Displaying 1 result from an estimated 1 matches for "dados2005".
2012 Aug 06
2
Splitting Data Into Different Series
...2005,2005,2005,3939,3939,3939,3939,3939,3939),
nrow=18, ncol=3, byrow=FALSE,
dimnames=list(c(1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18),
c("date", "value", "code")))
dados433 <- matrix(data = NA, nrow = 6, ncol = 3, byrow= FALSE)
dados2005 <- matrix(data = NA, nrow = 6, ncol = 3, byrow= FALSE)
dados3939 <- matrix(data = NA, nrow = 6, ncol = 3, byrow= FALSE)
for(i in seq(along=dados[,3])) {
if(dados[i,3] == 433) {dados433[i,1:3] <- dados[i,1:3]}
}
for(i in seq(along=dados[,3])) {
if(dados[i,3] == 2005) {dados2005[i,...