search for: depd50

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2002 Apr 26
0
[Fwd: Re: degrees of freedom for t-tests in lme]
...t;.0001 x 3.05784 0.0382305 3209 79.98440 <.0001 sex 0.01958 0.0057823 3209 3.38548 0.0007 depD27 0.01382 0.0593448 22 0.23293 0.8180 depD35 -0.06537 0.0550606 22 -1.18723 0.2478 depD50 -0.28581 0.0557979 22 -5.12220 <.0001 However, my real questions is: How DF = 3209 and 22 are calculated? I follow the book by Pinheiro and Bates (2000, p.91), Q = 1 mo=1 because I have intercept in model m1=26 groups m2=3237 observations p0=1 p1=3, (I have 4 levels of dep&...
2002 Apr 24
0
degrees of freedom for t-tests in lme
...3.05937 0.0367970 3206 83.14182 <.0001 log(den) 0.00898 0.0022357 3206 4.01732 0.0001 sex 0.01980 0.0057675 3206 3.43216 0.0006 depD27 -0.01505 0.0560142 3206 -0.26872 0.7882 depD35 -0.06102 0.0548647 3206 -1.11227 0.2661 depD50 -0.29123 0.0567132 24 -5.13511 <.0001 Are these coefficients are the level-2, and thus, DF for testing dep's should be (J-Q2_1=26-1-1=24). Why I get the number 3206, especially for depD27 depD35 and depD50. Thanks Han Han-Lin.Lai at noaa.gov -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-...