search for: dataa

Hi, ?In the example you provided, it looks like the dates in Date2 happens first.? So, I changed it a bit.? DataA<- read.table(text=" ID,Status,Date1,Date2 ??? ??? ?????? 1,A,3-Feb-01,15-May-01 ??? ??? 1,B,15-May-01,16-May-01 ??? ??? 1,A,16-May-01,3-Sep-01 ??? ??? ??? ??? ??? 1,B,3-Sep-01,13-Sep-01 ??? ??? ??? ??? ??? 1,C,13-Sep-01,26-Feb-04 ??? ??? ??? ??? ??? 2,A,9-Feb-01,24-May-01 ??? ??? 2,B...

Greetings everyone, I'm trying to add a specific table or a specific number of rows (e.g.44) to a table with no success. This is my basic table > head(dataA) year plot spp prop.B DCA1 DCA2 DCA3 DCA4 1 2000 1 a1 0.031079 -0.0776 -0.0009 0.0259 -0.0457 2 2000 1 a2 0.968921 -0.0448 0.1479 -0.1343 0.1670 3 2000 2 a1 0.029218 -0.0776 -0.0009 0.0259 -0.0457 4 2000 2 a4 0.021678 -0.305...

Hello all, I have a data frame dataa: newdate newstate newid newbalance newaccounts 1 31DEC2001 AR 1 1170 61 2 31DEC2001 VA 2 4565 54 3 31DEC2001 WA 3 2726 35 4 31DEC2001 AR 3 2700...

i am working with two sets of likert scale type (4 distinct values) data: dataA <- rep(1:4, c(3,2,2,4)) dataB <- rep(1:4, c(5,4,3,2)) i can now (bar)plot both of these separately and compare the distributions. plot(table(dataA), type='h') plot(table(dataB), type='h') is there a way to plot both of them in one plot, so that the bars for value "1&qu...

Hi, I got following error in write.table() : > write.table(dataa, file="c:/data1.csv", row.names=F, col.names=T, sep=",") Error in file(file, ifelse(append, "a", "w")) : cannot open the connection In addition: Warning message: In file(file, ifelse(append, "a", "w")) : cannot open file 'c:/data1...

...;,"17/01/2005","27/06/2006"),"%d/%m/%Y") dateB <- as.Date(c("22/11/2002","13/02/2005","18/08/2005","18/01/2006","21/08/2007","21/04/2009","17/05/2009","17/05/2009"),"%d/%m/%Y") dataA <- data.frame(id=c("A","B","C","B"),date=dateA, x=11:14,y=5:2) dataB <- data.frame(id=c("B","A","B","C","B","C","D","B"),date=dateB,m=27:20,n=22:29) #mystery function, s...

...a, wondering if there is a easy way to fit a glm without typing all the explanatory variable names. For example, if I have 100 explanatory variables x1, x2, ..., x100 and response variable is y, I don't want to do something like glm1 <- glm(y ~ x1 + x2 + ... + x100, family = gaussian, data = dataA) since it would be a lot of typing. Many thanks, -Jack [[alternative HTML version deleted]]

Hi, I want to plot this matrix (I attach the data), it is suposed that each column is a different time series. If I do g<-read.table("dataADF.txt", header=F) and plot(g[,1],type="l") it plots the first column plot if I want in a unique graph each colums of dataA, all in one. How should I proceed?There is a direct pre-defined code? And If I wanted a plot by each column? -------------- next part -------------- 0.2511...

...p_model.txt") n <- length(unique(subsetA$subject)) #number of subjects nt <- 13 #number of days Y <- subsetA$concentr #concentration per day/subject t <- 1:13 #days dataA <- list("n","nt","Y","t") parameters <- c("tau","C0","st90","C0.pop","st90.pop","tau.cpop","tau.stpop") inits <- list(tau=c(1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1),C0=5,st90=4...

I have two dataframes, the first column of each dataframe is a unique id number (the rest of the columns are data variables). I would like to figure out how many times each id number appears in each dataframe. So far I can use: length( match (dataframeA$unique.id[1], dataframeB$unique.id) ) but this only works on each row of dataframe A one-at-a-time. I would like to do this for all of

...r answers Stephen and Ben, I hope I am posting on the correct list now. I managed so far to run the multinomial model with random effect with the following command: MCMCglmm(fixed=cbind(Apsy,Mygl,Crle,Crru,Miag,empty) ~ habitat:trait,random=~idh(trait):mesh,family="multinomial12", data=dataA,rcov=~trait:units) (where multiple responses are different species, Habitat the explanatory variable and Mesh the random effect) The main question I am facing now is: Why the multinomial model fit does not provide by default a parameter estimate for each response category but a unique one for al...

Jim, Both the branch and the branch target are in the same function. This is known delta and should not matter where it is relocated because the delta will remain the same once it is a .o or later. I just want to know how to tell the compiler that this expression is target offset - branch offset. More generally, I want to know the rules for setting up expressions in general. I have no idea if

Hello! If I have a matrix as 1 2 2 3 and I want to change the value 2 in 0, what can I do? Thank you -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe" (in the "body", not the subject !)

...7:07 -0700 (PDT) From: tathta <caitlyn.paget@gmail.com> Subject: Re: [R] matching each row To: r-help@r-project.org Message-ID: <24395711.post@talk.nabble.com> Content-Type: text/plain; charset=us-ascii >From an email suggestion, here are two sample datasets, and my ideal output: dataA <- data.frame(unique.id=c("A","B","C","B"),x=11:14,y=5:2) dataB <- data.frame(unique.id=c("A","B","A","B","A","C","D","A"),x=27:20,y=22:29) ## mystery operation(s) happen h...