Displaying 20 results from an estimated 638 matches for "data2".
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2009 Nov 13
2
why the same values cannot be judged to be the same in R
...########
data1<-matrix(data=c(1,1.2,1.3,"3/23/2004",1,1.5,2.3,"3/22/2004",2,0.2,3.3,"4/23/2004",3,1.5,1.3,"5/22/2004"),nrow=4,ncol=4,byrow=TRUE)
data1<-data.frame(data1);names(data1)<-c("areaid","x","y","date")
data2<-matrix(data=c(1,1.22,1.32,1, 1.53, 2.34,1, 1.21, 1.37,1, 1.52,
2.35,2, 0.21, 3.33,2, 0.23, 3.35,3, 1.57, 1.31,3, 1.59,
1.33),nrow=8,ncol=3,byrow=TRUE)
data2<-data.frame(data2);names(data2)<-c("areaid","x1","y1")
data2$tag<-0
data1_1<-data1[1,...
2023 Jun 11
1
Problem with filling dataframe's column
Dear Rui;
Many thanks for your email. I used one of your codes,
"data2$LU[which(data2$Layer == "Level 12")] <- "Park"", and it works
correctly for me.
Actually I need to expand the codes so as to consider all "Levels" in the
"Layer" column. There are more than hundred levels in the Layer column.
If I use your provided co...
2023 Jun 11
1
Problem with filling dataframe's column
?s 22:54 de 11/06/2023, javad bayat escreveu:
> Dear Rui;
> Many thanks for your email. I used one of your codes,
> "data2$LU[which(data2$Layer == "Level 12")] <- "Park"", and it works
> correctly for me.
> Actually I need to expand the codes so as to consider all "Levels" in the
> "Layer" column. There are more than hundred levels in the Layer column.
> If I...
2023 Jun 11
1
Problem with filling dataframe's column
...g to fill a column based on a specific value in another column of
> a dataframe, but it seems there is a problem with the codes!
> The "Layer" and the "LU" are two different columns of the dataframe.
> How can I fix this?
> Sincerely
>
>
> for (i in 1:nrow(data2$Layer)){
> if (data2$Layer == "Level 12") {
> data2$LU == "Park"
> }
> }
>
>
>
>
Hello,
There are two bugs in your code,
1) the index i is not used in the loop
2) the assignment operator is `<-`...
2008 Nov 05
2
how can I save the estimates of a regression model in a file?
Dear all
I need some help with R.
How can I save the estimates of a regression model in a file?
here is what I did:
1) this is my regression model:
fit1 <- lm(logmilk ~ logdays + days, data=data2)
2) however, I want to get the parameters estimates for each individual (by
group):
so i did the following:
by(data2, list(data2$V2),function(.data2) lm(logmilk ~ logdays + days, data=
.data2))
3) Then to keep the estimates in a file I did:
res1 <- by(data2, list(data2$V2),function(.data2) lm(...
2011 Nov 16
3
plotting a double y axis when x and y lengths differ
Hello All,
Many thanks to the help I have received so far.
Here is an example data set I hope to plot
Data1
Year Data SE
1 2005 2 0.01
2 2006 4 0.01
3 2007 5 0.01
4 2008 2 0.01
5 2009 3 0.01
6 2010 6 0.01
Data2
Year Data SE
1 2006 32 1
2 2007 100 2
3 2008 60 4
4 2009 67 3
5 2010 8 1
Notice Data2 has one less years worth of data than Data1 (which is my
problem)
I am fond of using plotCI as it makes creating error bars and offsetting
overlapping error bars so easy, and double y-axis plot...
2011 Jul 16
1
Fwd: construct boxplots from data with varying column widths
...gt;>>
>>> function1,12.5
>>> function1,13.11
>>> function1,35.2
>>> ...
>
>> That is definitely to be preferred. Read that into R and show us the
>> results of str on your R data object.
>
> Thanks for your suggestion.
>
>> str(data2)
> 'data.frame': 1940170 obs. of 2 variables:
> $ function.: Factor w/ 127 levels "fn_activities01_list",..: 102
> 102 102 102 102 102 102 102 102 102 ...
> $ runtime : num 38.1 32.4 41.2 92.9 130.5 ..
