search for: decreasing

The chisq.test on line 57 contains following code: STATISTIC <- sum(sort((x - E)^2/E, decreasing = TRUE)) However, based on book "Accuracy and stability of numerical algorithms" available from: http://ftp.demec.ufpr.br/CFD/bibliografia/Higham_2002_Accuracy%20and%20Stability%20of%20Numerical%20Algorithms.pdf Table 4.1 on page 89, it is better to sort the data in increasing order tha...

There appears to be an issue with the decreasing=TRUE option on the order() function that indicates either a bug or perhaps a design flaw (potentially flawed because I would suggest the majority of users would expect different behaviour). # demonstration of problem: x <- c(2,1,3,4,5) order(x) order(x, decreasing=TRUE) order(x) correctly repo...

I recently reported order() to ignore decreasing=TRUE with na.last=NA. Now I discovered two other problems and send corrected code. Best regards Jens Oehlschlägel # PROBLEM 1 see PR#1906 # PROBLEM 2 > order(1, na.last=NA) Error in apply(sapply(z, is.na), 1, any) : dim(X) must have a positive length # clearly wrong as > order...

The NEWS file for R-devel (as of 2018-11-28 r75702) says ? order(...., decreasing=c(TRUE,FALSE)) could fail in some cases. Reported from StackOverflow via Karl Nordstr?m. However, either I don't understand the meaning of decreasing=c(TRUE,FALSE) or there are still problems. I thought order(x,y,decreasing=c(TRUE,FALSE) meant to return indices, i, such that x[i] was non-...

...for currently available ones. > removeGeneric("rbind") [1] TRUE > rbind function (..., deparse.level = 1) .Internal(rbind(deparse.level, ...)) <environment: namespace:base> > setGeneric("order", signature="...", + function (..., na.last=TRUE, decreasing=FALSE) + standardGeneric("order")) Creating a generic for "order" in package ".GlobalEnv" (the supplied definition differs from and overrides the implicit generic in package "base": Signatures differ: (...), (na.last, decreasing)) [1] "o...

...perhaps an OS issue? (I run R 2.0.1 on Win xp.) Thank you, b. #------------code test <- c("2005-02-08 18:49:15","2005-02-07 18:36:54", "2005-02-04 18:37:03","2005-02-06 18:29:04") test <- strptime(test,format="%Y-%m-%d %H:%M:%S") order(test,decreasing=F) #doesn't work - why? tst <- test + 0 order(tst,decreasing=F) #works - how come? print(tst) #------------run > test <- c("2005-02-08 18:49:15","2005-02-07 18:36:54", + "2005-02-04 18:37:03","2005-02-06 18:29:04") > test <- strptime(test,f...

Hello! Say I have a function foo1, which has argument ... to pass various arguments to foo2 i.e. foo1 <- function(x, ...) { foo2(x, ...) } Say that foo2 accepts argument arg1 and I would like to do the following: - if foo1 is called as foo1(x) then I would like to assign some value to arg1 inside foo1 before calling foo2 arg1 <- "some value" foo2(x, arg1=arg1) - if foo1 is

...te new to R so this question will sound quite fundamental. I need to create a vector of length 160. The first element should be (1+r)^159 and each element thereafter should decrease by a factor of (1+r) until the 160th element that should be 1. Is there a function similar to seq() but increasing or decreasing by factors? I need to do this in one step i.e, not using loops. Any help would be greatly appreciated. Regards, Andre [[alternative HTML version deleted]]

Hello I've a samba printing problem: while all cups handled printers work perfectly, a fax printer application recently stopped working because of the default 'max print jobs' of 1000. In reality, the spool directory is empty. My question is: where ist this 'max print jobs' stored and how should it decrease or be decreased automatically or manually? Is there a way for the

Hello all, I'm running very simple regression but face a problem of non-homogeneity of variance, but with a decreasing variance with increasing mean...I do not know how to deal with that. this relationship doesn't seem to be strong, but it's my first time to see something like that, and would like to know what to do if one day it becomes stronger. I tested just for fun some transformation but was not able t...

