search for: dateo

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2002 Jun 27
0
lattice and dates
...stead and coercing it to a number using as.integer():> as.integer(Sys.time())I dare say you could also set up a structure in which there are both numeric and string fields, do your modelling with the former and labelling with the latter:> now=Sys.time()> numero= as.integer(now)> dateo= format(now, "%a, %b %d, %Y")> timeo= format (now, "%X")> item=list(numeric=numero, strings=c(timeo,dateo))This seems to do the trick, and gives you a list with values that look like this.> item$numeric[1] 1025176725$strings[1] "12:18:45" "Thu,...
2013 Mar 17
6
Sweave y RStudio
...t; > las estaciones de recoleccion de muestras quedan en regiones no > > contaminadas tengo una gran cantidad de embryones no malformados. > > El problema es que al hacer los histogramas no me figuran los ceros. > > El codigo que estoy utilizando es el siguiente. > > hist(datEO[datEO$Ft.dameggs&datEO$YEAR=="1994",9],breaks=100,xlim=c(0,1)) > > Probe hacerlo con otro programa (PAST) en el cual si me figuran los > ceros. > > Alguien tiene alguna idea de como resolverlo? > > Adjunto una imagen de como se ve el hist en past. > > Saludo...
2002 Jun 27
1
lattice and dates (correcting e-mail formatting glitch - sorry!!)
...ead and coercing it to a number using as.integer(): > as.integer(Sys.time()) I dare say you could also set up a structure in which there are both numeric and string fields, do your modelling with the former and labelling with the latter: > now=Sys.time() > numero= as.integer(now) > dateo= format(now, "%a, %b %d, %Y") > timeo= format (now, "%X") > item=list(numeric=numero, strings=c(timeo,dateo)) This seems to do the trick, and gives you a list with values that look like this. > item $numeric [1] 1025176725 $strings [1] "12:18:45" "...