Displaying 20 results from an estimated 72 matches for "curvatur".
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curvature
2003 Jun 02
1
Help - Curvature measures of nonlinearity
...n of growth parameter estimates between sexes of the same species, or estimates from different populations.
The realibility statistical tests normally applied are highly dependent on the nonlinearity of the model used.
Are there any developed routines in R ? to:
1) calculate the maximum intrinsic curvature
2) maximum parameter affecting curvature
3) plot the two dimensional cross sections of confidence regions (for different alpha values) of the model parameters
Regards,
Ivone Figueiredo
[[alternate HTML version deleted]]
2010 Mar 05
0
R algorithm for maximum curvatures measures of nonlinear models
Hi all,
I'm looking for the algorithm to calculate maximum intrinsic and parameter effects curvature of Bates & Watts (1980). I have Bates & Watts (1980) original article, Bates et al (1983) article, Seber & Wild (1989) and Ratkowsky (1983) books. Those sources show steps and algorithm to get this measures but I don't know translate C code to R language and I've no success unt...
2008 Feb 16
1
Evaluate function on a grid
...ter product of two
arrays, like this:
sx <- c(seq(-3, x0, len = 100), seq(x0, 3, len = 100)[-1])
sy <- c(seq(-3, y0, len = 100), seq(y0, 3, len = 100)[-1])
fout <- outer( sx, sy, f)
persp(fout)
This works pretty well, but I would like to achieve better results by using
information o the curvature of
the function.
I know that the curvature of the function is very high in a neighborhood of
(x0, y0), but it
is rather flat for (x,y) not belonging to this neighborhood.
So in principle I have to choices: increase the number of points were the
function is evaluated; evaluate the function more de...
2002 May 29
0
classification by nls and anova
...lation and saturation
Is there a way to model these classes, and compare their significance by
means of an
analysis of the residuals (ANOVA)?
Something like
model 1 = linear & constant =~ 0 & slope = 0
model 2 = linear & constant =~ 1 & slope = 0
model 3 = ???? some curvature
model 4 = ???? some curvature
model 5 = linear & slope > 0
model 6 = full four parameter logistic model
with the procedure:
Starting with the linear model and testing for any curvature.
-> curvature not significant
==> result = model 1, 2 or 3, depending on signifi...
2005 May 27
1
Testing Nonlinear Restrictions
Dear all,
I'm interested in testing 2 nonlinear restrictions on coefficients of a nls object. Is there a package for doing this? Something in the lines of `test(nls object, res=c("res 1","res 2"),...)'
I only found the function delta.method in the alr3 library that calculates the se of a singleton nonlinear restriction of a nls object using the delta method.
Thanks in
2011 Jun 07
2
gam() (in mgcv) with multiple interactions
...e two-way (and one three-way) interactions that I know are of interest (I know this from previous logistic regression modelling of the dataset).
For those who like to see the actual R code, here are two fits I've tried:
gam(outcome ~ te(acl, dispersal) + te(amplitude, dispersal) + te(slope, curvature, amplitude), family=binomial, data=rla, method="REML")
gam(outcome ~ te(slope) + te(curvature) + te(amplitude) + te(acl) + te(dispersal) + te(slope, curvature) + te(slope, amplitude) + te(curvature, amplitude) + te(acl, dispersal) + te(amplitude, dispersal) + te(slope, curvature, amplit...
2007 Oct 17
0
curly bracket in plot (reply)
...function(x1,y1,x2,y2,h)
{
x2 <- x2-x1; y2 <- y2-y1
v1 <- viewport(x=x1,y=y1,width=sqrt(x2^2+y2^2),
height=h,angle=180*atan2(y2,x2)/pi,
just=c("left","bottom"),gp=gpar(col="red"))
pushViewport(v1)
grid.curve(x2=0,y2=0,x1=.125,y1=.5,curvature=.5)
grid.move.to(.125,.5)
grid.line.to(.375,.5)
grid.curve(x1=.375,y1=.5,x2=.5,y2=1,curvature=.5)
grid.curve(x2=1,y2=0,x1=.875,y1=.5,curvature=-.5)
grid.move.to(.875,.5)
grid.line.to(.625,.5)
grid.curve(x2=.625,y2=.5,x1=.5,y1=1,curvature=.5)
popViewport()}
grid.newpage()
grid.move.to(.25,.3)
grid...
2007 Mar 27
1
"Groups" in XYPLOT
...to the table, result is high prob of exceed is in
row with low slope
#and low probabibility is in row with high slope
freqs$rank<-z
write.table(freqs, "C:/R_PLots/coastslopefreqs.txt", sep=",",
col.names=TRUE, row.names=TRUE, quote=TRUE, na="NA")
##########coastal_curvature
#needs the maptools package to read ESRI grid
require(maptools)
#import the curvature grid
basin.map <- readAsciiGrid("C:/R_PLots/coastal_crv.asc", colname="curv")
basin_curv <- (basin.map$curv)
#read the curvs into a dataframe
freqs<-as.data.frame(table(basin_curv))
#...
2004 Jun 28
3
How to determine the number of dominant eigenvalues in PCA
...le covariance matrix.
Assume x-axis is the number of eigenvalues (1, 2, ....,n), and y-axis is the
corresponding eigenvalues (a1,a2,..., an) arranged in desceding order.
So this x-y plot will be a decreasing curve. Someone mentioned using the elbow (knee) method
to find the point that the maximal curvature of this curve occurs.
The number at this point would be the number of dominant eigenvalues.
