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Greetings ... I hope somebody can explain this to me, or give me a help to fix this problem ... On my Samba server ( 3.0.2rc2 ) I am getting ... Feb 9 17:31:21 eastrand smbd[2113]: [2004/02/09 17:31:21, 0] rpc_server/srv_pipe.c:api_pipe_netsec_process(1371) Feb 9 17:31:21 eastrand smbd[2113]: failed to decode PDU Feb 9 17:31:21 eastrand smbd[2113]: [2004/02/09 17:31:21, 0]

Hi all, There are some surprises when trying to connect Windows 10 (up to date circa Dec 2016) to Samba (4.5.2) with 'smb encrypt = desired' as a config option. I've made a grid of some of the combinations 'smb encrypt = desired' settings below. The biggest surprise is that if 'smb encrypt = desired' is set globally and in the share, Windows 10 cannot connect at all, but if 'smb encrypt = required'...

Always... Desire that in the New Year that if you really initiate... It hears the words that always it desired to hear. It pronounces the phrases that one day it desired to repeat. It feels the emotion that always waited to feel. It walks for the tracks that one day it desired to follow. It divides the affection with who always desired to distribute. It hugs all the friends whom always it desired to congreg...

...problem, here is a deconstructed version of what I did to each column, for easier parsing: ----------------------------- begin call to 'apply' ------------------------ Step 1: Identify several disjoint subsequences of fixed length, say length three, of a column. column.values <- 1:16 desired.subseqs <- c( NA, NA, NA, 1, 1, 1, NA, 1, 1, 1, NA, NA, 1,1,1, NA ) # this vector is used for every column. desired.values <- desired.subseq * column.values Step 2: Find the average value of each subsequence. desired.means <- rollapply( desired.values, 3, mean, fill=NA, align = "...

On Fri, Dec 23, 2016 at 02:21:16PM -0600, Chad William Seys via samba wrote: > Hi all, > > There are some surprises when trying to connect Windows 10 (up to date circa > Dec 2016) to Samba (4.5.2) with 'smb encrypt = desired' as a config option. > > I've made a grid of some of the combinations 'smb encrypt = desired' > settings below. > > The biggest surprise is that if 'smb encrypt = desired' is set globally and > in the share, Windows 10 cannot connect at all, but if 's...

On Fri, Dec 23, 2016 at 02:21:16PM -0600, Chad William Seys via samba wrote: > There are some surprises when trying to connect Windows 10 (up to date circa > Dec 2016) to Samba (4.5.2) with 'smb encrypt = desired' as a config option. > > ... > > browse | select | direct > smb encrypt (no G, no S) = '' Y | Y | Y > smb encrypt (G, no S) = required Y[0] | Y | Y > smb encrypt (no G, S) = desired Y[4] | N[1] |...

...the number of 3rd dimension levels of the array. Rows will be the same for both. For this example lets say the array will have 2 columns, but that's not fixed. dim(arr)<-c(dim(mat)[1],2,dim(mat)[2]) I wish to repeat each matrix column in the 3rd dimension of an array as follows in "desired appearance" below, but haven't quite got my generic array() function right. I need the equivalent of byrow=TRUE when filling in the array. thanks for all your help! mat<-matrix(1:12,ncol=3) mat desired.arr<-array(NA,dim=c(dim(mat)[1],2,dim(mat)[2])) #build array using generic cod...

...ne or two letters) is always followed by a set of digits (one or two digits), possibly with one or more spaces between the sets of letters and digits. A set of letters always belongs to the following set of digits and I want to parse the strings into these groups. As an example, the strings and the desired parsing results could look like this: A10B10, desired parsing result: A10 and B10 A10 B5, desired parsing result: A10 and B5 AB 10 CD 12, desired parsing result: AB10 and CD12 A10CD2EF3, desired parsing result: A10, CD2, and EF3 I assume that it is possible to search a string for letter...

I have a large list of matrices and a vector that identifies the desired matrices that I would like to rbind. However, I am stuck on how to get this to work. I have written some code below to illustrate my problem: # 3 simple matrices a<-matrix(1:9,3,3) b<-matrix(10:18,3,3) c<-matrix(19:27,3,3) #this is the type of list of matrices I am dealing with matrix....

...rs. I would now like to add a fourth column to df which labels each row according to whether it was unique combination 1,2,3 or 4: x1=c(rep(0:1,6)) x2=c(rep(c(1,1,0,0)6)) x3=c(rep(1,6),rep(0,6)) df=data.frame(x1,x2,x3) tabledf=as.data.frame(with(df, table(x1,x2,x3))) res=c(3,4,3,4,3,4,1,2,1,2,1,2) desired=data.frame(x1,x2,x3,res) df tabledf desired I realise that this is probably quite simple to do, I am just struggling to get my head around it! Help much appreciated in advance. Cheers, Simon -------------------------------- Simon O'Hanlon BSc, MSc Department of Infectious Disease Epidemiol...

