Displaying 9 results from an estimated 9 matches for "dat2new".
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dat1new
2013 May 11
3
boxplot with grouped variables
my dataset looked like this in the beginning:
>Daten
V1 V2 V3
1 Dosis Gewicht Geschlecht
2 0 6.62 m
3 0 6.65 m
4 0 5.78 m
5 0 5.63 m
I need box plots for V2 with all combination of V1 and V3, so I deleted the
first row, and tried this:
boxplot(Daten$V2[Daten$V3=="m"])
but it does not work and I
2013 Mar 27
9
conditional Dataframe filling
Hi everyone:
This may be trivial but I just have not been able to figure it out.
Imagine the following dataframe:
a b c d
TRUE TRUE TRUE TRUE
FALSE FALSE FALSE TRUE
FALSE TRUE FALSE FALSE
I would like to create a new dataframe, in which TRUE gets 0 but if
false then add 1 to the cell to the left. So the results for the
example above should be something like:
a b c
2013 Sep 27
0
Best and Worst values
...("arun.RData")
Pred1<- get(obj_name[1])
Actual1<- get(obj_name[2])
dat2<- data.frame(S1=rep(Pred1[,1],ncol(Pred1)-1),variable=rep(colnames(Pred1)[-1],each=nrow(Pred1)),Predict=unlist(Pred1[,-1],use.names=FALSE),Actual=unlist(Actual1[,-1],use.names=FALSE),stringsAsFactors=FALSE)
dat2New<- dat2[!(is.na(dat2$Predict)|is.na(dat2$Actual)),]
?dat3<- dat2New[order(dat2New$S1,dat2New$Predict),]
library(plyr)
resLow<-ddply(dat3,.(S1),summarize, cbind(head(Predict,5),head(Actual,5)))
resHigh<-ddply(dat3,.(S1),summarize, cbind(head(rev(Predict),5),head(rev(Actual),5)))
?resLow...
2013 May 22
0
calcul of the mean in a period of time
...???????????? 2.5
2????????????????????? 4????????????????? 2.6
2?????????????????????? 5???????????????? 1.5
3?????????????????????? 0???????????????? 1.2
4?????????????????????? 0???????????????? 1.3
4?????????????????????? 1???????????????? 1.8
",sep="",header=TRUE)
library(plyr)
?dat2New<-ddply(dat2,.(patient_id),summarize,t=seq(min(t),max(t)))
?res<-join(dat2New,dat2,type="full")
?lst1<-lapply(split(res,res$patient_id),function(x) {x1<-x[x$t!=0,];do.call(rbind,lapply(split(x1,((x1$t-1)%/%3)+1),function(y) {y1<-if(any(y$t==1)) rbind(x[x$t==0,],y) else y; d...
2013 May 09
0
Replace rows in dataframe based on values in other columns
...?????????? 15 Hazel 4/11/2010
??????????? 15 Hazel 4/11/2010
??????????? 15 Hazel 4/11/2010
??????????? 15 Hazel 4/11/2010
??????????? 17 Pete 9/2/2012
??????????? 17 Pete 9/2/2012
??????????? 17 Pete 9/2/2012
??????????? 17 Pete 9/2/2012
",sep="",header=TRUE,stringsAsFactors=FALSE)
dat2New<-unsplit(lapply(split(dat2,dat2$Restaurant), FUN= function(x) {x1<-x[order(as.Date(x$purchase_date,format="%m/%d/%Y")),]; x1$Current_Owner<- tail(x1$owner,1); x1}),dat2$Restaurant)
?
?rownames(dat2New)<- 1:nrow(dat2New)
?dat2New
#?? Restaurant owner purchase_date Current_Owner...
2013 Jun 15
2
Plotting two y-axis vs non-numeric x-axis
Hi dear all, the following code is correct. but I want to use non-numeric
x-axis, for example
if I replace time <- seq(0,72,6) by
month <-
c("Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec","Pag")
Ofcourse I use factor(month) instead of
2013 Aug 22
1
converting a summary table to survey database form
Hi!
I am looking to choose a condom based on its pleasure score.
I received some summarised data from 10 individuals:
structure(list(Ramses = c(4, 4, 5, 5, 6, 3, 4, 4, 3, 4), Sheiks = c(5,
5, 6, 4, 7, 6, 4, 5, 6, 3), Trojans = c(7, 8, 7, 9, 6, 3, 2,
2, 2, 3), Unnamed = c(2, 1, 1, 3, 3, 4, 5, 4, 4, 3)), .Names = c("Ramses",
"Sheiks", "Trojans", "Unnamed"),
2013 Sep 25
1
Best and worst values for each date
Hi,
May be you can try this:
obj_name<- load("arun.RData")
Pred1<- get(obj_name[1])
Actual1<- get(obj_name[2])
library(reshape2)
dat<-cbind(melt(Pred1,id.vars="S1"),value2=melt(Actual1,id.vars="S1")[,3])? # to reshape to long form
colnames(dat)[3:4]<- c("Predict","Actual")
dat$variable<- as.character(dat$variable) #not that
2013 May 07
4
how to calculate the mean in a period of time?
...????????????? 2.2
1????????????????????? 3???????????????? 1.8
2????????????????????? 0????????????????? 2.3
2?????????????????????? 2???????????????? 2.5
2????????????????????? 4????????????????? 2.6
2?????????????????????? 5???????????????? 1.5
",sep="",header=TRUE)
library(plyr)
?dat2New<-ddply(dat2,.(patient_id),summarize,t=seq(min(t),max(t)))
?res<-join(dat2New,dat2,type="full")
res1<-do.call(rbind,lapply(split(res,res$patient_id),function(x) {x1<-x[x$t!=0,];do.call(rbind,lapply(split(x1,((x1$t-1)%/%3)+1),function(y) {y1<-if(any(y$t==1)) rbind(x[x$t==0,],...