search for: dat5

Hello, I looked in the R-help but could not find an archive addressing the following. I would like to convert a character to numeric after reading a file with RDS extension. After using as.numeric, I checked if it is numeric. It was not converted. Please help. Here is my code >Report <- readRDS(file="RDS/Report.RDS") > Report[1:2,] dive_id date

Hi all Say I have a function: myname=function(dat,x=5,y=6){ res<<-x+y-dat } for various input such as myname(dat1) myname(dat2) myname(dat3) myname(dat4) myname(dat5) how should I modify the 'res' line, to have new informative variable name correspondingly, such as dat1.res dat2.res dat3.res dat4.res dat5.res stored in the workspace. This is only an example of a complex function I have written. Thanks in advance! Casper -- View this message in...

Hi, I have a panel data set that I am trying to subset. I am trying to keep values for years >=1960. The full set is from 1940 to 2000. I tried a few things, but none worked. Here are a couple that I am trying to use. TableAPS1 <- subset(TableAP, year => 1959) TableAPS1 <- TableAP[ which(year > 1959),] It would be really nice if someone can point out what I am doing wrong

Hi, I hope that folks can give me some simple approaches to taking the data set below, which is accumulated in two columns called "long" and "group", then arrange the data is the "long" column into a data frame containing five variables: "Group 1", "Group 2", "Group 3", "Group 4", and "Group 5". I am hoping for a few

...table('input1.txt')* ** ** *dat1 <- dat[ dat[,1]=8 & dat[,2]=9 & dat[,3]=2 ,]=1* *dat2<-dat[(dat[,2]= 8 & dat[,3]=9 & dat[,4]=2),]=1* *dat3<-dat[(dat[,5]=8 & dat[,4]=9 & dat[,5]=2),]=1* *dat4<-dat[(dat[,4]=8 & dat[,5]=9 & dat[,6]=2),]=1* *dat5<-dat[(dat[,5]=8 & dat[,6]=9 & dat[,7]=2),]=1* *dat6<-dat[(dat[,6]=8 & dat[,7]=9 & dat[,8]=2),6]=1* *dat7<-dat[(dat[,7]=8 & dat[,8]=9 & dat[,9]=2),7]=1* *dat8<-dat[(dat[,8]=8 & dat[,9]=9 & dat[,10]=2),8]=1* ** datfinal<-dat1+da2+dat3+dat4+da...

Hi, R-help, I have a group of data from RNA-seq want to be analyzed by Fisher's exact test in R. I want to compare the significant difference of about 30,0000 individuals in two different samples, and I have no idea how to use R, so could you please give me some suggestions or the scripts for Fisher's exact test? Thank you very much. Best, Guanfeng Wang [[alternative HTML version

Hello, I have two different files which I'd like to combine to make one data frame but I've no idea how to do it! The first file has two columns; one is the date, the following is a binary code for debris flow events. Then my other file has also two columns; the date and then precipitation data. The thing is, is that the two date columns don't all contain the same dates. The binary

...one). The model loops over the path of each animal, estimating a hidden movement state and their parameters. For 4 individuals with 100 data points each the data looks something like this: dat1 : num 100 dat2 : int 4 dat3 : num [1:4] 8 4 2 5 dat4 : num [1:100, 1:4] 1 1 1 1 1 2 2 2 2 2 ... dat5 : num [1:100, 1:4] 2 2 2 2 2 1 2 2 2 2 ... dat6 : num [1:100, 1:4] 16 34.3 33.5 27.9 14.9 ... dat7 : num [1:100, 1:4] 0.357 0.474 0.487 0.495 0.524 ... dat8 : num [1:50, 1:4] 36.4 294.5 24.4 21.1 422.8 ... This is how I've called WinBugs in r: # write data to text file sp.data =...

Dear useRs, i have vectors of about 27 descriptors, each having 703 elements. what i want to do is the following 1. i want to do regression analysis of these 27 vectors individually, against a dependent vector, say B, having same number of elements.2. i would like to know best 10 regression results, if i do regression analysis of dependent vector against the random combination of any 4

Hi, I have a pretty simple problem. Here is the code: dat1=complete(dat.mice,1) dat2=complete(dat.mice,2) dat3=complete(dat.mice,3) dat4=complete(dat.mice,4) dat5=complete(dat.mice,5) dat6=complete(dat.mice,6) dat7=complete(dat.mice,7) dat8=complete(dat.mice,8) dat9=complete(dat.mice,9) dat10=complete(dat.mice,10) dat11=complete(dat.mice,11) dat12=complete(dat.mice,12) dat13=complete(dat.mice,13) dat14=complete(dat.mice,14) dat15=complete(dat.mice,...