But I could not find any reference papers on this idea.
Does anyone has tried this method or knows more details on this?
Thanks for your point.
Fred
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2005 Mar 30
6
French Curve
Dear R experts,
Did someone implemented French Curve yet? Or can anyone point me some
papers that I can follow to implement it?
thanks in advance for your help.
Paul
2005 Sep 14
4
Converting coordinates to actual distances
Hello,
I've been searching for a method of converting Lat/Lon decimal
coordinates into actual distances between points, and taking into
account the curvature of the earth. Is there such a package in R? I've
looked at the GeoR package, but this does not seem to contain what I am
looking for. Ideally the output would be a triangular matrix of
distances.
Thanks in advance,
Paul Brewin
Paul E Brewin (PhD)
Center for Research in Biological Sys...
2024 Mar 22
1
geom_edge & color
Hi,
this seems to work (assuming that your problem was the setting of
colours...):
--- snip ---
network %>%
ggraph(., layout = "auto") +
# This produces an error...
# geom_edge_arc(curvature=0.3, aes(width=(E(network)$weight/10),
color=c("darkblue", "red")[as.factor(edge_list$relationship)], alpha=0.5))
+
# ... this works :-)
geom_edge_arc(curvature=0.3, aes(width=E(network)$weight/10,
color=edge_list$relationship), alpha=.5) +
scale_edge_color_manual(...
2005 Jul 10
1
O/T -2 Log Lambda and Chi Square
Hi R People:
Sorry about the off topic question. Does anyone know the reference
for "-2 Log Lambda is approx dist. Chi square", please?
It may be Bartlett, but I'm not sure....
thanks in advance!
Sincerely,
Laura Holt
mailto: holtlaura at gmail.com
2009 Jan 16
1
Lattice: how to have multiple wireframe nice intersection?
Hello,
This code builds a simple example of 2 wireframes :
require(lattice)
x <- c(1:10)
y <- c(1:10)
g <- expand.grid(x = 1:10, y = 1:10, gr = 1:2)
g$z <- c(as.vector(outer(x,y,"*")), rep(50,100))
wireframe(z ~ x * y, data = g, groups = gr, scales = list(arrows =
FALSE))
However, the intersection between the wireframes is not properly
drawn. Is there a way to fix this
2012 Jul 11
2
Modifying the design matrix X in GAMS to suit data assimilation
...t was a great resource.
My observations are spatiotemporal salinity in the San Francisco Bay at a number of instruments over a few days. The thing that I want to fit is the initial condition for a salt transport model at the beginning of this time period. The spline basis functions, parameters and curvature penalties would all be purely spatial, though the cross-validation would be in the space of the data.
The modification I need to make is as follows:
1. evaluate each spatial basis function at every computational point in my mesh (dense, but not part of the GAM)
2. use the bases members as individ...
2010 Apr 02
4
Derivative of a smooth function
Dear All,
I've been?searching for?appropriate codes to compute the rate of change and the curvature?of ?nonparametric regression model whish was denoted by a smooth function?but?unfortunately?don't manage to?do?it. I presume that such characteristics from a smooth curve can be determined by the first and second derivative operators.
The following are the example of fitting a nonparametric r...
2005 Aug 18
0
[SPAM] - Re: How to assess significance of random effect in lme4 - Bayesian Filter detected spam
...he best literature available at the moment:
>
> 1. Doug Bates in his PhD dissertation and later in his book
> with Don Watts (1988) Nonlinear Regression Analysis and Its
> Applications (Wiley) split approximation errors in nonlinear least
> squares into "intrinsic curvature" and "parameter effects curvature".
> He quantified these two problems in the context of roughly three dozen
> published examples, if my memory is correct, and found that in not
> quite all cases, the parameter effects were at least an order of
> magnitude greater th...
2024 Mar 22
1
geom_edge & color
...dge.color = ifelse(edge_list$relationship == "pos", "blue", "red"),
layout=layout_with_mds(.))
tiff("figures/Test_network_bysubcatecory.tiff", width=1000, height=900, res=120)
network %>%
ggraph(., layout = "auto")+
geom_edge_arc(curvature=0.3, aes(width=(E(network)$weight/10), color=c("darkblue", "red")[as.factor(edge_list$relationship)], alpha=0.5)) +
geom_node_point(aes(size = V(network)$hub_score*200, color= as.factor(V(network)$community))) +
geom_node_text(aes(label = V(network)$name), size=3, color...
2024 Mar 20
1
geom_edge & color
...defined in the edge_list$relationship: negative relationship
= red and positive relationship = darkblue. The code is working in the way
that the groups are separated by two colors. However, the code uses not the
assigned colors. Does anyone have any idea how to adapt the code?
--> geom_edge_arc(curvature=0.3, aes(width=(E(network)$weight/10),
color=c("darkblue", "red")[as.factor(edge_list$relationship)], alpha=0.5)) +
Kind regards
Sibylle
Working example
library(circlize)
library(ggplot2)
library(igraph)
library(tidyverse)
library(RColorBrewer)
library(stringi)
library(sc...
2003 Dec 22
2
error propagation - hope it is correct subject
Dear all
Please, can you advice me how to compute an error, standard deviation or
another measure of variability of computed value.
I would like to do something like:
var(y) = some.function(var(x1),var(x2),var(x3))
for level F1 (2,3,...)
Let say I have some variables - x1, x2, x3 (two computed for levels of factor F
and one which is same for all levels) and I want to compute
y =