>
>> head(data2)
> function...
2004 Feb 04
5
Date Time Conversion problems...
...ot;Way, Shawn",1/2/2003,AP15043,1/2/2003,1/9/2003,JS ,1000
"Vo, Hoang",1/7/2003,SO17440,1/8/2003,12/31/2003,USFi-,3705
"Harrold, Paul",1/10/2003,AP15122,1/13/2003,1/14/2003,FishM,65.06
Old Code:
library(lattice)
data <- read.csv("h:\\list3.csv",header=TRUE)
data2 <-
data.frame(Name=data$UserName,Date=data$RequestDate,Vendor=data$Vendor,Cost=
data$Total)
data2$Date <- strptime(as.character(data2$Date),format="%m/%d/%Y")
start <- strptime(c("1/01/2003"),format="%m/%d/%Y")
end <- strptime(c("12/31/2003"),form...
2009 Nov 27
2
If condition using accessors
...me with one problem I've been struggling with
for the last hours!!
(Sorry if I'm using the wrong terminology as well!)
I have a data matrix in which SIE is one of my variables. What I need to
do now is to create a new variable (group) if a certain condition in SIE
is met.
I tried:
if (data2$SIE < 50.646){
data2$group=as.factor("small")
}
which gives me "In if (data2$SIE < 50.646) { : the condition has length
> 1 and only the first element will be used"
and
ifelse (data2$SIE < 50.64593, data2$group =
as.factor("small"),data2$group = as.fac...
2008 Aug 21
1
problem merging two data sets ( one with a header and one without)
I have two set of data, Data1 and Data2 . Data1 has a header and Data2 does
not. I would like to merge the two data sets after removing some columns
from data2 .
I am having a problem merging so I had to write and read final data and
specify the ?header=F? so the merge can be done by?V1?. Is there a way to
avoid this step. The problem...
2014 Nov 10
2
range () does not remove NA's with complete.cases() for dates (dplyr/mutate)
...<NA> <NA> 2007-10-10
5 5 2006-09-01 2005-08-10 <NA> <NA> 2006-09-01
6 6 2007-09-04 2011-10-05 <NA> <NA> 2011-10-05
7 7 2005-10-25 <NA> <NA> 2011-11-04 2011-11-04
>
> # range of dates
>
> range(data2$mrjdate[complete.cases(data2$mrjdate)])
[1] "2004-11-04" "2009-10-24"
> range(data2$cocdate[complete.cases(data2$cocdate)])
[1] "2005-08-10" "2011-10-05"
> range(data2$inhdate[complete.cases(data2$inhdate)])
[1] "2005-07-07" "2011-10-13&q...
2023 Jun 11
2
Problem with filling dataframe's column
Dear R users;
I am trying to fill a column based on a specific value in another column of
a dataframe, but it seems there is a problem with the codes!
The "Layer" and the "LU" are two different columns of the dataframe.
How can I fix this?
Sincerely
for (i in 1:nrow(data2$Layer)){
if (data2$Layer == "Level 12") {
data2$LU == "Park"
}
}
--
Best Regards
Javad Bayat
M.Sc. Environment Engineering
Alternative Mail: bayat194 at yahoo.com
[[alternative HTML version deleted]]
2009 Nov 12
2
redundant factor levels after subsetting a dataset
...me with a numeric and a character variable.
x=c(1,2,3,2,0,2,-1,-2,-4)
md=c(rep("Miller",3), rep("Richard",3),rep("Smith",3))
data1=data.frame(x,md)
#I subset this data.frame in a way such that one level of the character
variable does not appear in the new dataset.
data2=data1[x>0,]
data3=subset(data1,x>0)
#However, when I check the levels of the factor variable in the subset data
frame, it still shows the levels that are now unused.
unique(data2$md)
unique(data3$md)
#This leads to complications in table and tapply that I want to avoid.
table(data2$md)
t...
