2 sample.df3 sample.df4 sample.df5 sample.df6 # In the future i will have up to 1,200 of these small dataframes to create. # is there a way to loop through the list and create many small data frame...

...es[1], Show = shows, Score = 1:3) > df2 <- data.frame(Date = dates[1], Time = times[2], Show = shows, Score = 1:3) > df3 <- data.frame(Date = dates[1], Time = times[4], Show = shows, Score = 1:3) > df4 <- data.frame(Date = dates[2], Time = times[1], Show = shows, Score = 1:3) > df5 <- data.frame(Date = dates[2], Time = times[2], Show = shows, Score = 1:3) > df6 <- data.frame(Date = dates[2], Time = times[3], Show = shows, Score = 1:3) > df7 <- data.frame(Date = dates[2], Time = times[4], Show = shows, Score = 1:3) > df7 Date Time Show Scor...

This error occurs because the "==" comparison operator doesn't allow comparison of ordered and normal factors: /df[df5$close_quarter == as.Date("2011-02-01"),]/ Warning message: In /`[.data.frame`(df, df$close_quarter == as.Date("2011-02-01")/, : Incompatible methods ("Ops.ordered", "Ops.Date") for "==" Why should this be a problem -- Isn't this being overly...

I have a dataset like this (dput for this below) which represents user computer sessions: username machine start end 1 user1 D5599.domain.com 2011-01-03 09:44:18 2011-01-03 09:47:27 2 user1 D5599.domain.com 2011-01-03 09:46:29 2011-01-03 10:09:16 3 user1 D5599.domain.com 2011-01-03 14:07:36 2011-01-03 14:56:17 4 user1 D5599.domain.com

I am trying to use the value of an ID variable in an if statement and not getting the results I expected. # ID values for two school districts > with(rf, tapply(DistrictID, DistrictName, min) ) Aberdeen School Dist. # 58 Buhl Joint School District 59340 53409 This creates DNAME as I expected ...

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...e(cbind(x=3D1, y=3D1:1000), fac=3Dsample(LETTERS[1:3], = 1000, repl=3DTRUE)) df2 <- data.frame(cbind(x=3D1, y=3D1:10), fac=3Dsample(LETTERS[4:6], = 10, repl=3DTRUE)) df3 <- data.frame(cbind(x=3D1, y=3D1:1000000), = fac=3Dsample(LETTERS[1:3], 1000000, repl=3DTRUE)) df4 <- rbind(df1,df2) df5 <- rbind(df2,df3) =20 =20 Since this only happens intermittantly and appears to be related to the = size of the objects I ran the following code. sink("rbind test.txt") df1 <- data.frame(cbind(x=3D1, y=3D1:10), fac=3Dsample(LETTERS[4:6], 10, = repl=3DTRUE)) for (j in seq(100000,100...

I have a series of data frames that are identical structurally, i.e. - made with the same code, but I need to add them together so that they become one, longer, data frame, i.e. - each of the slot vectors are increased in length by the length of the added data frame vectors. So if I have df1 with a slot A so that length(df1$A) = 100 and I have df2 with a slot A so that length(df2$A)=200 then I

I am trying to create a frequency distribution and I am a bit confused. Here are the commands I have entered: > data <- read.csv(file="40609_sortedfinal.csv",head=TRUE,sep=",") > NumberOfActionsByStatus = data$STATUS > NumberOfActionsByUser = data$ETS_LOGIN > NumberOfBidOffer = data$BID_OFFER > NumberOfActionsByUser.freq = table(NumberOfActionsByUser) >

Hello list. I'm trying to rebuild the 2.6.9.67.0.20.EL kernel, but it fails even without modifications. How did I try it? Created a (non-root) build environment (not a mock ) Installed the kernel.scr.rpm and did a rpmbuild -ba --target=`uname -m` kernel-2.6.spec 2> prep-err.log | tee prep-out.log The build failed at the end: Processing files: kernel-xenU-devel-2.6.9-67.0.20.EL Checking