search for: datum

Hello R users I recently learned how to use this command: lapply(datum,"[[","ColumnName") Unfortunately, I don't know how exactly it works, what it's called (in particular the "[[" part], and what other things you can do with it (retrieve multiple columns?). Given datum is a list of dataframes with the same column, but diffe...

...ve. site <- c("s1", "s1", "s1", "s2","s2", "s2") pref <- c(1, 2, 3, 1, 2, 3) R1 <- c(NA, NA, 1, NA,NA,NA) R2 <- c(NA, 0, 1, 1, NA, 1) R3 <- c(NA, 1, 1, NA, 1, 1) R4 <- c(0, NA, 0, 1, NA, 0) R5 <- c(NA, 0, 1, NA, 1, 1) datum <- data.frame(site, pref, R1, R2, R3, R4, R5) ## For 1 column; datum$R1[is.na(datum$R1)==T]<-5 tapply(datum$R1, datum$site, min, na.rm=T) ## Can loop this over all columns; new<-matrix(0,5,2) for (i in 3:7) {datum[,i][is.na(datum[,i])==T]<-5 new[i-2,]<-tapply(datum[,i], datum$site...

Anna Crepes: Traubenzucker + Feldsalat spezielles Dressing (bringt selbst mit?) -------- Weitergeleitete Nachricht -------- Betreff: Fwd: Fwd: Fwd: Fwd: Fwd: Fwd: Fwd: 26. Datum: Thu, 11 Dec 2014 15:34:39 +0100 Von: Markus <universe at truemetal.org> An: universe at truemetal.org Geschenke Moritz: dunkle Schokolade. Geschenke Anna: normale Schokolade. -------- Weitergeleitete Nachricht -------- Betreff: Fwd: Fwd: Fwd: Fwd: Fwd: Fwd: 26. Datum: Wed, 10 Dec 2014 05...

Hello, I have data like the following: datum <- structure(list(Y = c(415.5, 3847.83333325, 1942.833333325, 1215.22222233333, 950.142857325, 2399.5833335, 804.75, 579.5, 841.708333325, 494.053571425 ), X = c(1.081818182, 0.492727273, 0.756363636, 0.896363636, 1.518181818, 0.499166667, 1.354545455, 1.61, 1.706363636, 1.063636364 )), .Names...

Dear all I try to make hourly average by cut() function, which almost works as *I* expected. What puzled me is that if there is only one item at the end of your data it results in NA. Example will explain what I mean datum<-seq(ISOdate(2004,8,31), ISOdate(2004,9,1), "min") cut(datum[1370:1381],"hour", labels=F) [1] 1 1 1 1 1 1 1 1 1 1 1 NA cut(datum[1370:1382],"hour", labels=F) [1] 1 1 1 1 1 1 1 1 1 1 1 2 2 I do not understand why the last item in first call is NA. I f...

Hello list! I have a data.frame which looks like this: > serv datum op.read op.write read write 1 2011-01-29 10:00:00 0 0 0 0 2 2011-01-29 10:00:01 0 0 0 0 3 2011-01-29 10:00:02 0 0 0 0 4 2011-01-29 10:00:03 0 4 0 647168 5 2011-01-29 10:00:04 0 0...

Dear All, is there a simple way to print a data.frame without its row.names? example: datum <- as.Date(c("2004-01-01", "2004-01-06", "2004-04-12")) content <- c('Neujahr', 'Hl 3 K.', 'Ostern') df1 <- data.frame(datum, content) print(df1) datum content 1 2004-01-01 Neujahr 2 2004-01-06 Hl 3 K. 3 2004-04-12 Ostern Can...

...453), nrow=1) RM179 <- matrix(c(-81.890929, 33.317914), nrow=1) RM148 <- matrix(c(-81.7547337, 33.1514072), nrow=1) RM119 <- matrix(c(-81.501919, 32.94038), nrow=1) RM61 <- matrix(c(-81.262388, 32.524739), nrow=1) RM215.sp <- SpatialPoints(RM215, proj4string=CRS("+proj=longlat +datum=WGS84")) d060101 <- as.POSIXct("2006-01-01", tz="EST") study_seq <- seq(from=d060101, length.out=761, by="days") up.215 <- sunriset(RM215.sp, study_seq, direction="sunrise", POSIXct.out=TRUE) down.215 <- sunriset(RM215.sp, study_seq, directio...

...us results. An example. Let's take a point lying somewhere in Germany, zone=32U x <- 8.968735 y <- 49.454735 After conversion I sould get something like Easting: 426858 (km) Northing: 5427937 (km) sp1 <- SpatialPoints(matrix(c(x,y), ncol=2), proj4string = CRS("+proj=longlat +datum=WGS84")) sp1Transformed <- spTransform(sp1, CRS("+proj=merc +zone=32u +datum=WGS84")) coordinates(sp1Transformed) coords.x1 coords.x2 [1,] 998395.0133 6319888.068 The result is an obvious nonsense. Well, after some deliberation I swapped the original coordinate colum...

...though it is certain that one of them is called "pressure". (This is an oceanographic application, in case anyone wonders why pressure would be an independent variable for use in interpolation.) <code> #interpolate to target pressures in "pt". npt <- length(pt) for (datum.name in data.names) { if (datum.name != "pressure") { length(res$data[[datum.name]]) <- npt res$data[[datum.name]] <- approx(x$data[["pressure"]], x$data[[datum.name]], pt)$y } } </code> -- View this message in context: http://www.nabble.co...