...- sum(apply(x[,6:32],2,function(y) y[1]>=y[2]));x2<- sum(apply(x[,6:32],2, function(y) y[1]<=y[2])); if(x1>x2) x[1,] else x[2,] } ),unique(dat2$gene)) #assuming that there are not more than 2 copies of a particular gene. (In the dataset, it was not present) ?dat4<-rbind(dat1New,dat3) dat5<-dat4[order(as.numeric(row.names(dat4))),] ?dim(dat5) #[1] 639? 32 A.K. ________________________________ From: Vivek Das <vd4mmind at gmail.com> To: arun <smartpink111 at yahoo.com> Sent: Monday, September 9, 2013 2:30 PM Subject: Re: Duplicated genes actually these are all di...

Hi all. I'm trying to see how the package Rodbc works, with R 1.2.2, win98 and MySql 3.23. I'd like to export a dataset with 524 variables and 3440 records form R to MySql. I issued the following commands: library(RODBC) channel <- odbcConnect("test") sqlSave(channel,dat=totale) Error in sqlTables(channel)[, 3] : incorrect number of dimensions Actually it gave me other

Hello. Please forgive me if this problem has already been posted (and solved) by someone else ... I can't find it anywhere though it seems so very basic. Here it is: I have a list comprised of several matrices, each of which has two columns. > list [[1]] [,1] [,2] [1,] 1 3 [2,] 2 4 [[2]] [,1] [,2] [1,] 5 7 [2,] 6 8 [[3]] [,1] [,2]

Hi guys, I have 1000 rows of a dataset. In my analysis, I need 70% of the data, run my analysis and then use the remaining 30% to test my model. Could anybody kindly help me on this? Cheers

Hi, Could you please advice some easy way to do the following for a dataframe (header=F) having unequal column- & row- length. 1. Combine/stack/join contents from - a) multiple rows into one column. b) multiple columns into one row. 2. Stack contents from multiple columns (or, rows) into one column (or, row). Thank you. Cheers, Santana [[alternative HTML

Hi. This is likely a trivial problem but have not found a solution. Imagine the following dataframe: Lat Lon x1 x2 x3 01 10 NA NA .1 01 11 NA .2 .3 01 12 .4 .5 .6 I want to generate another column that consist of the first value in each row from columns x1 to x3. That is NewColumn .1 .2 .4 Any input greatly appreciated, Thanks, Camilo Camilo Mora, Ph.D.

Hi friends, I need to generate a list, that should contain the quantile value of one column in a data frame. while I am compiling this one i am facing one bug,, Really I cannot find out that where the problem has occurred? Could any one help me to come out from this bug?? Here is the code, data <- lapply(comb.data$zFE, function(x) aggregate(x,

Folks, I have a data frame with columns 200401, 200402, ..., 201207, 201208. These represent years/months. What would be the best way to sum these columns by year? What about by quarter? Thanks for your time, KW -- [[alternative HTML version deleted]]

Dear useRs, I have a slightly complicated data structure and am stuck trying to extract what I need. I'm pasting an example of this data below. In some cases, there are duplicates in the "gene_id" column because there are two different "sample 1" values for a given "sample 2" value. Where these duplicates exist, I need to average the corresponding

...y other variables concurrently. I'm using the "psych" package and have tried other methods such as writing a loop to extract semi-partial correlations, but it does not seem to be working. How can I accomplish this? library(psych) > set.cor(y = (66:76), x = c(1:64), z = 65, data = dat5) Error in solve.default(x.matrix, xy.matrix) : Lapack routine dgesv: system is exactly singular: U[54,54] = 0 structure(list(cope8_StriatumMask_7_betas_mean = c(11.47, -0.6002, -11.59, -52.51, 36.63, -36.99, -26.89, 21.68, 3.776, 19.35, -56.44, -11.41, -1.825, 5.327, -2.886, 11.91, 43.99, 42.17,...