Displaying 1 result from an estimated 1 matches for "data_na".
Did you mean:
data_a
2005 Jul 04
1
compare two lists with differents levels
...product_release pr, product p where cat.ID=cc.category and cc.criteria=c.ID and c.ID=qc.criteria and qc.question=q.ID and fq.question=q.ID and fq.form=f.ID and f.ID=rf.form and rf.release=r.ID and r.ID=pr.release and pr.product=p.ID and r.ID='",param2,"';",sep=""))
data_NA<-matrix(data=0,nrow=length(release$Title),ncol=length(formv$TitleCrit),byrow=TRUE, dimnames=list(as.factor(release$Title),paste(as.factor(formv$TitleCrit),"(",formv$first_letter,")",sep="")))
for (i in 1:length(formv$TitleCrit))
{
for(k in 1: length(release1$Ti...