2009 Nov 06
1
probem on merge data
...t;5/22/2004"),nrow=4,ncol=4,byrow=TRUE)
data1<-data.frame(data1)
names(data1)<-c("areaid","x","y","date")
data1
areaid x y date
1 1 1.2 1.3 3/23/2004
2 1 1.5 2.3 3/22/2004
3 2 0.2 3.3 4/23/2004
4 3 1.5 1.3 5/22/2004
data2<-matrix(data=c(1,1.22,1.32,1, 1.53, 2.34,1, 1.21, 1.37,1, 1.52,
2.35,2, 0.21, 3.33,2, 0.23, 3.35,3, 1.57, 1.31,3, 1.59,
1.33),nrow=8,ncol=3,byrow=TRUE)
data2<-data.frame(data2)
names(data2)<-c("areaid","x1","y1")
data2
areaid x1 y1
1 1 1....
2010 Sep 06
1
combining collumns for data.frames
Hi
This question is far less simple than the title suggests, please read carefully, thanks.
I have 2 sets of data, both read into R
>data1<-read.table ("1.txt", header=T, sep="\t")
>data2<-read.table ("2.txt", header=T, sep="\t")
>data1
Taxon stage1 stage2 stage3 stage4
T1 0 0 1 1
T2 0 1 1 0
T3 0 0 0 1
T4 1 0 0...
2013 Jun 10
4
Combining CSV data
Hello R community,
I am trying to combine two CSV files that look like this:
File A
Row_ID_CR, Data1, Data2, Data3
1, aa, bb, cc
2, dd, ee, ff
File B
Row_ID_N, Src_Row_ID, DataN1
1a, 1, This is comment 1
2a, 1, This is comment 2
3a, 2,...
2010 May 28
1
Match 2 vectors
Hi,
I have 2 dataframes of unequal length, and I would like to match a
factor to them so that both dataframes will have the same number of
rows.
example:
# create the 2 dataframes with unequal length
data1 <- data.frame(letters, 1:26)[-c(5,10,19:21),]
data2 <- data.frame(letters, 1:26)[-c(6,9,15:18),]
data2a <- match(data1[,1], data2[,1])
data2b <- data2[data2a,]
When I match data1 to data2, and combine the data2a vector to the
original data2, I'm still missing some rows. I need to get the 26
rows, and preferably with the first column...
2009 Nov 09
0
how to stop a loop in a sampling
...lows.###
data1<-matrix(data=c(1,1.2,1.3,"3/23/2004",1,1.5,2.3,"3/22/2004",2,0.2,3.3,"4/23/2004",3,1.5,1.3,"5/22/2004"),nrow=4,ncol=4,byrow=TRUE)
data1<-data.frame(data1);names(data1)<-c("areaid","x","y","date")
data2<-matrix(data=c(1,1.22,1.32,1, 1.53, 2.34,1, 1.21, 1.37,1, 1.52,
2.35,2, 0.21, 3.33,2, 0.23, 3.35,3, 1.57, 1.31,3, 1.59,
1.33),nrow=8,ncol=3,byrow=TRUE)
data2<-data.frame(data2);names(data2)<-c("areaid","x1","y1")
id<-unique(data1$areaid)
for (n i...
2008 May 14
4
Accessing items in a list of lists
Using R 2.6.2, say I have the following list of lists, "comb":
data1 <- list(a = 1, b = 2, c = 3)
data2 <- list(a = 4, b = 5, c = 6)
data3 <- list(a = 3, b = 6, c = 9)
comb <- list(data1 = data1, data2 = data2, data3 = data3)
So that all names for the lowest level list are common. How can I most
efficiently access all of the sublist items "a" indexed by the outer
list names? For...
2010 Jan 05
3
R matching lat/lon pairs from two datasets?
...aset and use that rows data for calculations. I am using
match, but this is finding the first match and not comparing the pair,
how can I determine if the lat/lon are the same? See example below. Is
there a better way to determine to a matching pair of lat/lon values?
Example Datasets:
> data2
V1 V2 V3
1 -123.76 47.82 8
2 -123.75 47.82 11
> data[1:2]
V1 V2
1 47.82 -123.76
2 47.82 -123.75
3 47.82 -123.74
4 47.82 -123.73
#Subset of current R code :
lat <- data$V1
lon <- data$V2
yrs <- c(1,2,5,10,25,50,100,200,500,1000)
lon2 <- data2$V1
lat2 <-...