search for: devoe

Sto imparando ora ad utilizzare R. Ho un problema: devo caricare i dati da un file xls creato da me, utilizzando la funzione "read.xls" produce il seguente errore: Errore in xls2csv(xls, sheet, verbose = verbose, ..., perl = perl) : Unable to read xls file 'indagineUSA.xls'. Errore in file.exists(tfn) : argomento 'file' non valido Cosa c'è che non va? La directory

Hi, I am neither a statistician nor a user of R. I am a programmer trying to provide my users (both statisticians and R users) data in a format that works best for them. What is a data frame? Is source data easier to work with in this format or a csv file? Or yet another format? Thanks for your time. Bruce [[alternative HTML version deleted]]

I am not a pure Statistics background and therefore please forgive me if this question (which is not R related either) is too trivial. In many Statistics literature I find following statement: "restrictions in different coefficients matrices have to be imposed to ensure uniqueness of the parametrization". Can somebody tell me what is the meaning of Uniqueness in the parametrization?

Any advice on which package I can use for calculating effect sizes for two dependent samples? compute.es seems only to consider independent samples. Thanks in advance Steve Powell [[alternative HTML version deleted]]

Hi, everybody, I just want to pass arguments to a function as below: range <- c(0.1, 0.5) runif(1, range) But it doesn?t work. Does anyone have any suggestions to offer? Thanks. Lisa -- View this message in context: http://r.789695.n4.nabble.com/Arguments-of-a-function-tp3387643p3387643.html Sent from the R help mailing list archive at Nabble.com.

? o J2RE pegue o rpm. teste c/ essa aplica??o: BuddySpace (? algo como o Gaim ou Jabber) Na p?gina dessa aplica??o tem o link certinho pra pegar o Java. buddyspace.sourceforge.net Eduardo Ukstin wrote: >Boa tarde lista, > >Algu?m poderia me dar uma sugest?o de ferramenta gr?fica para >trabalhar com java no linux? > >Aproveitando, ainda n?o consegui instalar o java na minha

siamo a venerd?, anche questa settimana ? passata e devo ammettere che questo pensiero mi fa stare molto bene visto che da oggi fino a luned? passer? sicuramente dei giorni stupendi e lascier? dietro quelli appena passati che devo essere sincera mi hanno fatto girare parecchio le palle..tra lavoro e universit? poche notizie buone purtroppo....quello che mi salva sempre ? che porto una gran luce

Bom dia eu chamo-me Ana, estou a tentar fazer matriz de correla??o e covariancia para comparar 4 variaveis e saber quais s?o as mehores... fiz o segundo codigo mas devo tar a fazer alguma confus?o para nao me aparecer o output correcto: cor(dados[,2:5],method=c("pearson")) cor_with_p_test(dados[2:5]) ct <- cor.test(dados[,2:5]) ct$p ct$v #matriz de covariancias cov(dados[,2:5],

Hi all, I am new user in R, I am trying to to use paste function to concatenate strings which has been fetched from database table(postgres database), the following are my code: when i do: > sqlFetch(channel,'transactions') outputs are following(only parts, there are around 200 transactions in total) orderid productname price quantity discount 1 T10248 potato 1.80

Thanks Bill. Do you and others think that a link to this guide (or another)should be included in the Posting Guide and/or R FAQ? -- Bert On Tue, May 17, 2011 at 4:07 PM, <Bill.Venables at csiro.au> wrote: > Amen to all of that, Bert. ?Nicely put. ?The google style guide (not perfect, but a thoughtful contribution on these kinds of issues, has avoiding attach() as its very first line.

Hi, I have a dataset that has 2 groups of samples. For each sample, then response measured is the number of success (no.success) obatined with the number of trials (no.trials). So a porportion of success (prpop.success) can be computed as no.success/no.trials. Now the objective is to test if there is a statistical significant difference in the proportion of success between the 2 groups of

Hi, let's say I have a simple ANOVA model with 2 factors A (level A1 and A2) and B (level B1 and B2) and their interaction: aov(y~A*B, data=dat) It turns out that the interaction term is not significant (e.g. P value = 0.2), but if I used glht() to compare A1 vs. A2 within each level of B, I found that the comparison is not significant when B=B1, but is very significant (P<0.01) when

...me code that, oh i don't know, broke the oplock on last used files or something. if foxpro has several file handles open you may run into this one, i don't know. try "FILES = 90" in config.sys, see what happens. complete guess-work, mind you... luke On Thu, 28 May 1998, Jiva DeVoe wrote: > Today, a coworker of mine and I had a bit of a debate, and I was hoping > someone here could resolve the question. (Incidentally, Microsoft didn't > seem able to grasp what I was asking when I called them on this) Originally > the question came up out of a discussion abo...

Hi list. I'm trying to plot a graph "by" factors. Exactly, the x axis are my depths (as.factor), my left y axis are my transects (also as.factor) and I want to plot the mean and standard deviation (three samples per factor combination) of my SW (numeric) variable. The second y axis (at the right) will, probably, need to be displayed several times (for both left y axis

Hi all, I added the following line on the "Renviron.site" file: R_LIBS=C:\Program Files (x86)\R\library And when I start R and run: .libPaths() I don't see this path. On windows XP it worked for me. I am now using windoes 7 (64 bit) with R 32. Is there a reason this shouldn't work? Thanks, Tal ----------------Contact

Hi, I have a data.frame that has a categorical variable, for which I would like to look at the distribution of levels of this variable, based on a grouping of two other variables. As an example: x <- data.frame(obs=sample(c('low', 'high'),100, replace=TRUE), grp1=sample(1:10, 100, replace=TRUE), grp2=runif(100)) cut.grp1 <- cut(x$grp1, 3) cut.grp2 <- cut(x$grp2, 3)

Hi R experts I am just wondering if something is already available (or easily adaptable) to do the following. I am planning to build linear models for all possible combinations of terms, so for example if the terms are sent into a function as this string " X1 + X2 + X3 + X4 + X1:X2" I would want to build models for all possible combinations of these 5 terms, e.g. m1 <- lm( y ~

I have a dataset where I have missing times (11:00 and 16:00). I would like the outputs to include the missing time so that the final time vector looks like "realt" and has the previous time's value. Ex. If meas at time 15:30 is 0.45, then the meas for time 16:00 will also be 0.45. meas are the measurements and times are the times at which they were taken. meas<-runif(18)

I am a beginner in R, so please don't step on me if this is too simple. I have two data sets datax and datay for which I created a qqplot qqplot(datax,datay) but now I want a line that indicates the perfect match so that I can see how much the plot diverts from the ideal. This ideal however is not normal, so I think qqnorm and qqline cannot be applied. Perhaps you can help? Ralf

Colleagues Assume that I have a vector containing some text strings, some of which contain a particular character. I could like to apply "toupper" to the text before the character. For example (in this case, "|" is the particular character): ORIGINAL: TEXT <- c("aaaa", "bbb|cc", "|ddd") AFTER APPLICATION OF toupper: TEXT <-