Displaying 3 results from an estimated 3 matches for "curveexpert".
2010 Aug 23
1
Fitting Weibull Model with Levenberg-Marquardt regression method
Hi,
I have a problem fitting the following Weibull Model to a set of data.
The model is this one: a-b*exp(-c*x^d)
If I fitted the model with CurveExpert I can find a very nice set of coefficients which create a curve very close to my data, but when I use the nls.lm function in R I can't obtain the same result.
My data are these:
X Y
15 13
50 13
75 9
90 4
With the commercial software I obtain the following coefficients:
Weibull...
2011 Aug 31
3
Fitting my data to a Weibull model
...ell into a Weibull model y = a-b*exp(-c*x^d).
I want to estimate the parameters of the coefficients a, b, c and d, given x
and y.
Can you guys help me?
Just as an example, I fit the data
y <- c(1,2,3,4,10,20)
and
x <- c(1,7,14,25,29,30)
According to this model above, and using the software CurveExpert, and I got
the estimates of a (2.95),b (2.90),c (2.82e-2) and d (2.97).
This is just a sample data but I would like to do it on R because I can loop
multiple times through all my files.
I would also like to fit a logistic model y = a/(1+b*exp-c*x)
Can you help me????
Thanks
--
View this messa...
2010 Aug 24
0
mlm for within subject design
...nfield.ac.uk
To: r-help at r-project.org
Date: Mon, 23 Aug 2010 16:01:59 +0100
Subject: [R] Fitting Weibull Model with Levenberg-Marquardt regression method
Hi,
I have a problem fitting the following Weibull Model to a set of data.
The model is this one: a-b*exp(-c*x^d)
If I fitted the model with CurveExpert I can find a very nice set of coefficients which create a curve very close to my data, but when I use the nls.lm function in R I can't obtain the same result.
My data are these:
X Y
15 13
50 13
75 9
90 4
With the commercial software I obtain the following coefficients:
Weibull...