...d the data as a table using read.table, with header=TRUE (I excluded 2000 values), when calling the objects it appears to be there and I can see the values this is what I get when doing density.lf (x=logN0, n=50, window="gaussian") Error in `[.data.frame`(x, order(x, na.last = na.last, decreasing = decreasing)) : undefined columns selected then assigned a column name (using colname so it is called first), then assigned it as a vector using assign ("x", c (logN0)) the error I get is density.lf (x, n=50, window="gaussian") Error in sort.int(x, na.last = na.last,...

Full_Name: Doug Grove Version: R.1.9.1 OS: Linux Submission from: (NULL) (140.107.156.61) I just found that rank() has a 'decreasing' argument that is not documented in its help page. I checked my version of 2.0.0 (original release hence unpatched) and it is not documented there. For curiousity I also went back to version 1.8.1 and checked the function (not the documentation)and at that point rank() had not yet acquired th...

Hi all, I have a large data frame and would like to make a barplot of a categorical variable with the bars sorted in order of decreasing frequency. # Example: v1 = c(1.2, 1.4, 0.9, 1.0, 1.1, 1.0) v2 = c("aa", "cc", "bb", "bb", "cc", "bb") v3 = c(8, 10, 11, 9, 9, 10) df = data.frame(v1=v1, v2=v2, v3=v3) # How can I tell ggplot to sort the bars? # First bar = "bb"...

...so: the code above doesn't seem to do the right thing. Consider > the following example: > > > x <- c(1, 1, 2, 3) > > rank2(x, ties.method = "last") > [1] 1 2 4 3 > > That doesn't look right to me -- I had expected > > > rev(sort.list(x, decreasing = TRUE)) > [1] 2 1 3 4 > Indeed, well spotted, that seems to be correct. > > Henric Winell > ------------------------------ In the particular example (of length 4), what is really wanted is the following. ind <- integer(4) ind[sort.list(x, decreasing=TRUE)] <- 4:1 ind The...

Hi all, How can I decrease the number of ticks on the y-axis in a lattice levelplot()? I have as many ticks displayed on the y-axis as I have columns of data (1000 columns), how can I decrease this amount of ticks, while still properly displaying all the data? Note that I get my data from a matrix object, in which the z-values of the levelplot are the actual values in the matrix, whereas the

Hello list, When I convert an yuv pixel into rgb using the recipies in http://www.fourcc.org/fccyvrgb.php I get an accurate color conversion but the contrast seems to be decreased. If i write, e.g., the pixel directly into an sdl yuv_overlay, I get a well-contrasted frame, however, if I convert the pixel to rgb and call SDL_MapRGB, I get a contrast-decreased frame. Thanks, Ribamar

I've found the need to compute a version of order(x,y) where I want the sort order for *increasing* x and *decresing* y ... something we could imagine could be provided in the future as order(x,y, decreasing = c(FALSE, TRUE)) i.e., using a 'vectorized' decreasing argument. {No, I'm not volunteering right now!} I've found the following R-level solution and like to quiz you for more elegant / faster solutions {but I am not really interested in replacing order(x) by sort.list(x, me...

Hi All, I want to give ranks to elements in a column so I used: total_list$field1.rank <- rank(total_list$field1,ties.method="min") But this gives me the rank in increasing order. How do I get the ranks in decreasing order? I know decreasing = FALSE is not a legal argument here. Thanks. Jiong The email message (and any attachments) is for the sole use of the intended recipient(s) and may contain confidential information. Any unauthorized review, use, disclosure or distribution is prohibited. If you are not...

## While in R v. 2.3.1 (the mid-July patch for Windows) ## on a Windows XP machine, this call to order() works fine... order(1:10,decreasing = TRUE) ## [1] 10 9 8 7 6 5 4 3 2 1 ## ...however, the argument name 'decreasing' ## must be typed in toto (note the missing 'g' ## in the following): > order(1:10,decreasin = TRUE) ## Error in order(na.last, decreasing, ...) : ## argument lengths differ ## I...

Hi all, I have a frequency data that looks like this. 3 2 1 5 What I want to get is the "decreasing" cumulative of this data yielding 11 8 6 5 0 Is there any? I am aware of cumsum(), which will yield 3 5 6 11. But it is not what I want. - G.V.