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1999 Mar 09
2
summary() of lm() problem (PR#135)
...asch2) is truncated to just the first 10 rows. I made it so the modified dataset is called sasch2 so that I could cut and paste the exact same lm() call: > tmp<-sasch2[1:10,] > holdsasch2<-sasch2 > sasch2<-tmp > dump('sasch2','bugs.dump') > lm(sasch2[, "ddiff"] ~ sasch2[, "td30"] + sasch2[, "td60"] + sasch2[, "td90"] + sasch2[, + "td120"] + +sasch2[, "td180"] + sasch2[, "td240"] + sasch2[, "td300"] + sasch2[, "td360"] + + sasch2[, "td420"] + sasc...
1999 Mar 09
1
lm() using data frames
...planatory variables) and plenty of memory, specifically > gc() free total Ncells 886738 1000000 Vcells 7912909 8388608 I get a fatal error when attempting summary() on the fit of an lm() on a large-ish set of dummy variables (stored in a matrix): Call: lm(formula = sasch2[, "ddiff"] ~ sasch2[, "td30"] + sasch2[, "td60"] + sasch2[, "td90"] + sasch2[, "td120"] + +sasch2[, "td180"] + sasch2[, "td240"] + sasch2[, "td300"] + sasch2[, "td360"] + sasch2[, "td420"] + sasch2[,...
2006 Jan 22
23
calculate users age
i know it''s probably really simple, how do i work out someone''s age if i have their d.o.b. stored as a date in my db. cheers -- Posted via http://www.ruby-forum.com/.