Hello, again I'm on my weblog-script... having problems... This code: =========================== weblog <- read_weblog("web.log") weblog_by_date <- split(weblog, weblog$date) #for ( i in names(weblog_by_day) ) { print(i); print(weblog_by_day$i) } for ( datum in names(weblog_by_date) ) { print(datum) selected <- weblog_by_date[[datum]] res_size_by_host <- tapply( selected$size, selected$host, sum) mycat <- function(a,b) cat(paste(a, "==>", b, "\n")) mapply( mycat, selected$size, selected$host ) print( res_siz...

Readers, I have been reading the r book (Crawley) and tried to use the influence measures function for linear regression, as described. I have one datum that I wish to show in the graph but exclude from the regression and ab line. x y 0 5 10 9 20 10 30 19 40 4 With the influence measures function I plot the graph but linear regression includes the datum (40,4), which I want to show on the graph but exclude from the linear regression ab line. Is...

Readers, I have data with different time stamps that I wish to plot (for example): data set 1 time(hh:mm:ss),datum 01:00:00,500 01:00:15,600 01:00:30,750 01:00:45,720 01:01:00,700 01:01:15,725 01:01:30,640 01:01:45,710 data set 2 time,datum 01:00:12,20 01:01:01,55 01:01:55,22 The time interval in data set 1 does not change, but the time interval in data set 2 does change, such that for a specific total time ra...

Dear useRs, I'm struggling again with date-related stuff: I am using R to draw water levels at certain measuring stations. My data comes as a tab-delimited text file and looks like this: DATUM P1 P2 ... 2006-11-16 425.21 423.99 2006-12-15 425.12 423.97 2007-01-16 425.16 424.06 ... (measurements started in July 2004 and still continue on a monthly or bi-weekly basis) This is then plotted using this code: a<-read.table("dummy_data.tab", sep="\t",...

...lease ignore. Shame on me.. *blushing* LOL. Am 12.12.2014 um 21:19 schrieb Markus: > Anna Crepes: Traubenzucker > + Feldsalat spezielles Dressing (bringt selbst mit?) > > > > -------- Weitergeleitete Nachricht -------- > Betreff: Fwd: Fwd: Fwd: Fwd: Fwd: Fwd: Fwd: 26. > Datum: Thu, 11 Dec 2014 15:34:39 +0100 > Von: Markus <universe at truemetal.org> > An: universe at truemetal.org > > Geschenke Moritz: dunkle Schokolade. > Geschenke Anna: normale Schokolade. > > > > -------- Weitergeleitete Nachricht -------- > Betreff: Fwd: Fwd: Fwd:...

How to do the attachment in mail like the yahoo and gmail does? --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Ruby on Rails: Talk" group. To post to this group, send email to rubyonrails-talk-/JYPxA39Uh5TLH3MbocFFw@public.gmane.org To unsubscribe from this group, send email to

...eate barplot of abundances over time (in days). The period is over 171 days, so I don't want to have all labels there but only the first day of the month. I couldn't find anything like this on the forum yet. Mostrly it's about year to year data. This is the relevant part of my table: datum month abundance 26/03/11 March 1 27/03/11 March 0 28/03/11 March 1 29/03/11 March 0 30/03/11 March 0 31/03/11 March 0 1/04/11 April 0 2/04/11 April 0 3/04/11 April 0 ... 9/09/11 September 1 I tried making a sequence: hatch$axis.ticks2=seq(from=hatch$datum[1],to=hatch$datum[171], by=30) Bu...

...ctx.bld.CreateExtractValue(val, 0, "class"); auto cp = ctx.bld.CreateConstGEP2_32(ty, ptr, 0, 0); auto cx = ctx.bld.CreatePtrToInt(cp, ctx.Int32Type()); ctx.EmitCall1("debugInt", cx); ctx.bld.CreateStore(c, cp); // Set datum auto d = ctx.bld.CreateExtractValue(val, 1, "datum"); auto dp = ctx.bld.CreateConstGEP2_32(ty, ptr, 0, 1); auto dx = ctx.bld.CreatePtrToInt(dp, ctx.Int32Type()); ctx.EmitCall1("debugInt", dx); ctx.bld.CreateStore(d, dp)...

...in R already loaded 2 different line shapefiles with projection then i will see if i can replicate this problem. So, first file: buff class : SpatialLinesDataFrame features : 1 extent : 560525.5, 561302.4, 4698908, 4701110 (xmin, xmax, ymin, ymax) crs : +proj=utm +zone=16 +datum=WGS84 +units=m +no_defs variables : 2 names : ID, buff_dist value : 2, 135 second file: pln class : SpatialLinesDataFrame features : 1 extent : 560615.6, 560705.4, 4698905, 4699180 (xmin, xmax, ymin, ymax) crs : +proj=utm +zone=16 +datum=WGS84 +units=m...

...resulting data frame had 10 bad rows. The errors appear due to read.table missing delimiter characters, with multiple data being imported into the same cell, then the remainder of the row and the next run together and garbled due to the reading frame shift (example: a single cell might contain: <datum>~ ~ <datum> ~<datum>, after which all the cells of the row and the next are wrong). To replicate, I tried the same import procedure on a smaller demographics data set from the same supplier- only about 1Mb, and got the same kinds of errors (5 bad rows in about 3500). I also importe...