Displaying 1 result from an estimated 1 matches for "data_mc".
Did you mean:
data_ac
2010 Mar 08
1
compare tables
...n until row 27 and each row for all
columns. Then, when the first output table is finished I go on
comparing the first "creator" table with the second table in the
output, row for row for all columns. I do this for all iterations.
The first "creator" table is called "data_mc".
# apply similarity function (lettermatch) to my data
for (i in 1:(nrow(data_mc))){
for (y in 1:(ncol(data_mc))) {
creator_table <- data_mc[data_mc$Status=="mother",y]
output_tables <- ???
output[i,y]<-(lettermatch(creator_table, output_tables...