search for: curv

> I did some local testing and it seems that you are using a curve that is not acceptable for openssl as a server key. > > I tested with openssl s_server -cert ec-cert.pem -key ec-key.pem -port 5555 > > using cert generated with brainpool. Everything works if I use prime256v1 or secp521r1. This is a limitation in OpenSSL and not something we can reall...

...8iPNsGMCuwYQjykDeDVngTmO8 > YT3tjFh3RrwNEDewPesByTHxhU6E+s98in9cq8rqAGSH8547Cq2KC/BOywJAGNHd > SF0PuAzqghQ7JKXqufjxKEyMMEu4H9HlH/h4lwX9hUO5EVDlCNqkcHHu9TCXBCmR > xT/8nuAtTycVigK88A== > -----END CERTIFICATE----- > > > I did some local testing and it seems that you are using a curve that is not acceptable for openssl as a server key. I tested with openssl s_server -cert ec-cert.pem -key ec-key.pem -port 5555 using cert generated with brainpool. Everything works if I use prime256v1 or secp521r1. This is a limitation in OpenSSL and not something we can really do anything abou...

...</a>> wrote: </div> <div> <br> </div> <div> <br> </div> <div> <br> </div> <blockquote type="cite"> <div> I did some local testing and it seems that you are using a curve that is not acceptable for openssl as a server key. </div> </blockquote> <blockquote type="cite"> <div> I tested with openssl s_server -cert ec-cert.pem -key ec-key.pem -port 5555 </div> </blockquote> <blockquote type=&q...

I am attempting to wrap the histogram function in my own custom function, so that I can quickly generate some standard plots. A part of what I want to do is to draw a normal curve over the histogram: > x <- rnorm(1000) > hist(x, freq=F) > curve(dnorm(x), lty=3, add=T) (for normal use, x would be a vector of empirical values, but the rnorm() function works for testing) That works just as you'd expect, but I've found something a bit strange. If I t...

Dear useRs, my question could be very basic for which i apologize in advance. Each column of a matrix with dimensions 365 rows and 37 columns was drawn against another matrix of dimensions 365 rows and 1 column. with that i was able to draw 37 curves on the same axis. now i want to draw an average curve of these 37 curves on the same axis in such a way that all the curves (average and 37 curves) should appear on the same axis at the same time. i used >par(new=TRUE) But it has 2 limitations 1- it completly distorted y-axis values 2- it...

hmm HFSC ? where can i find more informations and examples about the *linux* HFSC ? http://trash.net/~kaber/hfsc/ does not help here -- _______________________________________________ LARTC mailing list / LARTC@mailman.ds9a.nl http://mailman.ds9a.nl/mailman/listinfo/lartc HOWTO: http://lartc.org/

Hi all How can I change the limits (xlim or ylim) in a plot that has been already created? For example, consider this naive example curve(dbeta(x,2,4)) curve(dbeta(x,8,13),add=T,col=2) When adding the second curve, it goes off the original limits computed by R for the first graph, which are roughly, c(0,2.1) I know two obvious solutions for this, which are: 1) passing a sufficiently large parameter e.g. ylim=c(0,4) to the first gr...

Dear Sirs, I am a new user of the R package. When I try to use the curve function it confuses me. > curve(x^2) Works fine. > curve(x) Makes a complaint I don't understand. Why is x^2 valid and x is not? I check the documentation of curve, and it says the first argument must be an expression containing x. > expression(x) Is an expression containing x....

Hi All, I'm trying to figure out the cumulative incidence curve in R in some limited time. I found in package "cmprsk", the command "plot.cuminc" can get this curve. But I noticed that there is no mark for the censored time there, comparing with the KM curve by "plot.survfit". Here are my codes (attached is the data): --------...

HI I'm a student in chemical engineering, and i have to implement an algoritm about FIVE PARAMETERS INTERPOLATION for a calibration curve (dose, optical density) y = a + (c - a) /(1+ e[-b(x-m]) where x = ln(analyte dose + 1) y = the optical absorbance data a = the curves top asymptote b = the slope of the curve c = the curves bottom asymptote m = the curve X intercept Have you never seen this formula, because i don't fine inf...

First a statistical issue: The survfit routine will produce predicted survival curves for any requested combination of the covariates in the original model. This is not the same thing as an "adjusted" survival curve. Confusion on this is prevalent, however. True adjustment requires a population average over the confounding factors and is closely related to the sta...

Hi, Down a cascade of function calls, I want to use the curve function with an expression that is a variable. For various reason, this variable must be a character object and cannot be an expression as required by the curve function. How do I convert my variable into a expression that is accepted by curve? Thanks in advance for your help. ## The following...

Hi all, I want to provide the result from D() to curve(), because I want to plot the k-th derivative of some functions. Actually, I copy from console the result given by D() and paste inside curve(). With a lot of functions and high degree differentiation this process is tedious. Can I provide directly?? # what I actually have done (very simple funct...

Though I have read quite a bit, and tried quite a bit, I have yet to find a nice way to overlay 2 or more curves in the same plot, with different ranges. Here is simplified sample code to demonstrate the question: > plot(2*(seq(1,5)), type="l", axes=FALSE) > curve(2*(seq(1,5)), type="b", add=TRUE) Error in curve(2 * (seq(1, 5)), type = "b", add = TRUE) : 'expr&...

Hi Folks, I'd be grateful for good suggestions about the following. I'm plotting a family of (X,Y) curves (for different levels of another variable, Z): say 6 curves in all but could be more or less -- it's a rather variables situation. I'd like to label each curve with the value of Z that it corresponds to. The problem is that the layout (shapes, spacings, ranges of X over which non-NA val...

If I have, say, five scatter points and want to connect them together into a smooth curve. I did plot(x,y,type="l"), but the graph is five segments connecting with each other, but not a smooth curve. I wonder if there is a line type that is a curve. Thanks! -- View this message in context: http://r.789695.n4.nabble.com/connecting-points-into-a-smooth-curve-tp3021796p30217...

I am Julia Cains from Brisbane. This is my first mail to this group and I have recently started learning the R language.   I am trying to learn the smoothening of the yield curve. However, I came across the CRAN package – “YieldCurve” meant for Modelling and estimation of the yield curve. The problem is I am not able to understand whether this package will help me to carry out smoothening of the curve.   The related pdf file consists of following R code.     YieldCurv...

...he sake of example). Gender Age M 70 F 65 M 70 Each row represents a person with an age/gender combination. We could put this data into a data frame. Now, I would like to do some actuarial analysis on this data set. To do so, I need to create and store a mortality curve for each person in the table (a mortality curve is a matrix with 2 columns: date and survival probability). I can write a function that returns a mortality curve given gender and age. The question is the following: In what data format should I store all these mortality curve objects? Should I add...

Hi List, I would like to plot multiple curves (parametric density curves) in one plot. For example: # parameters for three normal density curves parms = data.frame(ID=c(1,2,3),mu=c(50,55,60),sigma=c(10,12,15)) # I can easily draw three normal density curves using curve(): curve(dnorm(x,mean=parms$mu[1],sd=parms$sigma[1]),from=0, to=150,...

Dear all, I would like to plot under the same plot many curves like mycdf<-ecdf(runif(100)) plot(mycdf) curve(mycdf,from=-1,to=1) mycdf<-ecdf(runif(200)+3) plot(mycdf) curve(mycdf,from=-1,to=1) as you can see each new call to curve redraws (erases) the window. How I can have an effect like plot(mycdf) lines(mycdf2) lines(mycdf3) I would like to th...