I have a list that looks like this ... > have <- list(a=7,b=3,c=1) > have $a [1] 7 $b [1] 3 $c [1] 1 and I want to have a simple way to change it to the following without re-typing the values ... > desire <- list(a=c(7,7),b=c(3,3),c=c(1,1)) > desire $a [1] 7 7 $b [1] 3 3 $c [1] 1 1 In other words, I need to create the list in desire from the list in have. In my

Thank you and sorry for the confusion. The desired result should have 8 variables as a comma separated in each line. The string variable is considered as one variable. The output of your script is wfine for me. Thank you! On Fri, Jul 19, 2024 at 1:00?PM Ebert,Timothy Aaron <tebert at ufl.edu> wrote: > > The desired result is odd. &...

The desired result is odd. 1) It looks like the string is duplicated in the desired result. The first line of data has "15, xc, Ab", and the desired result has "15, xc, Ab, 15, xc, Ab" 2) The example has S1 through S5, but the desired result has data for eight variables in the first line (...

Dear R Users, I apology for not being able to provide an adequately informative subject. Let me describe my problem with an example. For a matrix * (mat <- matrix(c(1,1,2,2,2,3,3, 5,9,1,3,7,4,8), ncol = 2))* my desired output is * (desired <- matrix(c(1,2,3, 5,1,4), ncol = 2))* That is, the first column is numerically grouped and only the first item in each group is wanted. The second column is in increasing order within each group. My actual data will be of size 10^6 by 100 so I am hoping to solve this...

The contrast and desirability packages are available for all platforms at cran.r-project.org (and coming soon to a mirror near you). The contrast package extends Frank Harrell's contrast.Design function for one degree of freedom contrasts of model parameters to other types of models, such as lm, glm, lme, gls and geese models. Fold-changes are also calculated for all contrasts. There is a

The contrast and desirability packages are available for all platforms at cran.r-project.org (and coming soon to a mirror near you). The contrast package extends Frank Harrell's contrast.Design function for one degree of freedom contrasts of model parameters to other types of models, such as lm, glm, lme, gls and geese models. Fold-changes are also calculated for all contrasts. There is a

hi, I seek to be able itself to wish a desire box our listeners am to music, over ices am played have someone a recommendation for me? can be gladly with mysql. greeting -- Mit freundlichen Gr?ssen Carsten Henkel mailto:carsten@chatlabel.de In unserer Firma ist alles elektrisch - sogar das Gehalt versetzt einem einen Schlag. dieser Text ist zuf?llig gew?hlt und

...1 2 [14,] 1 2 2 [15,] 0 3 2 [16,] 2 0 3 [17,] 1 1 3 [18,] 0 2 3 [19,] 1 0 4 [20,] 0 1 4 [21,] 0 0 5 (thus each row corresponds to a point in my sample space). Now what I need to do is to construct a new matrix, which uses the 'observation' matrix above, which is a sort of table: > desired y1 y2 y3 d [1,] 5 0 0 0 [2,] 4 1 0 1 [3,] 3 2 0 0 [4,] 2 3 0 0 [5,] 1 4 0 2 [6,] 0 5 0 1 [7,] 4 0 1 0 [8,] 3 1 1 0 [9,] 2 2 1 0 [10,] 1 3 1 0 [11,] 0 4 1 0 [12,] 3 0 2 0 [13,] 2 1 2 0 [14,] 1 2 2 0 [15,] 0 3 2 0 [16,] 2 0 3 2 [17,] 1 1 3 0 [18,] 0 2 3 0 [19,] 1 0 4 0 [20,] 0 1 4 1 [...

Hi: I've been hired to provide, among other things, internet coverage for a convention in 2 weeks. I have two feature requests, one highly desired and one moderately desired. My moderately desired feature has been mentioned before - server-side recording of the stream. As in the cases mentioned previously, I'd like to be able to repeat segments without having to upload them first. Since I'll be using a modem on site, I'd have t...

...amiliar with regular expressions and escaping. I need to replace the %-signs in a character vector with elements as "income 0%-33%# to be replaced by "income 0\%-33\%" (for later use in LaTeX). Using gsub("%","\\%","income 0%-33%") does not give the desired result. However, gsub("%","\\\\%","income 0%-33%") gives "income 0\\%-33\\%", one backslash too much. What is the appropriate expression to get the desired output (one backslash before each %-sign)? I am using R 2.1.0 on suse linux 9.2. Thanks, Ruud