search for: datewise

Dear 'HTH' R friends I have a small dataframe as given below. I need to sort this database based on date in a decending order. I am not sure whether I have defined the date column in a proper format. mydat<-data.frame(date = (c("1/31/2010", "2/28/2010", "3/31/2010", "4/30/2010", "5/31/2010", "6/30/2010",

we have multiple servers approx 10 and each has about 100 GB of data in the /var/lib/mysql dir , excluding tar , mysqldump and replication how do we take backup for these databases on to a remote machine and store them datewise , ( the remote machine is a 2TB HDD ) currently tar is not feasible as the data is too huge and the same goes with mysqldump suggestion will be of great help -- Regards Agnello D'souza -------------- next part -------------- An HTML attachment was scrubbed... URL: <http://lists.cento...

...ere's a portion in one of my analyses in which I am wont to sort a data.frame so: seriesS <- seriesS[order(as.Date(row.names(seriesS),format="%m/%d/%Y")),] So, I've got row.names which are textual representations of dates, I'd like to retain them as such, but order them datewise. As long as seriesS has more than one column, this works nicely, seriesS afterwards is a data.frame with columns similar to those it had going in. But if I encounter a case with only one column, the result is _not_ a data frame, but instead an ? array? list? I can solve this with a kluge: ser...

We i have settup it like this it giveme caller id agent id and date-time on gsm file but i want them to be in folder on every day basis datewise. exten => _1NXXNXXXXXX,2,Set(CALLFILENAME=${ACCOUNTCODE}-${EXTEN}-${TIMESTAMP}) exten => _1NXXNXXXXXX,3,Monitor(gsm,/rec/asterisk/apr07/${CALLFILENAME},mb) Any Idea ? Faisal > ------------------------------ > > Message: 16 > Date: Tue, 10 Apr 2007 03:08:57 +0500 > Fro...

Dear sir, I am extremely sorry for messing up the logic asking for help w.r.t. my earlier mails   I have tried to explain below what I am looking for.     I have a database (say, currency_rates) storing datewise currency exchange rates with some base currency XYZ.   currency_rates <- data.frame(date = c("12/31/2010", "12/30/2010", "12/29/2010", "12/28/2010", "12/27/2010","12/24/2010", "12/23/2010", "12/22/2010", "12/2...

Dear Manoj, Have found out the mistake in my script. One must create directory if he/she wants to move old files to backup directory. In my script I was not creating any new backup-dir(datewise), therefore despite of have -b --backup-dir flags it was not working. This means rsync can only create automatically new direcotry for destination but not backup-dir !!!! Am I correct? Bipin --- Manoj Menon <manojcmenon@yahoo.com> wrote: > Hi Bipin, > > Perhaps this is tota...

...elia_vettori@yahoo.co.nz> napsal dne 07.01.2011 13:46:53: > Dear sir, I am extremely sorry for messing up the logic asking for help w.r.t. > my earlier mails > > I have tried to explain below what I am looking for. > > > I have a database (say, currency_rates) storing datewise currency exchange > rates with some base currency XYZ. > > currency_rates <- data.frame(date = c("12/31/2010", "12/30/2010", "12/29/ > 2010", "12/28/2010", "12/27/2010","12/24/2010", "12/23/2010", "12/22/...