Displaying 1 result from an estimated 1 matches for "dbabddadd".
2008 Aug 10
2
Basic data structures
...und the correct documentation. Here's a simple example which
illustrates several of my problems.
Suppose I want to have a regexp match against a string, and return all
the matching substrings in a vector of strings.
regexp <- "[ab]+"
strlist <- c( "abc", "dbabddadd", "aaa" )
matches <- gregexpr(regexp,strlist)
With this input, I'd want to return list( list("ab"), list("ab", "a"),
list("aaa") ).
Now the matches object prints out as
[[1]]
[1] 1
attr(,"match.length")
[1] 2...