search for: day1h

...9999 1.167 9999 9999 1.208 9999 9999 1.25 9999 9999.....and so on (the time column is in fractions of a day) I want to be able to group the data by day. I managed to do this using: Day1H = hourlydata[c(1:24),] but I'd like to be able to create groups for each day without doing this manually for each set of 24 rows. Any suggestions greatly appreciated Thanks -- View this message in context: http://n4.nabble.com/Grouping-rows-of-data-by-day-tp2016063p2016063.html Sent from...